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A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in
- a)4 days
- b)6 days
- c)8 days
- d)18 days
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A works twice as fast as B. If B can complete a work in 12 days indepe...
Ratio of rates of working of A and B = 2 : 1
So, ratio of time taken = 1 : 2
B's 1 day's work = 1/12
∴ A's one day work = 1/3 (2 times of B's work)
(A + B)'s 1 day's work = (1/6) + (1/12) = 3/12 = 1/4
So, A and B together can finish work in 4 days.
So, ratio of time taken = 1 : 2
B's 1 day's work = 1/12
∴ A's one day work = 1/3 (2 times of B's work)
(A + B)'s 1 day's work = (1/6) + (1/12) = 3/12 = 1/4
So, A and B together can finish work in 4 days.
Most Upvoted Answer
A works twice as fast as B. If B can complete a work in 12 days indepe...
Given: A works twice as fast as B. B can complete the work in 12 days.
To find: The number of days in which A and B can together finish the work.
Solution:
Let us assume that B can complete the work in 'x' days.
Then A can complete the same work in x/2 days. (As A works twice as fast as B)
Given that B can complete the work in 12 days.
Therefore, x = 12.
So, B completes the work in 12 days.
A can complete the same work in 12/2 = 6 days.
Now, let us consider the case where A and B work together.
Let the total work be denoted by 'W'.
Let us assume that A and B can together complete the work in 'd' days.
In one day, the work done by A and B together = (1/6 + 1/12) = 1/4. (As A can complete 1/6th of the work in a day and B can complete 1/12th of the work in a day)
Therefore, the work done by A and B together in 'd' days = d/4.
As per the question, the work done by A and B together is 'W'.
Therefore, we can write:
d/4 = W
d = 4W
Therefore, A and B can together complete the work in 4 days.
Hence, the correct option is (a) 4 days.
To find: The number of days in which A and B can together finish the work.
Solution:
Let us assume that B can complete the work in 'x' days.
Then A can complete the same work in x/2 days. (As A works twice as fast as B)
Given that B can complete the work in 12 days.
Therefore, x = 12.
So, B completes the work in 12 days.
A can complete the same work in 12/2 = 6 days.
Now, let us consider the case where A and B work together.
Let the total work be denoted by 'W'.
Let us assume that A and B can together complete the work in 'd' days.
In one day, the work done by A and B together = (1/6 + 1/12) = 1/4. (As A can complete 1/6th of the work in a day and B can complete 1/12th of the work in a day)
Therefore, the work done by A and B together in 'd' days = d/4.
As per the question, the work done by A and B together is 'W'.
Therefore, we can write:
d/4 = W
d = 4W
Therefore, A and B can together complete the work in 4 days.
Hence, the correct option is (a) 4 days.
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Community Answer
A works twice as fast as B. If B can complete a work in 12 days indepe...
Ratio of rates of working of A and B = 2 : 1
So, ratio of time taken = 1 : 2
B's 1 day's work = 1/12
∴ A's one day work = 1/3 (2 times of B's work)
(A + B)'s 1 day's work = (1/6) + (1/12) = 3/12 = 1/4
So, A and B together can finish work in 4 days.
So, ratio of time taken = 1 : 2
B's 1 day's work = 1/12
∴ A's one day work = 1/3 (2 times of B's work)
(A + B)'s 1 day's work = (1/6) + (1/12) = 3/12 = 1/4
So, A and B together can finish work in 4 days.
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A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work ina)4 daysb)6 daysc)8 daysd)18 daysCorrect answer is option 'A'. Can you explain this answer?
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