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31 g of phosphorus (P4) and 32 g of oxygen are completely converted into P4O6 & P4O10 respectively, then moles of P4O6 & P4O10 formed respectively will be(1) 1/8, 1/8(2) 1/16, 3/16(3) 3/16, 1/16(4) 5/32, 3/32 ?
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31 g of phosphorus (P4) and 32 g of oxygen are completely converted in...
The balanced chemical equation for the reaction is:
P4 + 3O2 → P4O6
To find the limiting reactant, we need to calculate the moles of each reactant:
Moles of P4 = 31 g / 123.89 g/mol = 0.25 mol
Moles of O2 = 32 g / 31.9988 g/mol = 1 mol
According to the balanced equation, 1 mole of P4 reacts with 3 moles of O2 to form 2 moles of P4O6. Therefore, the theoretical yield of P4O6 can be calculated for each reactant:
Theoretical yield with P4 = 0.25 mol P4 x (2 mol P4O6 / 1 mol P4) x (283.88 g P4O6 / 1 mol P4O6) = 14.19 g P4O6
Theoretical yield with O2 = 1 mol O2 x (2 mol P4O6 / 3 mol O2) x (283.88 g P4O6 / 1 mol P4O6) = 189.17 g P4O6
Since the actual yield is not given, we cannot determine the percent yield. However, we can determine the limiting reactant by comparing the theoretical yields. The smaller theoretical yield corresponds to the limiting reactant:
P4 yields 14.19 g P4O6
O2 yields 189.17 g P4O6
Therefore, P4 is the limiting reactant and 14.19 g of P4O6 is the maximum amount that can be produced from the given amount of reactants.
P4 + 3O2 → P4O6
To find the limiting reactant, we need to calculate the moles of each reactant:
Moles of P4 = 31 g / 123.89 g/mol = 0.25 mol
Moles of O2 = 32 g / 31.9988 g/mol = 1 mol
According to the balanced equation, 1 mole of P4 reacts with 3 moles of O2 to form 2 moles of P4O6. Therefore, the theoretical yield of P4O6 can be calculated for each reactant:
Theoretical yield with P4 = 0.25 mol P4 x (2 mol P4O6 / 1 mol P4) x (283.88 g P4O6 / 1 mol P4O6) = 14.19 g P4O6
Theoretical yield with O2 = 1 mol O2 x (2 mol P4O6 / 3 mol O2) x (283.88 g P4O6 / 1 mol P4O6) = 189.17 g P4O6
Since the actual yield is not given, we cannot determine the percent yield. However, we can determine the limiting reactant by comparing the theoretical yields. The smaller theoretical yield corresponds to the limiting reactant:
P4 yields 14.19 g P4O6
O2 yields 189.17 g P4O6
Therefore, P4 is the limiting reactant and 14.19 g of P4O6 is the maximum amount that can be produced from the given amount of reactants.
Community Answer
31 g of phosphorus (P4) and 32 g of oxygen are completely converted in...
See....here p and o are taken by there molar mass hence moles of both of them are 1....Nd again we HV that they completely converted into d product Nd both product should HV equal moles...Nd which added to become 1....Nd we HV only option 1 for our conclusion....we can solve it by unitry method...Nd which we HV to take moles of both product should be same Nd total mass of product should be equal to total mass of d reactants Nd we HV molar mass of both products Nd by solving it we will get 1/8....but in my point of view first one is easier...
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31 g of phosphorus (P4) and 32 g of oxygen are completely converted into P4O6 & P4O10 respectively, then moles of P4O6 & P4O10 formed respectively will be(1) 1/8, 1/8(2) 1/16, 3/16(3) 3/16, 1/16(4) 5/32, 3/32 ?
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31 g of phosphorus (P4) and 32 g of oxygen are completely converted into P4O6 & P4O10 respectively, then moles of P4O6 & P4O10 formed respectively will be(1) 1/8, 1/8(2) 1/16, 3/16(3) 3/16, 1/16(4) 5/32, 3/32 ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 31 g of phosphorus (P4) and 32 g of oxygen are completely converted into P4O6 & P4O10 respectively, then moles of P4O6 & P4O10 formed respectively will be(1) 1/8, 1/8(2) 1/16, 3/16(3) 3/16, 1/16(4) 5/32, 3/32 ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 31 g of phosphorus (P4) and 32 g of oxygen are completely converted into P4O6 & P4O10 respectively, then moles of P4O6 & P4O10 formed respectively will be(1) 1/8, 1/8(2) 1/16, 3/16(3) 3/16, 1/16(4) 5/32, 3/32 ?.
31 g of phosphorus (P4) and 32 g of oxygen are completely converted into P4O6 & P4O10 respectively, then moles of P4O6 & P4O10 formed respectively will be(1) 1/8, 1/8(2) 1/16, 3/16(3) 3/16, 1/16(4) 5/32, 3/32 ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 31 g of phosphorus (P4) and 32 g of oxygen are completely converted into P4O6 & P4O10 respectively, then moles of P4O6 & P4O10 formed respectively will be(1) 1/8, 1/8(2) 1/16, 3/16(3) 3/16, 1/16(4) 5/32, 3/32 ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 31 g of phosphorus (P4) and 32 g of oxygen are completely converted into P4O6 & P4O10 respectively, then moles of P4O6 & P4O10 formed respectively will be(1) 1/8, 1/8(2) 1/16, 3/16(3) 3/16, 1/16(4) 5/32, 3/32 ?.
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