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Two equal resistors, each of resistance R, connected in series across a voltage source V dissipate power P. What would be the power dissipated in the same resistors when they are connected in parallel across the same voltage source?
  • a)
    4P 
  • b)
    2P
  • c)
    16P
  • d)
    P
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Two equal resistors, each of resistance R, connected in series across ...

Explanation:

When resistors are connected in series:
- In series connection, the total resistance is equal to the sum of individual resistances: Rs = R + R = 2R.
- The current flowing through each resistor is the same, I = V / Rs.
- The power dissipated by each resistor is given by P = I^2 * R = (V / Rs)^2 * R = V^2 * R / (2R)^2 = V^2 * R / 4R^2 = V^2 / 4R.

When resistors are connected in parallel:
- In parallel connection, the total resistance is given by Rp = R / 2.
- The current flowing through each resistor is split between them, so the current through each resistor is I = V / R.
- The power dissipated by each resistor is given by P = I^2 * R = (V / R)^2 * R = V^2 / R.

Comparing the power dissipated:
- Power dissipated in series connection: V^2 / 4R.
- Power dissipated in parallel connection: V^2 / R.

Therefore, the power dissipated in parallel connection is 4 times greater than the power dissipated in series connection. Hence, the correct answer is option 'A'.
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Community Answer
Two equal resistors, each of resistance R, connected in series across ...
Let R be the resistance of the identical two resistors. When they are connected in series across a voltage source V, the equivalent resistance of the combination is 2R and then total power dissipated by the resistors will be P = V2/2R.
When they are connected in parallel across the same voltage source V, the equivalent resistance of the combination is R/2, and then total power dissipated by the resistors will be V2/(R/2) = 4V2/2R = 4P.
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