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A car is moving with a speed v on a straight road can be stop with in distance de on applying bricks if same car is moving with speed 3V and brakes provide half retardation then car will stop after travelling distance (1) 6d (2) 3d (3) 9d (4) 18d?
Most Upvoted Answer
A car is moving with a speed v on a straight road can be stop with in ...
Solution:
Given,
- Speed of car = v
- Distance required to stop car = de
To find,
- Distance required to stop car when speed is 3v and brakes provide half retardation
Stopping distance formula:
The distance required to stop a moving object is given by,
d = (v^2)/(2a)
where,
- d = stopping distance
- v = initial velocity
- a = retardation/acceleration
Stopping distance for initial speed v:
Using stopping distance formula, we can calculate the stopping distance for initial speed v as,
de = (v^2)/(2a)
or,
a = (v^2)/(2de)
Stopping distance for speed 3v:
Given,
- Speed of car = 3v
- Retardation = 1/2 a
Using stopping distance formula, we can calculate the stopping distance for initial speed 3v as,
d = ((3v)^2)/(2*(1/2a))
or,
d = (9v^2)/a
Substituting the value of a from the equation for stopping distance for initial speed v,
d = (9v^2)/((v^2)/(2de))
or,
d = 18de
Therefore, the distance required to stop the car when speed is 3v and brakes provide half retardation is 18 times the distance required to stop the car when speed is v.
Hence, the correct answer is option (4) 18d.
Given,
- Speed of car = v
- Distance required to stop car = de
To find,
- Distance required to stop car when speed is 3v and brakes provide half retardation
Stopping distance formula:
The distance required to stop a moving object is given by,
d = (v^2)/(2a)
where,
- d = stopping distance
- v = initial velocity
- a = retardation/acceleration
Stopping distance for initial speed v:
Using stopping distance formula, we can calculate the stopping distance for initial speed v as,
de = (v^2)/(2a)
or,
a = (v^2)/(2de)
Stopping distance for speed 3v:
Given,
- Speed of car = 3v
- Retardation = 1/2 a
Using stopping distance formula, we can calculate the stopping distance for initial speed 3v as,
d = ((3v)^2)/(2*(1/2a))
or,
d = (9v^2)/a
Substituting the value of a from the equation for stopping distance for initial speed v,
d = (9v^2)/((v^2)/(2de))
or,
d = 18de
Therefore, the distance required to stop the car when speed is 3v and brakes provide half retardation is 18 times the distance required to stop the car when speed is v.
Hence, the correct answer is option (4) 18d.
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A car is moving with a speed v on a straight road can be stop with in distance de on applying bricks if same car is moving with speed 3V and brakes provide half retardation then car will stop after travelling distance (1) 6d (2) 3d (3) 9d (4) 18d?
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A car is moving with a speed v on a straight road can be stop with in distance de on applying bricks if same car is moving with speed 3V and brakes provide half retardation then car will stop after travelling distance (1) 6d (2) 3d (3) 9d (4) 18d? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A car is moving with a speed v on a straight road can be stop with in distance de on applying bricks if same car is moving with speed 3V and brakes provide half retardation then car will stop after travelling distance (1) 6d (2) 3d (3) 9d (4) 18d? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car is moving with a speed v on a straight road can be stop with in distance de on applying bricks if same car is moving with speed 3V and brakes provide half retardation then car will stop after travelling distance (1) 6d (2) 3d (3) 9d (4) 18d?.
A car is moving with a speed v on a straight road can be stop with in distance de on applying bricks if same car is moving with speed 3V and brakes provide half retardation then car will stop after travelling distance (1) 6d (2) 3d (3) 9d (4) 18d? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A car is moving with a speed v on a straight road can be stop with in distance de on applying bricks if same car is moving with speed 3V and brakes provide half retardation then car will stop after travelling distance (1) 6d (2) 3d (3) 9d (4) 18d? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car is moving with a speed v on a straight road can be stop with in distance de on applying bricks if same car is moving with speed 3V and brakes provide half retardation then car will stop after travelling distance (1) 6d (2) 3d (3) 9d (4) 18d?.
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