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What is the difference in pH for 1/3 and 2/3 stages of neutralisation of 0.1 M CH3COOH with 0.1 M NaOH?
a)– 2 log 3
b)2 log (1/4)
c)2 log (2/3)
d) 2 log 2
Correct answer is option 'D'. Can you explain this answer?
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What is the difference in pH for 1/3 and 2/3 stages of neutralisation ...
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What is the difference in pH for 1/3 and 2/3 stages of neutralisation ...
Understanding Neutralisation Stages
In the neutralisation of acetic acid (CH3COOH) with sodium hydroxide (NaOH), we consider two distinct stages:
- 1/3 Stage: This refers to the point where 1/3 of the acetic acid has been neutralised.
- 2/3 Stage: This is the point where 2/3 of the acetic acid has been neutralised.
Buffer Solution at Different Stages
At these stages, the solutions act as buffer systems:
- 1/3 Stage: 1 part CH3COOH and 2 parts CH3COO- (acetate ion).
- 2/3 Stage: 2 parts CH3COOH and 1 part CH3COO-.
Using the Henderson-Hasselbalch equation, the pH can be determined as:
- pH = pKa + log([A-]/[HA])
Where pKa is the dissociation constant of acetic acid (~4.76).
Calculating pH at Each Stage
- pH at 1/3 Stage:
- [A-]/[HA] = 2/1
- pH1 = pKa + log(2)
- pH at 2/3 Stage:
- [A-]/[HA] = 1/2
- pH2 = pKa + log(1/2)
Finding the Difference in pH
To find the difference in pH between the two stages:
- ΔpH = pH2 - pH1
- ΔpH = (pKa + log(1/2)) - (pKa + log(2))
- ΔpH = log(1/2) - log(2) = log(1/4)
Since log(1/4) = -2 log(2), we have:
- ΔpH = 2 log(2)
Therefore, the correct answer is option D: 2 log 2, which reflects the change in pH between the 1/3 and 2/3 stages of neutralisation.
In the neutralisation of acetic acid (CH3COOH) with sodium hydroxide (NaOH), we consider two distinct stages:
- 1/3 Stage: This refers to the point where 1/3 of the acetic acid has been neutralised.
- 2/3 Stage: This is the point where 2/3 of the acetic acid has been neutralised.
Buffer Solution at Different Stages
At these stages, the solutions act as buffer systems:
- 1/3 Stage: 1 part CH3COOH and 2 parts CH3COO- (acetate ion).
- 2/3 Stage: 2 parts CH3COOH and 1 part CH3COO-.
Using the Henderson-Hasselbalch equation, the pH can be determined as:
- pH = pKa + log([A-]/[HA])
Where pKa is the dissociation constant of acetic acid (~4.76).
Calculating pH at Each Stage
- pH at 1/3 Stage:
- [A-]/[HA] = 2/1
- pH1 = pKa + log(2)
- pH at 2/3 Stage:
- [A-]/[HA] = 1/2
- pH2 = pKa + log(1/2)
Finding the Difference in pH
To find the difference in pH between the two stages:
- ΔpH = pH2 - pH1
- ΔpH = (pKa + log(1/2)) - (pKa + log(2))
- ΔpH = log(1/2) - log(2) = log(1/4)
Since log(1/4) = -2 log(2), we have:
- ΔpH = 2 log(2)
Therefore, the correct answer is option D: 2 log 2, which reflects the change in pH between the 1/3 and 2/3 stages of neutralisation.
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What is the difference in pH for 1/3 and 2/3 stages of neutralisation of 0.1 M CH3COOH with 0.1 M NaOH?a)– 2 log 3b)2 log (1/4)c)2 log (2/3)d) 2 log 2Correct answer is option 'D'. Can you explain this answer?
Question Description
What is the difference in pH for 1/3 and 2/3 stages of neutralisation of 0.1 M CH3COOH with 0.1 M NaOH?a)– 2 log 3b)2 log (1/4)c)2 log (2/3)d) 2 log 2Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What is the difference in pH for 1/3 and 2/3 stages of neutralisation of 0.1 M CH3COOH with 0.1 M NaOH?a)– 2 log 3b)2 log (1/4)c)2 log (2/3)d) 2 log 2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the difference in pH for 1/3 and 2/3 stages of neutralisation of 0.1 M CH3COOH with 0.1 M NaOH?a)– 2 log 3b)2 log (1/4)c)2 log (2/3)d) 2 log 2Correct answer is option 'D'. Can you explain this answer?.
What is the difference in pH for 1/3 and 2/3 stages of neutralisation of 0.1 M CH3COOH with 0.1 M NaOH?a)– 2 log 3b)2 log (1/4)c)2 log (2/3)d) 2 log 2Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What is the difference in pH for 1/3 and 2/3 stages of neutralisation of 0.1 M CH3COOH with 0.1 M NaOH?a)– 2 log 3b)2 log (1/4)c)2 log (2/3)d) 2 log 2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the difference in pH for 1/3 and 2/3 stages of neutralisation of 0.1 M CH3COOH with 0.1 M NaOH?a)– 2 log 3b)2 log (1/4)c)2 log (2/3)d) 2 log 2Correct answer is option 'D'. Can you explain this answer?.
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