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A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire is
  • a)
    2.4 N
  • b)
    1.2 N
  • c)
    3.0 N
  • d)
    2.0 N
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A straight wire of length 0.5 meter and carrying a current of 1.2 ampe...
Given:
Length of wire (l) = 0.5 meter
Current (I) = 1.2 ampere
Magnetic field (B) = 2 tesla

To find:
Force on the wire

Formula:
The force experienced by a current-carrying wire in a magnetic field is given by the formula:

F = BIL sinθ

Where,
F = Force on the wire
B = Magnetic field
I = Current
L = Length of wire
θ = Angle between the magnetic field and the wire

Calculation:
In this case, the magnetic field is perpendicular to the length of the wire, which means the angle (θ) between them is 90 degrees.

Using the given values in the formula:

F = BIL sinθ
F = (2 tesla) * (1.2 ampere) * (0.5 meter) * sin(90 degrees)

Since sin(90 degrees) = 1, the equation simplifies to:

F = (2 tesla) * (1.2 ampere) * (0.5 meter) * 1
F = 1.2 N

Answer:
The force on the wire is 1.2 Newtons. Therefore, option B is the correct answer.
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A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer?
Question Description
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