How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27...
C.P. of 1 kg sugar of 1st kind C.P. of 1 kg sugar of 2nd kind
Therefore, Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.
Let x kg of sugar of 1st kind be mixed with 27 kg of 2nd kind.
Then, 7 : 3 = x : 27 or x = (7 x 27 / 3) = 63 kg.
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How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27...
Profit per kg = 9.24 ×1/11=0.84....... Cost of sugar per kg = 9.24 - 0.84 =8.4......... Let's x amount of sugar costing 9 rs. Per kg will be added...... Cost per kg = total cost ÷ total quantity........Then, (7×27 + 9x) ÷ (27 + x) = 8.4........ => 7×27 + 9x = 8.4x + 8.4 × 27........=> 0.6x = 27 (8.4 - 7)..........=> x = 27×14 ÷ 6.........=> x =9×7 = 63
How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27...
Given:
Cost of sugar A = Rs. 9/kg
Cost of sugar B = Rs. 7/kg
Selling price of mixture = Rs. 9.24/kg
Profit percentage = 10%
To find:
How many kilograms of sugar A must be mixed with sugar B so that there is a gain of 10% by selling the mixture at Rs. 9.24/kg.
Solution:
Let the quantity of sugar A be x kg.
Quantity of sugar B = 27 kg (Given)
Total quantity of mixture = x + 27 kg
Cost price of sugar A = Rs. 9/kg
Cost price of sugar B = Rs. 7/kg
Cost price of x kg of sugar A = Rs. 9x
Cost price of 27 kg of sugar B = Rs. 7 × 27 = Rs. 189
Total cost price of mixture = 9x + 189
Selling price of mixture = Rs. 9.24/kg
Profit percentage = 10%
Profit = Selling price - Cost price
Profit percentage = (Profit/Cost price) × 100
Profit percentage = ((9.24 - (9x + 189))/(9x + 189)) × 100
10% = ((9.24 - (9x + 189))/(9x + 189)) × 100
1 = ((9.24 - (9x + 189))/(9x + 189))
9x + 189 = 8.24x + 7.416
0.76x = 181.584
x = 239 kg
Therefore, 239 kg of sugar A must be mixed with 27 kg of sugar B to get a mixture that can be sold at Rs. 9.24/kg with a gain of 10%.