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In a mixture of gases, the volume content of a gas is 0.09% at stp ,then what is the no. of molecules of gas in 3litre of mixture , my mole concept is very weak so plzz help me with this question ,btw its answer is 7.2 × 10 to the power 19
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In a mixture of gases, the volume content of a gas is 0.09% at stp ,th...
Volume of that gas =. 09/100 x3=27x 10^-4 liter (as given percent) 22.4 l =1mole1l=1/22.4 moleMoles of gas =(27 X 10^-4)/22.4After simplifying =1.205 x10^-4 molesMultiple with avagadro number to get number of molecule 1.205x10^-4 x Na=7.2x 10^19 molecules
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In a mixture of gases, the volume content of a gas is 0.09% at stp ,th...
Calculation of Number of Molecules in a Mixture of Gases

Given Data:
- Volume content of gas = 0.09%
- Volume of the mixture = 3 liters
- Answer: 7.2 × 10^19 molecules

Steps to Solve:
- **Determine the Volume of the Gas:**
- Volume of gas = Volume of mixture x Volume content of gas
- Volume of gas = 3 liters x 0.09% = 0.0027 liters
- **Convert Volume to Number of Molecules:**
- Number of moles = Volume of gas / 22.4 L (1 mole of gas at STP)
- Number of moles = 0.0027 / 22.4 = 0.00012054 moles
- **Calculate the Number of Molecules:**
- Number of molecules = Number of moles x Avogadro's number
- Number of molecules = 0.00012054 x 6.022 x 10^23
- Number of molecules = 7.2 x 10^19
Therefore, the number of molecules in 3 liters of the gas mixture is 7.2 × 10^19.
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In a mixture of gases, the volume content of a gas is 0.09% at stp ,then what is the no. of molecules of gas in 3litre of mixture , my mole concept is very weak so plzz help me with this question ,btw its answer is 7.2 × 10 to the power 19
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