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One mole of an ideal monoatomic gas expands isothermally against constant external pressure of 1 atm from initial volume of 1L to a state where its final pressure becomes equal to external pressure. If initial temperature of gas is 300 K then total entropy change of system in the above process is :[R = 0.082 L atm mol–1 K–1 = 8.3 J mol–1K–1].a)0b)R ln (24.6)c)R ln (2490)d)Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about One mole of an ideal monoatomic gas expands isothermally against constant external pressure of 1 atm from initial volume of 1L to a state where its final pressure becomes equal to external pressure. If initial temperature of gas is 300 K then total entropy change of system in the above process is :[R = 0.082 L atm mol–1 K–1 = 8.3 J mol–1K–1].a)0b)R ln (24.6)c)R ln (2490)d)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One mole of an ideal monoatomic gas expands isothermally against constant external pressure of 1 atm from initial volume of 1L to a state where its final pressure becomes equal to external pressure. If initial temperature of gas is 300 K then total entropy change of system in the above process is :[R = 0.082 L atm mol–1 K–1 = 8.3 J mol–1K–1].a)0b)R ln (24.6)c)R ln (2490)d)Correct answer is option 'B'. Can you explain this answer?.

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Here you can find the meaning of One mole of an ideal monoatomic gas expands isothermally against constant external pressure of 1 atm from initial volume of 1L to a state where its final pressure becomes equal to external pressure. If initial temperature of gas is 300 K then total entropy change of system in the above process is :[R = 0.082 L atm mol–1 K–1 = 8.3 J mol–1K–1].a)0b)R ln (24.6)c)R ln (2490)d)Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of One mole of an ideal monoatomic gas expands isothermally against constant external pressure of 1 atm from initial volume of 1L to a state where its final pressure becomes equal to external pressure. If initial temperature of gas is 300 K then total entropy change of system in the above process is :[R = 0.082 L atm mol–1 K–1 = 8.3 J mol–1K–1].a)0b)R ln (24.6)c)R ln (2490)d)Correct answer is option 'B'. Can you explain this answer?, a detailed solution for One mole of an ideal monoatomic gas expands isothermally against constant external pressure of 1 atm from initial volume of 1L to a state where its final pressure becomes equal to external pressure. If initial temperature of gas is 300 K then total entropy change of system in the above process is :[R = 0.082 L atm mol–1 K–1 = 8.3 J mol–1K–1].a)0b)R ln (24.6)c)R ln (2490)d)Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of One mole of an ideal monoatomic gas expands isothermally against constant external pressure of 1 atm from initial volume of 1L to a state where its final pressure becomes equal to external pressure. If initial temperature of gas is 300 K then total entropy change of system in the above process is :[R = 0.082 L atm mol–1 K–1 = 8.3 J mol–1K–1].a)0b)R ln (24.6)c)R ln (2490)d)Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice One mole of an ideal monoatomic gas expands isothermally against constant external pressure of 1 atm from initial volume of 1L to a state where its final pressure becomes equal to external pressure. If initial temperature of gas is 300 K then total entropy change of system in the above process is :[R = 0.082 L atm mol–1 K–1 = 8.3 J mol–1K–1].a)0b)R ln (24.6)c)R ln (2490)d)Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.