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Molarity of 29% [w/w] h2so4 solution whose density is 1.22 g ml‐¹ is?
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Molarity of 29% [w/w] h2so4 solution whose density is 1.22 g ml‐¹ is?
Molarity Calculation of 29% w/w H2SO4 Solution
To determine the molarity of a 29% w/w sulfuric acid (H2SO4) solution with a density of 1.22 g/ml, follow these steps:
1. Calculate the mass of the solution
- Assume we have 1000 g (1 kg) of the solution.
- Thus, the mass of H2SO4 in the solution = 29% of 1000 g = 290 g.
2. Calculate the volume of the solution
- Use the density to find the volume:
- Density = Mass/Volume
- Rearranging gives Volume = Mass/Density.
- Volume of the solution = 1000 g / 1.22 g/ml = 819.67 ml = 0.81967 L.
3. Calculate the number of moles of H2SO4
- Molar mass of H2SO4 = 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol.
- Moles of H2SO4 = Mass of H2SO4 / Molar mass = 290 g / 98.09 g/mol = 2.95 moles.
4. Calculate the molarity of the solution
- Molarity (M) = Moles of solute / Volume of solution in liters.
- Molarity = 2.95 moles / 0.81967 L = 3.60 M.
Final Result
- The molarity of the 29% w/w H2SO4 solution is approximately 3.60 M.
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Molarity of 29% [w/w] h2so4 solution whose density is 1.22 g ml‐¹ is?
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