A woman with two genes for haemophilia and one gene for colour blindne...
If the woman is having 2 genes for haemophilia....does that mean homozygous ?! If it is , then 50% of the sons would be haemophilic and the other half would be haemophilic and color blind .
A woman with two genes for haemophilia and one gene for colour blindne...
Explanation:
Haemophilia and color blindness are both X-linked recessive disorders, meaning they are carried on the X chromosome.
Genetic Makeup of the Woman:
- The woman has two genes for haemophilia and one gene for color blindness on one of her X chromosomes.
- Therefore, she is a carrier for both haemophilia and color blindness.
Genetic Makeup of the Man:
- The man is normal and does not carry any genes for haemophilia or color blindness.
Possible Genetic Combinations in Offspring:
- The woman can pass on either the gene for haemophilia or color blindness to her offspring.
- Since the man is normal, he will pass on a Y chromosome to his sons.
Genetic Outcomes in Progeny:
- Sons:
- 50% of the sons will inherit the X chromosome with the gene for haemophilia from the mother and a Y chromosome from the father, making them haemophilic.
- The other 50% of the sons will inherit the X chromosome with the gene for color blindness from the mother and a Y chromosome from the father, making them color blind.
- Daughters:
- 50% of the daughters will inherit the X chromosome with the gene for haemophilia from the mother and the X chromosome from the father, making them carriers of haemophilia.
- The other 50% of the daughters will inherit the X chromosome with the gene for color blindness from the mother and the X chromosome from the father, making them carriers of color blindness.
Conclusion:
The progeny will consist of a mix of haemophilic sons, color blind sons, carrier daughters for haemophilia, and carrier daughters for color blindness.
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