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A projectile is projected at an angle θ(> 45°) with initial speed u. The time t at which magnitude of vertical component of its velocity is equal to magnitude of horizontal component of its velocity, isa)t= (u/g)(sin2 θ - cos2 θ)b)t = (u/g)(sinθ - cosθ)c)t = (u/g)(cosθ - sinθ)d)t = (u/g)(cosθ + sinθ)Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A projectile is projected at an angle θ(> 45°) with initial speed u. The time t at which magnitude of vertical component of its velocity is equal to magnitude of horizontal component of its velocity, isa)t= (u/g)(sin2 θ - cos2 θ)b)t = (u/g)(sinθ - cosθ)c)t = (u/g)(cosθ - sinθ)d)t = (u/g)(cosθ + sinθ)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A projectile is projected at an angle θ(> 45°) with initial speed u. The time t at which magnitude of vertical component of its velocity is equal to magnitude of horizontal component of its velocity, isa)t= (u/g)(sin2 θ - cos2 θ)b)t = (u/g)(sinθ - cosθ)c)t = (u/g)(cosθ - sinθ)d)t = (u/g)(cosθ + sinθ)Correct answer is option 'B'. Can you explain this answer?.

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Here you can find the meaning of A projectile is projected at an angle θ(> 45°) with initial speed u. The time t at which magnitude of vertical component of its velocity is equal to magnitude of horizontal component of its velocity, isa)t= (u/g)(sin2 θ - cos2 θ)b)t = (u/g)(sinθ - cosθ)c)t = (u/g)(cosθ - sinθ)d)t = (u/g)(cosθ + sinθ)Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A projectile is projected at an angle θ(> 45°) with initial speed u. The time t at which magnitude of vertical component of its velocity is equal to magnitude of horizontal component of its velocity, isa)t= (u/g)(sin2 θ - cos2 θ)b)t = (u/g)(sinθ - cosθ)c)t = (u/g)(cosθ - sinθ)d)t = (u/g)(cosθ + sinθ)Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A projectile is projected at an angle θ(> 45°) with initial speed u. The time t at which magnitude of vertical component of its velocity is equal to magnitude of horizontal component of its velocity, isa)t= (u/g)(sin2 θ - cos2 θ)b)t = (u/g)(sinθ - cosθ)c)t = (u/g)(cosθ - sinθ)d)t = (u/g)(cosθ + sinθ)Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A projectile is projected at an angle θ(> 45°) with initial speed u. The time t at which magnitude of vertical component of its velocity is equal to magnitude of horizontal component of its velocity, isa)t= (u/g)(sin2 θ - cos2 θ)b)t = (u/g)(sinθ - cosθ)c)t = (u/g)(cosθ - sinθ)d)t = (u/g)(cosθ + sinθ)Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A projectile is projected at an angle θ(> 45°) with initial speed u. The time t at which magnitude of vertical component of its velocity is equal to magnitude of horizontal component of its velocity, isa)t= (u/g)(sin2 θ - cos2 θ)b)t = (u/g)(sinθ - cosθ)c)t = (u/g)(cosθ - sinθ)d)t = (u/g)(cosθ + sinθ)Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.