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Vapour pressure of methyl alcohol and ethyl alcohol solution is represented by P = 115 Xa+ 140 Xa is the mole fraction of methyl alcohol. The value of lim xa-> 0 (Pb ^ 0)/xb is?
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Vapour pressure of methyl alcohol and ethyl alcohol solution is repres...
Given Data:
The vapour pressure of the methyl alcohol and ethyl alcohol solution is represented by the equation:
P = 115 Xa + 140 Xa, where Xa is the mole fraction of methyl alcohol.

Calculation:
To find the value of lim xa-> 0 (Pb ^ 0)/xb, we first need to express the equation in terms of the mole fraction of ethyl alcohol (Xb).
Since the total mole fraction is always equal to 1, we have:
Xa + Xb = 1
Xb = 1 - Xa
Substitute Xb = 1 - Xa into the equation for vapour pressure:
P = 115 Xa + 140 (1 - Xa)
P = 140 - 25 Xa
Now, we can find the mole fraction of ethyl alcohol (Xb) in terms of Xa:
Xb = 1 - Xa
Next, we can calculate the limit as Xa approaches 0:
lim xa-> 0 (Pb ^ 0)/xb = lim xa-> 0 (140 - 25 Xa)/ (1 - Xa)
= 140/1 = 140
Therefore, the value of lim xa-> 0 (Pb ^ 0)/xb is 140.
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Vapour pressure of methyl alcohol and ethyl alcohol solution is represented by P = 115 Xa+ 140 Xa is the mole fraction of methyl alcohol. The value of lim xa-> 0 (Pb ^ 0)/xb is?
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