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0.5 M HCl solution has ions Hg2 , Cd2 , Sr2 , Fe2 , Cu2 . To pass the H2S gas in the solution, which are precipitated out A) Cd2 , Fe2 , Sr2 B) Cd2 , Hg2 , Cu2 C) Hg2 , Cu2 , Fe2 D) Cu2 , Sr2 , Fe2?
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0.5 M HCl solution has ions Hg2 , Cd2 , Sr2 , Fe2 , Cu2 . To pass the ...
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Option B is correct
most insoluble Sulphide cations are-Hg+2,Pb+2,Cu+2,Cd+2,Bi+3
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0.5 M HCl solution has ions Hg2 , Cd2 , Sr2 , Fe2 , Cu2 . To pass the ...
Answer:

To determine which ions will precipitate out when H2S gas is passed through a 0.5 M HCl solution, we need to consider the solubility rules for sulfides.

Solubility rules for sulfides:
1. Group 1 and ammonium (NH4+) salts are soluble.
2. Sulfides of group 2 (alkaline earth metals) and heavy metals are insoluble, except for those of calcium (Ca2+), strontium (Sr2+), and barium (Ba2+).
3. Sulfides of transition metals are generally insoluble, except for those of zinc (Zn2+) and cadmium (Cd2+).

Considering these rules, we can determine which ions will precipitate out:

A) Cd2, Fe2, Sr2:
- Cd2: According to rule 3, sulfides of transition metals are generally insoluble, so CdS will precipitate.
- Fe2: According to rule 3, sulfides of transition metals are generally insoluble, so FeS will precipitate.
- Sr2: According to rule 2, sulfides of group 2 metals are insoluble, except for those of Ca2+, Sr2+, and Ba2+, so SrS will precipitate.
Therefore, option A) Cd2, Fe2, Sr2 is correct.

B) Cd2, Hg2, Cu2:
- Cd2: According to rule 3, CdS will precipitate.
- Hg2: According to rule 3, HgS will precipitate.
- Cu2: According to rule 3, CuS will precipitate.
Therefore, option B) Cd2, Hg2, Cu2 is correct.

C) Hg2, Cu2, Fe2:
- Hg2: According to rule 3, HgS will precipitate.
- Cu2: According to rule 3, CuS will precipitate.
- Fe2: According to rule 3, FeS will precipitate.
Therefore, option C) Hg2, Cu2, Fe2 is correct.

D) Cu2, Sr2, Fe2:
- Cu2: According to rule 3, CuS will precipitate.
- Sr2: According to rule 2, SrS will precipitate.
- Fe2: According to rule 3, FeS will precipitate.
Therefore, option D) Cu2, Sr2, Fe2 is correct.

In summary:
Based on the solubility rules for sulfides, the ions that will precipitate out when H2S gas is passed through a 0.5 M HCl solution are:
- Cd2, Fe2, Sr2 (option A)
- Cd2, Hg2, Cu2 (option B)
- Hg2, Cu2, Fe2 (option C)
- Cu2, Sr2, Fe2 (option D)
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0.5 M HCl solution has ions Hg2 , Cd2 , Sr2 , Fe2 , Cu2 . To pass the H2S gas in the solution, which are precipitated out A) Cd2 , Fe2 , Sr2 B) Cd2 , Hg2 , Cu2 C) Hg2 , Cu2 , Fe2 D) Cu2 , Sr2 , Fe2?
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0.5 M HCl solution has ions Hg2 , Cd2 , Sr2 , Fe2 , Cu2 . To pass the H2S gas in the solution, which are precipitated out A) Cd2 , Fe2 , Sr2 B) Cd2 , Hg2 , Cu2 C) Hg2 , Cu2 , Fe2 D) Cu2 , Sr2 , Fe2? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 0.5 M HCl solution has ions Hg2 , Cd2 , Sr2 , Fe2 , Cu2 . To pass the H2S gas in the solution, which are precipitated out A) Cd2 , Fe2 , Sr2 B) Cd2 , Hg2 , Cu2 C) Hg2 , Cu2 , Fe2 D) Cu2 , Sr2 , Fe2? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.5 M HCl solution has ions Hg2 , Cd2 , Sr2 , Fe2 , Cu2 . To pass the H2S gas in the solution, which are precipitated out A) Cd2 , Fe2 , Sr2 B) Cd2 , Hg2 , Cu2 C) Hg2 , Cu2 , Fe2 D) Cu2 , Sr2 , Fe2?.
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