Labelled Diagram:

Here is a labelled diagram showing three resistors connected in such a way that the resultant resistance is 5 ohms:

```
______ 2Ω ______
| |
| |
---- ----
| R1 |
| 2Ω |
---- ----
| |
| |
---- ----
| R2 |
| 4Ω |
---- ----
| |
| |
---- ----
| R3 |
| 12Ω |
---- ----
| |
| |
----------------------
Resultant
Resistance
5Ω
```

Explanation:

To achieve a resultant resistance of 5 ohms using three resistors, we need to connect them in a specific configuration. Let's analyze how this can be done.

Series and Parallel Connections:

Resistors can be connected in two ways: series and parallel. In a series connection, the resistors are connected end to end, while in a parallel connection, the resistors are connected side by side.

Series Connection:
- In a series connection, the total resistance is the sum of individual resistances.
- When resistors are connected in series, the current flowing through each resistor is the same.
- The voltage across the resistors in series gets divided based on their individual resistances.

Parallel Connection:
- In a parallel connection, the reciprocal of the total resistance is the sum of the reciprocals of individual resistances.
- When resistors are connected in parallel, the voltage across each resistor is the same.
- The current flowing through the resistors in parallel gets divided based on their individual resistances.

Combining Resistors:

To achieve a resultant resistance of 5 ohms, we can combine the given resistors in the following way:

1. Combine the 2 ohm and 4 ohm resistors in series:
- The total resistance in series connection is the sum of individual resistances.
- Therefore, the combined resistance of the 2 ohm and 4 ohm resistors in series is 2 ohms + 4 ohms = 6 ohms.

2. Combine the 6 ohm resistor (result of step 1) and the 12 ohm resistor in parallel:
- The reciprocal of the total resistance in parallel connection is the sum of the reciprocals of individual resistances.
- Therefore, the combined resistance of the 6 ohm and 12 ohm resistors in parallel is 1/6 ohm + 1/12 ohm = 3/12 ohm + 2/12 ohm = 5/12 ohm.
- To find the equivalent resistance, take the reciprocal of the sum of the reciprocals: 1 / (5/12) ohm = 12/5 ohm = 2.4 ohms.

3. Combine the 2.4 ohm resistor (result of step 2) with an additional resistor in series to achieve a total resistance of 5 ohms:
- Let's denote the unknown resistor as Rx.
- The sum of the 2.4 oh

Put 4ohm and 12ohm resister in parallel with 2ohm resister in series ........hope u will get it answer here diagram representation doesn't possible...