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If 0.75 mole of an ideal gas is expanded isothermally at 27oC from 15 litres to 25 litres, then work done by the gas during this process is (R = 8.314J-K-1-mol-1)
- a)-894.2J
- b)-954.2J
- c)-1054.2J
- d)-1154.2J
Correct answer is option 'B'. Can you explain this answer?
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If 0.75 mole of an ideal gas is expanded isothermally at 27oC from 15 ...
Given:
n = 0.75 mol
T = 27°C = 300 K
Vi = 15 L
Vf = 25 L
R = 8.314 J/K/mol
To find: Work done by the gas during the isothermal expansion
Formula:
Work done by the gas during isothermal expansion = nRT ln(Vf/Vi)
Calculation:
ln(Vf/Vi) = ln(25/15) = ln(5/3)
nRT ln(Vf/Vi) = 0.75 × 8.314 × 300 × ln(5/3) = -954.2 J
Therefore, the work done by the gas during the isothermal expansion is -954.2 J, which is option (B).
n = 0.75 mol
T = 27°C = 300 K
Vi = 15 L
Vf = 25 L
R = 8.314 J/K/mol
To find: Work done by the gas during the isothermal expansion
Formula:
Work done by the gas during isothermal expansion = nRT ln(Vf/Vi)
Calculation:
ln(Vf/Vi) = ln(25/15) = ln(5/3)
nRT ln(Vf/Vi) = 0.75 × 8.314 × 300 × ln(5/3) = -954.2 J
Therefore, the work done by the gas during the isothermal expansion is -954.2 J, which is option (B).
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If 0.75 mole of an ideal gas is expanded isothermally at 27oC from 15 ...
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If 0.75 mole of an ideal gas is expanded isothermally at 27oC from 15 litres to 25 litres, then work done by the gas during this process is (R = 8.314J-K-1-mol-1)a)-894.2Jb)-954.2Jc)-1054.2Jd)-1154.2JCorrect answer is option 'B'. Can you explain this answer?
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If 0.75 mole of an ideal gas is expanded isothermally at 27oC from 15 litres to 25 litres, then work done by the gas during this process is (R = 8.314J-K-1-mol-1)a)-894.2Jb)-954.2Jc)-1054.2Jd)-1154.2JCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 0.75 mole of an ideal gas is expanded isothermally at 27oC from 15 litres to 25 litres, then work done by the gas during this process is (R = 8.314J-K-1-mol-1)a)-894.2Jb)-954.2Jc)-1054.2Jd)-1154.2JCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 0.75 mole of an ideal gas is expanded isothermally at 27oC from 15 litres to 25 litres, then work done by the gas during this process is (R = 8.314J-K-1-mol-1)a)-894.2Jb)-954.2Jc)-1054.2Jd)-1154.2JCorrect answer is option 'B'. Can you explain this answer?.
If 0.75 mole of an ideal gas is expanded isothermally at 27oC from 15 litres to 25 litres, then work done by the gas during this process is (R = 8.314J-K-1-mol-1)a)-894.2Jb)-954.2Jc)-1054.2Jd)-1154.2JCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 0.75 mole of an ideal gas is expanded isothermally at 27oC from 15 litres to 25 litres, then work done by the gas during this process is (R = 8.314J-K-1-mol-1)a)-894.2Jb)-954.2Jc)-1054.2Jd)-1154.2JCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 0.75 mole of an ideal gas is expanded isothermally at 27oC from 15 litres to 25 litres, then work done by the gas during this process is (R = 8.314J-K-1-mol-1)a)-894.2Jb)-954.2Jc)-1054.2Jd)-1154.2JCorrect answer is option 'B'. Can you explain this answer?.
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