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The hybridization of atomic orbital of nitrogen in NO2+, NO3- and NH4+ are:

  • a)
    sp, sp2, sp3

  • b)
    sp2, sp3, sp

  • c)
    sp2, sp, sp3

  • d)
    sp, sp3, sp2

Correct answer is option 'A'. Can you explain this answer?
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The hybridization of atomic orbital of nitrogen in NO2+, NO3- and NH4+...
Hybridization of Nitrogen in NO2, NO3- and NH4+

Explanation:

NO2 (Nitrogen Dioxide):
In NO2, nitrogen has one lone pair and two sigma bonds with oxygen atoms. The electronic configuration of nitrogen is 1s2 2s2 2p3. Nitrogen promotes an electron from 2s to 2p orbital and hybridizes with one 2s and two 2p orbitals of nitrogen and oxygen atoms. Therefore, the hybridization of nitrogen in NO2 is sp.

NO3- (Nitrate ion):
In NO3-, nitrogen has no lone pair and three sigma bonds with oxygen atoms. The electronic configuration of nitrogen is 1s2 2s2 2p3. Nitrogen promotes an electron from 2s to 2p orbital and hybridizes with one 2s and three 2p orbitals of nitrogen and oxygen atoms. Therefore, the hybridization of nitrogen in NO3- is sp2.

NH4+ (Ammonium ion):
In NH4+, nitrogen has no lone pair and four sigma bonds with four hydrogen atoms. The electronic configuration of nitrogen is 1s2 2s2 2p3. Nitrogen promotes an electron from 2s to 2p orbital and hybridizes with one 2s and three 2p orbitals of nitrogen and hydrogen atoms. Therefore, the hybridization of nitrogen in NH4+ is sp3.

Conclusion:
The hybridization of nitrogen in NO2, NO3- and NH4+ are sp, sp2, and sp3 respectively.
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The hybridization of atomic orbital of nitrogen in NO2+, NO3- and NH4+...
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The hybridization of atomic orbital of nitrogen in NO2+, NO3- and NH4+ are:a)sp, sp2, sp3b)sp2, sp3, spc)sp2, sp, sp3d)sp, sp3, sp2Correct answer is option 'A'. Can you explain this answer?
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