When 0.02 moles of NaOH are added to a litre of buffer solution, its p...
Given:
- Initial pH of buffer solution (pH
i): 5.75
- Final pH of buffer solution after addition of NaOH (pH
f): 5.80
- Moles of NaOH added: 0.02 mol
- Volume of buffer solution: 1 L
Calculating Change in pH:
The change in pH of a solution can be calculated using the formula:
ΔpH = pH
f - pH
iSubstituting the given values:
ΔpH = 5.80 - 5.75
ΔpH = 0.05
Calculating Buffer Capacity:
The buffer capacity (β) of a solution is a measure of its ability to resist changes in pH when an acid or base is added. It can be calculated using the formula:
β = Δn/ΔpH
Where:
Δn is the change in moles of acid or base added
ΔpH is the change in pH
In this case, Δn is the moles of NaOH added, which is given as 0.02 mol. Substituting the values into the formula:
β = 0.02 mol / 0.05
Simplifying the Calculation:
To simplify the calculation, we divide both the numerator and denominator by 0.01:
β = (0.02 mol / 0.01) / (0.05 / 0.01)
β = 2 / 0.5
β = 4
Interpreting the Result:
The buffer capacity of the solution is 4.
Answer:
The buffer capacity of the solution is 4. Therefore, the correct option is D) 2.5.