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In ydse the two slits are illuminated by light of wavelength 5890 A and the distance between the fringes obtained on the screen is 0.2 degree . tye whole apparatus is immersed in water then find the angular fringe width?
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In ydse the two slits are illuminated by light of wavelength 5890 A an...
The angular width is given by wavelength divided by width of the slit.Thus the angular width is directly proportional to the wavelength. wavelength in water is equal to refractive index times wavelength in air.The refractive index of water is 1.33. Hence new angular width will be equal to 1.33 X 0.2.
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In ydse the two slits are illuminated by light of wavelength 5890 A an...
Introduction:
In Young's double-slit experiment, a beam of light passes through two narrow slits, creating an interference pattern on a screen. The distance between the fringes obtained on the screen is known as the fringe width. When the apparatus is immersed in a medium like water, the wavelength of light changes due to the change in the refractive index of the medium. In this scenario, we need to calculate the angular fringe width.
Given:
- Wavelength of light in air: 5890 Å (angstroms)
- Distance between fringes on the screen: 0.2°
Calculating the Angular Fringe Width:
1. Convert the wavelength from angstroms to meters:
- 1 Å = 1 x 10^-10 m
- Therefore, the wavelength in meters = 5890 x 10^-10 m = 589 x 10^-9 m
2. Calculate the angular fringe width:
- Angular fringe width (θ) = Fringe width (y) / Distance from the slits to the screen (D)
3. Convert the angular fringe width to radians:
- 1° = π/180 radians
- Therefore, the angular fringe width in radians = (0.2°) x (π/180) radians
4. Substitute the given values into the formula:
- Angular fringe width = (0.2°) x (π/180) radians
5. Calculate the final result:
- Angular fringe width = 0.0034906585 radians
Conclusion:
The angular fringe width, when the apparatus is immersed in water, is approximately 0.0034906585 radians. This value represents the angular distance between adjacent fringes in the interference pattern observed on the screen.
In Young's double-slit experiment, a beam of light passes through two narrow slits, creating an interference pattern on a screen. The distance between the fringes obtained on the screen is known as the fringe width. When the apparatus is immersed in a medium like water, the wavelength of light changes due to the change in the refractive index of the medium. In this scenario, we need to calculate the angular fringe width.
Given:
- Wavelength of light in air: 5890 Å (angstroms)
- Distance between fringes on the screen: 0.2°
Calculating the Angular Fringe Width:
1. Convert the wavelength from angstroms to meters:
- 1 Å = 1 x 10^-10 m
- Therefore, the wavelength in meters = 5890 x 10^-10 m = 589 x 10^-9 m
2. Calculate the angular fringe width:
- Angular fringe width (θ) = Fringe width (y) / Distance from the slits to the screen (D)
3. Convert the angular fringe width to radians:
- 1° = π/180 radians
- Therefore, the angular fringe width in radians = (0.2°) x (π/180) radians
4. Substitute the given values into the formula:
- Angular fringe width = (0.2°) x (π/180) radians
5. Calculate the final result:
- Angular fringe width = 0.0034906585 radians
Conclusion:
The angular fringe width, when the apparatus is immersed in water, is approximately 0.0034906585 radians. This value represents the angular distance between adjacent fringes in the interference pattern observed on the screen.
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In ydse the two slits are illuminated by light of wavelength 5890 A and the distance between the fringes obtained on the screen is 0.2 degree . tye whole apparatus is immersed in water then find the angular fringe width?
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In ydse the two slits are illuminated by light of wavelength 5890 A and the distance between the fringes obtained on the screen is 0.2 degree . tye whole apparatus is immersed in water then find the angular fringe width? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In ydse the two slits are illuminated by light of wavelength 5890 A and the distance between the fringes obtained on the screen is 0.2 degree . tye whole apparatus is immersed in water then find the angular fringe width? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In ydse the two slits are illuminated by light of wavelength 5890 A and the distance between the fringes obtained on the screen is 0.2 degree . tye whole apparatus is immersed in water then find the angular fringe width?.
In ydse the two slits are illuminated by light of wavelength 5890 A and the distance between the fringes obtained on the screen is 0.2 degree . tye whole apparatus is immersed in water then find the angular fringe width? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In ydse the two slits are illuminated by light of wavelength 5890 A and the distance between the fringes obtained on the screen is 0.2 degree . tye whole apparatus is immersed in water then find the angular fringe width? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In ydse the two slits are illuminated by light of wavelength 5890 A and the distance between the fringes obtained on the screen is 0.2 degree . tye whole apparatus is immersed in water then find the angular fringe width?.
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