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3 gm of urea is dissolved in. 45 mg of H2O .the relative lowering in vapour pressure is?
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3 gm of urea is dissolved in. 45 mg of H2O .the relative lowering in v...
(P• - p / p•) = n2 / n1p•-p/p• ...is RLVPn2 .no .of moles of soluten1..no. of moles of solventso now ..RLVP = (wt of urea / gram mol. wt of urea.) x( gram mol. wt of H2O / wt of H2O.)urea mol. wt is 60 ..!nd H2O is 18...!they gave 45 mg means 45 x 10^ -3 (milli gram)now do u got that..!?here n1 means no of moles of solvent which is in denominator....so i wrote it reverse..!!!
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3 gm of urea is dissolved in. 45 mg of H2O .the relative lowering in v...
Calculation of Relative Lowering in Vapour Pressure
Given data:
- Mass of urea (m1) = 3 gm
- Mass of water (m2) = 45 mg
- Molar mass of urea = 60 g/mol
- Vapour pressure of pure water = P°
Step 1: Calculate the number of moles of urea
- Number of moles of urea (n1) = Mass of urea / Molar mass of urea
- n1 = 3 g / 60 g/mol
- n1 = 0.05 mol
Step 2: Calculate the number of moles of water
- Number of moles of water (n2) = Mass of water / Molar mass of water
- n2 = 45 mg / 18 g/mol
- n2 = 0.0025 mol
Step 3: Calculate the total number of moles in the solution
- Total number of moles (n) = n1 + n2
- n = 0.05 mol + 0.0025 mol
- n = 0.0525 mol
Step 4: Calculate the relative lowering in vapour pressure
- According to Raoult's law, the relative lowering in vapour pressure (ΔP/P°) is given by:
- ΔP/P° = x2
- where x2 is the mole fraction of the solute (urea)
Step 5: Calculate the mole fraction of urea
- Mole fraction of urea (x1) = n1 / n
- x1 = 0.05 mol / 0.0525 mol
- x1 = 0.9524
Step 6: Calculate the relative lowering in vapour pressure
- ΔP/P° = x2 = 1 - x1
- ΔP/P° = 1 - 0.9524
- ΔP/P° = 0.0476
Step 7: Expressing the result
- The relative lowering in vapour pressure is 0.0476 or 4.76%.
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3 gm of urea is dissolved in. 45 mg of H2O .the relative lowering in vapour pressure is?
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3 gm of urea is dissolved in. 45 mg of H2O .the relative lowering in vapour pressure is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 3 gm of urea is dissolved in. 45 mg of H2O .the relative lowering in vapour pressure is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3 gm of urea is dissolved in. 45 mg of H2O .the relative lowering in vapour pressure is?.
3 gm of urea is dissolved in. 45 mg of H2O .the relative lowering in vapour pressure is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 3 gm of urea is dissolved in. 45 mg of H2O .the relative lowering in vapour pressure is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3 gm of urea is dissolved in. 45 mg of H2O .the relative lowering in vapour pressure is?.
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