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Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which will be precipitate first on adding NH4OH if M 2 and M 3 both ions are in solutions? a) M^+2 b) M^+3 C) both together d) precipitate will not occur?
correct ans is b
can u explain?
correct ans is b
can u explain?
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Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which ...
B)).the solubility of M+2 is more than M+3 ion so precipitation occur first in M+3 ion
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Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which ...
Solubility Product and Precipitation
When a sparingly soluble salt is dissolved in water, it dissociates into its ions. The extent to which a salt will dissolve can be determined by its solubility product (Ksp) value. The solubility product is the product of the concentrations of the ions raised to the power of their stoichiometric coefficients in the balanced equation for the dissociation of the salt.
In this case, we are given the solubility product values for M(OH)3 and M(OH)2 as 10^-23 and 10^-14, respectively. Let's assume that M2+ and M3+ ions are present in the solution.
Precipitation of M(OH)3 and M(OH)2
When NH4OH is added to the solution, it will react with the M2+ and M3+ ions to form precipitates. The solubility of a compound is determined by comparing the value of its solubility product (Ksp) with the ion product (IP) of the solution.
The ion product (IP) is calculated by multiplying the concentrations of the ions in the solution raised to the power of their stoichiometric coefficients. If the ion product is greater than the solubility product, precipitation occurs.
Let's compare the ion product (IP) for M(OH)3 and M(OH)2 with their respective solubility products (Ksp).
Precipitation of M(OH)3:
The ion product for M(OH)3 can be represented as [M2+][OH-]^3. Since the concentration of OH- ions is determined by the concentration of NH4OH, which is in excess, we only need to consider the concentration of M2+ ions.
If the Ksp for M(OH)3 is 10^-23, and the concentration of M2+ ions exceeds the concentration given by the Ksp, precipitation of M(OH)3 will occur first.
Precipitation of M(OH)2:
The ion product for M(OH)2 can be represented as [M3+][OH-]^2. Again, since the concentration of OH- ions is determined by the concentration of NH4OH, we only need to consider the concentration of M3+ ions.
If the Ksp for M(OH)2 is 10^-14, and the concentration of M3+ ions exceeds the concentration given by the Ksp, precipitation of M(OH)2 will occur.
Conclusion:
Comparing the solubility product values, we see that the Ksp for M(OH)2 is higher than that of M(OH)3. Therefore, the precipitation of M(OH)2 will occur first when NH4OH is added to the solution containing M2+ and M3+ ions. The correct answer is option b) M3.
When a sparingly soluble salt is dissolved in water, it dissociates into its ions. The extent to which a salt will dissolve can be determined by its solubility product (Ksp) value. The solubility product is the product of the concentrations of the ions raised to the power of their stoichiometric coefficients in the balanced equation for the dissociation of the salt.
In this case, we are given the solubility product values for M(OH)3 and M(OH)2 as 10^-23 and 10^-14, respectively. Let's assume that M2+ and M3+ ions are present in the solution.
Precipitation of M(OH)3 and M(OH)2
When NH4OH is added to the solution, it will react with the M2+ and M3+ ions to form precipitates. The solubility of a compound is determined by comparing the value of its solubility product (Ksp) with the ion product (IP) of the solution.
The ion product (IP) is calculated by multiplying the concentrations of the ions in the solution raised to the power of their stoichiometric coefficients. If the ion product is greater than the solubility product, precipitation occurs.
Let's compare the ion product (IP) for M(OH)3 and M(OH)2 with their respective solubility products (Ksp).
Precipitation of M(OH)3:
The ion product for M(OH)3 can be represented as [M2+][OH-]^3. Since the concentration of OH- ions is determined by the concentration of NH4OH, which is in excess, we only need to consider the concentration of M2+ ions.
If the Ksp for M(OH)3 is 10^-23, and the concentration of M2+ ions exceeds the concentration given by the Ksp, precipitation of M(OH)3 will occur first.
Precipitation of M(OH)2:
The ion product for M(OH)2 can be represented as [M3+][OH-]^2. Again, since the concentration of OH- ions is determined by the concentration of NH4OH, we only need to consider the concentration of M3+ ions.
If the Ksp for M(OH)2 is 10^-14, and the concentration of M3+ ions exceeds the concentration given by the Ksp, precipitation of M(OH)2 will occur.
Conclusion:
Comparing the solubility product values, we see that the Ksp for M(OH)2 is higher than that of M(OH)3. Therefore, the precipitation of M(OH)2 will occur first when NH4OH is added to the solution containing M2+ and M3+ ions. The correct answer is option b) M3.
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Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which will be precipitate first on adding NH4OH if M 2 and M 3 both ions are in solutions? a) M^+2 b) M^+3 C) both together d) precipitate will not occur?correct ans is b can u explain?
Question Description
Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which will be precipitate first on adding NH4OH if M 2 and M 3 both ions are in solutions? a) M^+2 b) M^+3 C) both together d) precipitate will not occur?correct ans is b can u explain? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which will be precipitate first on adding NH4OH if M 2 and M 3 both ions are in solutions? a) M^+2 b) M^+3 C) both together d) precipitate will not occur?correct ans is b can u explain? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which will be precipitate first on adding NH4OH if M 2 and M 3 both ions are in solutions? a) M^+2 b) M^+3 C) both together d) precipitate will not occur?correct ans is b can u explain?.
Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which will be precipitate first on adding NH4OH if M 2 and M 3 both ions are in solutions? a) M^+2 b) M^+3 C) both together d) precipitate will not occur?correct ans is b can u explain? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which will be precipitate first on adding NH4OH if M 2 and M 3 both ions are in solutions? a) M^+2 b) M^+3 C) both together d) precipitate will not occur?correct ans is b can u explain? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which will be precipitate first on adding NH4OH if M 2 and M 3 both ions are in solutions? a) M^+2 b) M^+3 C) both together d) precipitate will not occur?correct ans is b can u explain?.
Solutions for Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which will be precipitate first on adding NH4OH if M 2 and M 3 both ions are in solutions? a) M^+2 b) M^+3 C) both together d) precipitate will not occur?correct ans is b can u explain? in English & in Hindi are available as part of our courses for NEET.
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Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which will be precipitate first on adding NH4OH if M 2 and M 3 both ions are in solutions? a) M^+2 b) M^+3 C) both together d) precipitate will not occur?correct ans is b can u explain?, a detailed solution for Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which will be precipitate first on adding NH4OH if M 2 and M 3 both ions are in solutions? a) M^+2 b) M^+3 C) both together d) precipitate will not occur?correct ans is b can u explain? has been provided alongside types of Solubility product of M(oh)3 and M(oh)2 are 10^-23 and 10^-14 . Which will be precipitate first on adding NH4OH if M 2 and M 3 both ions are in solutions? a) M^+2 b) M^+3 C) both together d) precipitate will not occur?correct ans is b can u explain? theory, EduRev gives you an
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