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A woman with two genes for haemophilia and one gene for colour blindness on one of 'X' chromosome marries a normal man.How will the progeny be? (A) 50 percent haemophilic colour blind sons and 50 percent normal sons (B) 50 percent haemophilic daughters(carrier) and 50 percent colour blind daughters(carrier) (C) all sons and daughters haemophilic and colour blind (D) haemophilic and colour blind daughter.?
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A woman with two genes for haemophilia and one gene for colour blindne...
If the woman is having 2 genes for haemophilia....does that mean homozygous ?! If it is , then 50% of the sons would be haemophilic and the other half would be haemophilic and color blind .
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A woman with two genes for haemophilia and one gene for colour blindne...
Explanation:
Haemophilia and color blindness are both X-linked recessive disorders, meaning they are carried on the X chromosome.
Genetic Makeup of the Woman:
- The woman has two genes for haemophilia and one gene for color blindness on one of her X chromosomes.
- Therefore, she is a carrier for both haemophilia and color blindness.
Genetic Makeup of the Man:
- The man is normal and does not carry any genes for haemophilia or color blindness.
Possible Genetic Combinations in Offspring:
- The woman can pass on either the gene for haemophilia or color blindness to her offspring.
- Since the man is normal, he will pass on a Y chromosome to his sons.
Genetic Outcomes in Progeny:
- Sons:
- 50% of the sons will inherit the X chromosome with the gene for haemophilia from the mother and a Y chromosome from the father, making them haemophilic.
- The other 50% of the sons will inherit the X chromosome with the gene for color blindness from the mother and a Y chromosome from the father, making them color blind.
- Daughters:
- 50% of the daughters will inherit the X chromosome with the gene for haemophilia from the mother and the X chromosome from the father, making them carriers of haemophilia.
- The other 50% of the daughters will inherit the X chromosome with the gene for color blindness from the mother and the X chromosome from the father, making them carriers of color blindness.
Conclusion:
The progeny will consist of a mix of haemophilic sons, color blind sons, carrier daughters for haemophilia, and carrier daughters for color blindness.
Haemophilia and color blindness are both X-linked recessive disorders, meaning they are carried on the X chromosome.
Genetic Makeup of the Woman:
- The woman has two genes for haemophilia and one gene for color blindness on one of her X chromosomes.
- Therefore, she is a carrier for both haemophilia and color blindness.
Genetic Makeup of the Man:
- The man is normal and does not carry any genes for haemophilia or color blindness.
Possible Genetic Combinations in Offspring:
- The woman can pass on either the gene for haemophilia or color blindness to her offspring.
- Since the man is normal, he will pass on a Y chromosome to his sons.
Genetic Outcomes in Progeny:
- Sons:
- 50% of the sons will inherit the X chromosome with the gene for haemophilia from the mother and a Y chromosome from the father, making them haemophilic.
- The other 50% of the sons will inherit the X chromosome with the gene for color blindness from the mother and a Y chromosome from the father, making them color blind.
- Daughters:
- 50% of the daughters will inherit the X chromosome with the gene for haemophilia from the mother and the X chromosome from the father, making them carriers of haemophilia.
- The other 50% of the daughters will inherit the X chromosome with the gene for color blindness from the mother and the X chromosome from the father, making them carriers of color blindness.
Conclusion:
The progeny will consist of a mix of haemophilic sons, color blind sons, carrier daughters for haemophilia, and carrier daughters for color blindness.
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A woman with two genes for haemophilia and one gene for colour blindness on one of 'X' chromosome marries a normal man.How will the progeny be? (A) 50 percent haemophilic colour blind sons and 50 percent normal sons (B) 50 percent haemophilic daughters(carrier) and 50 percent colour blind daughters(carrier) (C) all sons and daughters haemophilic and colour blind (D) haemophilic and colour blind daughter.?
Question Description
A woman with two genes for haemophilia and one gene for colour blindness on one of 'X' chromosome marries a normal man.How will the progeny be? (A) 50 percent haemophilic colour blind sons and 50 percent normal sons (B) 50 percent haemophilic daughters(carrier) and 50 percent colour blind daughters(carrier) (C) all sons and daughters haemophilic and colour blind (D) haemophilic and colour blind daughter.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A woman with two genes for haemophilia and one gene for colour blindness on one of 'X' chromosome marries a normal man.How will the progeny be? (A) 50 percent haemophilic colour blind sons and 50 percent normal sons (B) 50 percent haemophilic daughters(carrier) and 50 percent colour blind daughters(carrier) (C) all sons and daughters haemophilic and colour blind (D) haemophilic and colour blind daughter.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A woman with two genes for haemophilia and one gene for colour blindness on one of 'X' chromosome marries a normal man.How will the progeny be? (A) 50 percent haemophilic colour blind sons and 50 percent normal sons (B) 50 percent haemophilic daughters(carrier) and 50 percent colour blind daughters(carrier) (C) all sons and daughters haemophilic and colour blind (D) haemophilic and colour blind daughter.?.
A woman with two genes for haemophilia and one gene for colour blindness on one of 'X' chromosome marries a normal man.How will the progeny be? (A) 50 percent haemophilic colour blind sons and 50 percent normal sons (B) 50 percent haemophilic daughters(carrier) and 50 percent colour blind daughters(carrier) (C) all sons and daughters haemophilic and colour blind (D) haemophilic and colour blind daughter.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A woman with two genes for haemophilia and one gene for colour blindness on one of 'X' chromosome marries a normal man.How will the progeny be? (A) 50 percent haemophilic colour blind sons and 50 percent normal sons (B) 50 percent haemophilic daughters(carrier) and 50 percent colour blind daughters(carrier) (C) all sons and daughters haemophilic and colour blind (D) haemophilic and colour blind daughter.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A woman with two genes for haemophilia and one gene for colour blindness on one of 'X' chromosome marries a normal man.How will the progeny be? (A) 50 percent haemophilic colour blind sons and 50 percent normal sons (B) 50 percent haemophilic daughters(carrier) and 50 percent colour blind daughters(carrier) (C) all sons and daughters haemophilic and colour blind (D) haemophilic and colour blind daughter.?.
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A woman with two genes for haemophilia and one gene for colour blindness on one of 'X' chromosome marries a normal man.How will the progeny be? (A) 50 percent haemophilic colour blind sons and 50 percent normal sons (B) 50 percent haemophilic daughters(carrier) and 50 percent colour blind daughters(carrier) (C) all sons and daughters haemophilic and colour blind (D) haemophilic and colour blind daughter.?, a detailed solution for A woman with two genes for haemophilia and one gene for colour blindness on one of 'X' chromosome marries a normal man.How will the progeny be? (A) 50 percent haemophilic colour blind sons and 50 percent normal sons (B) 50 percent haemophilic daughters(carrier) and 50 percent colour blind daughters(carrier) (C) all sons and daughters haemophilic and colour blind (D) haemophilic and colour blind daughter.? has been provided alongside types of A woman with two genes for haemophilia and one gene for colour blindness on one of 'X' chromosome marries a normal man.How will the progeny be? (A) 50 percent haemophilic colour blind sons and 50 percent normal sons (B) 50 percent haemophilic daughters(carrier) and 50 percent colour blind daughters(carrier) (C) all sons and daughters haemophilic and colour blind (D) haemophilic and colour blind daughter.? theory, EduRev gives you an
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