Molarity of the Solution Obtained by Mixing HCl Solutions

To determine the molarity of a solution obtained by mixing 800 ml of 0.5 M HCl with 200 ml of 1 M HCl, we need to calculate the final concentration of the resulting solution.

Step 1: Convert Volume to Liters
First, we need to convert the volumes of the HCl solutions from milliliters to liters.

800 ml = 800/1000 = 0.8 L
200 ml = 200/1000 = 0.2 L

Step 2: Calculate the Moles of HCl
Next, we calculate the moles of HCl in each solution using the given molarity and volume.

Moles of HCl in 0.5 M HCl solution = 0.5 mol/L x 0.8 L = 0.4 mol
Moles of HCl in 1 M HCl solution = 1 mol/L x 0.2 L = 0.2 mol

Step 3: Determine the Total Moles of HCl
Now, we add the moles of HCl from both solutions to find the total moles of HCl in the resulting solution.

Total moles of HCl = 0.4 mol + 0.2 mol = 0.6 mol

Step 4: Calculate the Total Volume of the Solution
To find the total volume of the resulting solution, we add the volumes of the initial solutions.

Total volume of the solution = 0.8 L + 0.2 L = 1 L

Step 5: Calculate the Final Molarity
Finally, we can calculate the molarity of the resulting solution by dividing the total moles of HCl by the total volume of the solution.

Molarity = Total moles of HCl / Total volume of the solution
Molarity = 0.6 mol / 1 L = 0.6 M

Therefore, the molarity of the solution obtained by mixing 800 ml of 0.5 M HCl with 200 ml of 1 M HCl is 0.6 M.