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A body A moves with a uniform acceleration a and zero initial velocity. Another body B, starts from the same point moves in the same direction with a constant velocity ν. The two bodies meet after a time t. The value of t is
  • a)
    2ν/a
  • b)
    ν/a
  • c)
    ν/2a
  • d)
    √ν/2a
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A body A moves with a uniform acceleration a and zero initial velocity...
If body A moves with a uniform acceleration a and zero initial velocity, its velocity v at any time t can be calculated using the equation:

v = at

where a is the uniform acceleration and t is the time elapsed.

On the other hand, if body B starts from the same point and moves in the same direction with a constant velocity, its velocity v at any time t can be calculated using the equation:

v = u

where u is the constant velocity of body B.

So, while body A's velocity changes with time due to the uniform acceleration, body B's velocity remains constant throughout.

In summary, body A's velocity increases with time due to the uniform acceleration, while body B's velocity remains constant.
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A body A moves with a uniform acceleration a and zero initial velocity. Another body B, starts from the same point moves in the same direction with a constant velocity ν. The two bodies meet after a time t. The value of t isa)2ν/ab)ν/ac)ν/2ad)√ν/2aCorrect answer is option 'A'. Can you explain this answer?
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