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A body with mass 5kg is acted upon by a force F vector = (-3i 4j)N. If its initial velocity at t = 0 is u vector = (6i-12j) m/s , the time at which it will just have a velocity along y-axis is (a) never (b) 10 seconds (c) 2 seconds (d) 1 second?
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A body with mass 5kg is acted upon by a force F vector = (-3i 4j)N. If...
Given data:
- Mass of the body: 5 kg
- Force vector: F = (-3i + 4j) N
- Initial velocity at t = 0: u = (6i - 12j) m/s
Key formula:
The net force acting on a body is given by Newton's second law of motion:
F = m * a
Step 1: Calculate the acceleration
Using Newton's second law of motion, we can find the acceleration of the body.
F = m * a
(-3i + 4j) = 5 * a
So, a = (-3/5)i + (4/5)j
Step 2: Find the time when the body has velocity along the y-axis
To find the time at which the body will have a velocity along the y-axis, we need to determine when the x-component of the velocity becomes zero. Since the force is acting only in the x-direction and there is no external force acting in the y-direction, the y-component of the velocity will remain constant.
Step 3: Calculate the time
The x-component of the velocity can be calculated using the equation of motion:
v = u + at
0 = 6 + (-3/5)t
Solving the equation, we get:
t = 10 seconds
Step 4: Determine the answer
The time at which the body will have a velocity along the y-axis is 10 seconds.
Answer:
The correct option is (b) 10 seconds. At t = 10 seconds, the body will have a velocity along the y-axis.
- Mass of the body: 5 kg
- Force vector: F = (-3i + 4j) N
- Initial velocity at t = 0: u = (6i - 12j) m/s
Key formula:
The net force acting on a body is given by Newton's second law of motion:
F = m * a
Step 1: Calculate the acceleration
Using Newton's second law of motion, we can find the acceleration of the body.
F = m * a
(-3i + 4j) = 5 * a
So, a = (-3/5)i + (4/5)j
Step 2: Find the time when the body has velocity along the y-axis
To find the time at which the body will have a velocity along the y-axis, we need to determine when the x-component of the velocity becomes zero. Since the force is acting only in the x-direction and there is no external force acting in the y-direction, the y-component of the velocity will remain constant.
Step 3: Calculate the time
The x-component of the velocity can be calculated using the equation of motion:
v = u + at
0 = 6 + (-3/5)t
Solving the equation, we get:
t = 10 seconds
Step 4: Determine the answer
The time at which the body will have a velocity along the y-axis is 10 seconds.
Answer:
The correct option is (b) 10 seconds. At t = 10 seconds, the body will have a velocity along the y-axis.
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A body with mass 5kg is acted upon by a force F vector = (-3i 4j)N. If its initial velocity at t = 0 is u vector = (6i-12j) m/s , the time at which it will just have a velocity along y-axis is (a) never (b) 10 seconds (c) 2 seconds (d) 1 second?
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A body with mass 5kg is acted upon by a force F vector = (-3i 4j)N. If its initial velocity at t = 0 is u vector = (6i-12j) m/s , the time at which it will just have a velocity along y-axis is (a) never (b) 10 seconds (c) 2 seconds (d) 1 second? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body with mass 5kg is acted upon by a force F vector = (-3i 4j)N. If its initial velocity at t = 0 is u vector = (6i-12j) m/s , the time at which it will just have a velocity along y-axis is (a) never (b) 10 seconds (c) 2 seconds (d) 1 second? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body with mass 5kg is acted upon by a force F vector = (-3i 4j)N. If its initial velocity at t = 0 is u vector = (6i-12j) m/s , the time at which it will just have a velocity along y-axis is (a) never (b) 10 seconds (c) 2 seconds (d) 1 second?.
A body with mass 5kg is acted upon by a force F vector = (-3i 4j)N. If its initial velocity at t = 0 is u vector = (6i-12j) m/s , the time at which it will just have a velocity along y-axis is (a) never (b) 10 seconds (c) 2 seconds (d) 1 second? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body with mass 5kg is acted upon by a force F vector = (-3i 4j)N. If its initial velocity at t = 0 is u vector = (6i-12j) m/s , the time at which it will just have a velocity along y-axis is (a) never (b) 10 seconds (c) 2 seconds (d) 1 second? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body with mass 5kg is acted upon by a force F vector = (-3i 4j)N. If its initial velocity at t = 0 is u vector = (6i-12j) m/s , the time at which it will just have a velocity along y-axis is (a) never (b) 10 seconds (c) 2 seconds (d) 1 second?.
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