A closely wound solenoid 80cm.long had 5 layers of winding of 400 turn...
To calculate the magnetic field inside the solenoid, we can use Ampere's law. Ampere's law states that the magnetic field inside a solenoid is directly proportional to the current flowing through it and the number of turns per unit length.
Given data:
Length of the solenoid, L = 80 cm = 0.8 m
Number of layers, n = 5
Number of turns per layer, N = 400
Diameter of the solenoid, d = 1.8 cm = 0.018 m
Current carried, I = 8 A
1. Calculating the total number of turns:
Total number of turns, N_total = Number of turns per layer * Number of layers = N * n = 400 * 5 = 2000
2. Calculating the length of the solenoid:
The length of the solenoid is given as 80 cm, but we need to convert it to meters:
L = 0.8 m
3. Calculating the radius of the solenoid:
The diameter is given as 1.8 cm, so the radius can be calculated as:
r = d/2 = 0.018 m/2 = 0.009 m
4. Calculating the number of turns per unit length:
Number of turns per unit length, n' = Total number of turns / Length of the solenoid = N_total / L = 2000 / 0.8 = 2500 turns/m
5. Calculating the magnetic field inside the solenoid:
The magnetic field inside a solenoid can be calculated using the formula:
B = μ0 * n' * I
Here, μ0 is the permeability of free space, which has a constant value of 4π * 10^-7 T·m/A.
Substituting the values into the formula:
B = (4π * 10^-7 T·m/A) * (2500 turns/m) * (8 A)
B = 8π * 10^-3 T
Hence, the magnetic field inside the solenoid is 8π * 10^-3 T.
Note: The answer is given in scientific notation, where π is approximately 3.14159.
A closely wound solenoid 80cm.long had 5 layers of winding of 400 turn...
Put the formula (u.ni) coz it's an infinite solenoid as the radius is very less wrt length of solenoid, also here N is given not n so divide the no. of turns by the given length and units are important so keep SI units.so 4π × 10^-7 × 400/ 80×10^-2 × 8× 5ans 8π ×10^-3
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