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In a random mating population of 20000, 16800 individuals are the dominant then how many individuals will be homozygous?
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In a random mating population of 20000, 16800 individuals are the domi...
By Hardy Weinberg law,
p²+2pq+q²=1
(16800/20000)+q²=1
q²=3200/20000
q=0.4
p=0.6
p²+q²=0.52

Required individuals= 0.52×20000
=10400
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In a random mating population of 20000, 16800 individuals are the dominant then how many individuals will be homozygous?
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