One root of the quadratic equation x2- 12x + a = 0, is thrice the othe...
Explanation:
Let the roots of the quadratic equation be x and 3x.
Sum of roots = -(-12) = 12
a + 3a = 4a = 12 => a = 3
Product of the roots = 3a2 = 3(3)2 = 27.
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One root of the quadratic equation x2- 12x + a = 0, is thrice the othe...
**Quadratic Equation and its Roots:**
A quadratic equation is an equation of the form ax^2 + bx + c = 0, where a, b, and c are constants and x is the variable. The solutions to this equation are called the roots of the quadratic equation.
The roots of a quadratic equation can be found using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a).
**Given Information:**
In the given quadratic equation, x^2 - 12x + a = 0, one root is thrice the other. Let's assume the roots of the equation are p and 3p, where p is a constant.
**Sum and Product of Roots:**
The sum of the roots of a quadratic equation is given by the formula: sum = -b/a.
The product of the roots of a quadratic equation is given by the formula: product = c/a.
**Applying the Given Information:**
We know that one root is p and the other root is 3p. Therefore, the sum of the roots is p + 3p = 4p.
By comparing this with the formula for the sum of roots, we have: 4p = -(-12)/1 = 12.
Simplifying, we find: p = 12/4 = 3.
Therefore, the roots of the quadratic equation are p = 3 and 3p = 9.
**Finding the Value of a:**
To find the value of a, we can use the product of roots formula.
The product of the roots is p * 3p = 3 * 9 = 27.
By comparing this with the formula for the product of roots, we have: 27 = a/1.
Therefore, the value of a is 27.
**Conclusion:**
The value of a in the quadratic equation x^2 - 12x + a = 0, where one root is thrice the other, is 27.
Therefore, the correct answer is option E) None of these.