All questions of Transient Analysis in AC & DC Circuits for Electrical Engineering (EE) Exam

The output in response to a unit step input for a particular continuous control system is c(t)= 1-e-t. What is the delay time Td?
  • a)
    0.36
  • b)
    0.18
  • c)
    0.693
  • d)
    0.289
Correct answer is option 'C'. Can you explain this answer?

Pooja Patel answered
The output is given as a function of time. The final value of the output is limn->∞c(t) = 1; .
Hence Td (at 50% of the final value) is the solution of 0.5 = 1-e-Td, and is equal to ln 2 or 0.693 sec.

In an R-L circuit connected to an alternating sinusoidal voltage, size of transient current primarily depends on:
  • a)
    the voltage frequency
  • b)
    the circuit impedance
  • c)
    the instant in the voltage cycle at which circuit is closed
  • d)
    the peak value of steady-state current
Correct answer is option 'C'. Can you explain this answer?

Aarya Basu answered
Introduction:
In an R-L circuit connected to an alternating sinusoidal voltage, the transient current refers to the initial current that flows through the circuit when it is first closed. This transient current occurs before the system reaches its steady-state behavior. The size of this transient current primarily depends on the instant in the voltage cycle at which the circuit is closed.

Explanation:
When an R-L circuit is connected to an alternating sinusoidal voltage, the voltage across the circuit undergoes continuous changes over time. This sinusoidal voltage can be represented by a waveform that oscillates between positive and negative peaks. The transient current occurs during the initial phase of the circuit when the voltage is changing.

Effect of instant in the voltage cycle:
The instant in the voltage cycle at which the circuit is closed plays a crucial role in determining the size of the transient current. This is because the voltage waveform is not static, and its value at a specific instant determines the instantaneous current flow.

Explanation with examples:
1. If the circuit is closed at the peak of the positive half-cycle of the voltage waveform, the voltage is at its maximum value. At this instant, the rate of change of voltage is zero, resulting in a smaller transient current. This is because the inductor opposes changes in current, and when the voltage is at its maximum, the inductor tends to resist any further increase in current.

2. On the other hand, if the circuit is closed at the zero-crossing point of the voltage waveform, the rate of change of voltage is maximum. In this case, the inductor has a maximum opposition to the change in current, resulting in a larger transient current.

Conclusion:
Therefore, the instant in the voltage cycle at which the circuit is closed determines the magnitude of the transient current in an R-L circuit connected to an alternating sinusoidal voltage. Closing the circuit at the peak of the positive half-cycle results in a smaller transient current, while closing it at the zero-crossing point leads to a larger transient current. It is important to consider this factor when analyzing the behavior of R-L circuits in transient conditions.

The network function s^2 + 10s + 24/s2 + 8s + 15 represents
  • a)
    RC impedance
  • b)
    RL impedance
  • c)
    LC impedance
  • d)
    None of the mentioned
Correct answer is option 'D'. Can you explain this answer?

The given network function is s^2 + 10s + 24/s^2 + 8s + 15. This represents neither an RC impedance nor an RL impedance nor an LC impedance. Let's analyze the given network function in detail to understand why it does not represent any of these impedances.

1. RC Impedance:
An RC impedance is represented by a transfer function in the form of 1/(RCs + 1), where R is the resistance and C is the capacitance. In the given network function, we do not have a term in the form of RCs, so it cannot represent an RC impedance.

2. RL Impedance:
An RL impedance is represented by a transfer function in the form of RL/(RLs + 1), where R is the resistance and L is the inductance. Similarly, in the given network function, we do not have a term in the form of RLs, so it cannot represent an RL impedance.

3. LC Impedance:
An LC impedance is represented by a transfer function in the form of 1/(LCs^2 + RCs + 1), where L is the inductance, C is the capacitance, and R is the resistance. In the given network function, we do not have a term in the form of LCs^2, so it cannot represent an LC impedance.

4. None of the mentioned:
Based on the analysis above, we can conclude that the given network function does not fit into any of the mentioned categories, i.e., RC impedance, RL impedance, or LC impedance. Therefore, the correct answer is option 'D' - None of the mentioned.

In summary, the given network function does not represent any of the mentioned impedances (RC, RL, or LC). It is important to understand the different forms of transfer functions for these impedances to accurately identify and categorize them.

In Reciprocity Theorem, which of the following ratios is considered?
  • a)
    Voltage to current
  • b)
    Current to current
  • c)
    Voltage to voltage
  • d)
    No ratio is considered
Correct answer is option 'A'. Can you explain this answer?

Saranya Mishra answered
Reciprocity Theorem in Electrical Engineering
The Reciprocity Theorem in electrical engineering states that in a linear bilateral network, the ratio of voltage to current at one point in the network is equal to the ratio of current to voltage at another point in the network.

Ratio Considered in Reciprocity Theorem
In the Reciprocity Theorem, the ratio considered is the ratio of voltage to current. This means that the voltage at one point in the network divided by the current at that same point is equal to the current at another point in the network divided by the voltage at that point.
Therefore, the correct answer is option 'A) Voltage to current'.
By understanding and applying the Reciprocity Theorem in electrical network analysis, engineers can simplify calculations and determine the relationship between different points in a network more efficiently.
Overall, the Reciprocity Theorem plays a crucial role in analyzing electrical networks and understanding the interrelationship between voltage and current at different points within the network.

The circuit shown in figure was at steady state for t < 0 with switch at position ‘A’. The switch is thrown to position ‘B’ at time t = 0. The voltage across the 10 ohm resistor at time t = 0+ is ________V.
    Correct answer is between '-31,-29'. Can you explain this answer?

    At t < 0 the circuit was in steady state and switch at ‘A’
    The current drawn by circuit i
    Current through the inductor I(0-)
    Immediately after t > 0 the circuit will be the current through Inductor I(0-) = I(0+)
    at t= 0+
    V = I(0+) × 10Ω
    = -3 × 10 = -30V

    Time constant in an R-L circuit is defined as the time taken by the current to become
    • a)
      36.8% of the final value
    • b)
      36.8% of the initial value
    • c)
      63.2% of the final value
    • d)
      None of these
    Correct answer is option 'C'. Can you explain this answer?

    Pooja Patel answered
    An L-R Series Circuit consists basically of an inductor of inductance L, connected in series with a resistor of resistance R. The resistance “R” is the resistive value of the wire turns or loops that go into making up the inductors coil.
    Time constant (τ) –
    The time constant is defined as the time required for the circuit to reach 63.2% of the final value (steady-state value).

    Assertion (A.: It is observed that step function is first derivative of a ramp function and impulse function is first derivative of a step function.
    Reason (R): From the derived time response expression it is concluded that the output time response also follows the same sequence as that of input functions.
    • a)
      Both A and R are true and R is the correct explanation of A
    • b)
      Both A and R are true but R is not correct explanation of A
    • c)
      Both A is True but R is false
    • d)
      Both A is False but R is true
    Correct answer is option 'B'. Can you explain this answer?

    Partho Saha answered
    Understanding the Assertion and Reason
    The assertion (A) states that a step function is the first derivative of a ramp function, and an impulse function is the first derivative of a step function. This statement is indeed true in the context of signal processing.
    Key Points of Assertion (A):
    - Ramp Function: A ramp function increases linearly over time. Its derivative represents the rate of change.
    - Step Function: The step function is constant (zero) until a specific point, where it jumps to a value. The derivative of a ramp function is a step function, indicating an instantaneous change.
    - Impulse Function: An impulse function is a theoretical function that represents an instantaneous spike in value. The derivative of a step function, which changes at a single point, is an impulse function.
    Examining the Reason (R)
    The reason (R) posits that the output time response follows the same sequence as that of the input functions based on the derived time response expression. This statement is also true but does not directly explain the assertion.
    Key Points of Reason (R):
    - Output Time Response: It is derived from the system's response to various input functions.
    - Sequence of Functions: While the time response does follow the sequence of input functions, this does not clarify why the relationships between ramp, step, and impulse functions exist.
    Conclusion
    - Correctness of A and R: Both A and R are true statements. However, R does not explain A adequately.
    - Option B: Thus, the correct answer is option 'B': Both A and R are true, but R is not the correct explanation of A.

    In the circuit shown, the voltage VIN(t) is described by:
    where t is in seconds. The time (in seconds) at which the current I in the circuit will reach the value 2 Amperes is ________.
      Correct answer is between '0.3,0.4'. Can you explain this answer?

      Concept:
      Calculation:
      Taking Laplace to transform with given conditions
      Applying KCL at V(s) node:
      Taking the inverse Laplace transform, we get:
      i(t) = 5(1 – e-3t/2)
      Given, at t = t0
      i = 2 A
      2 = 5 (1 – e-3t/2)
      t = 0.3405 sec

      Consider a system with transfer function G(s) = s + 6/Ks2 + s + 6. Its damping ratio will be 0.5 when the values of k is:
      • a)
        2/6
      • b)
        3
      • c)
        1/6
      • d)
        6
      Correct answer is option 'C'. Can you explain this answer?

      Uday Saini answered
      Transfer Function

      The given transfer function is:
      G(s) = s^6 / (Ks^2 + s^6)

      Damping Ratio

      The damping ratio, denoted by ζ (zeta), is a parameter that characterizes the behavior of a second-order linear system. It determines the response of the system to a step input and provides information about the system's stability and transient response.

      Definition of Damping Ratio

      The damping ratio is defined as the ratio of the actual damping coefficient to the critical damping coefficient. Mathematically, it is expressed as:
      ζ = c / c_critical

      where c is the actual damping coefficient and c_critical is the critical damping coefficient.

      Finding the Damping Ratio

      To find the damping ratio of the given transfer function G(s), we need to determine the actual damping coefficient c and the critical damping coefficient c_critical.

      1. Actual Damping Coefficient (c):
      The actual damping coefficient can be determined by examining the denominator of the transfer function. In this case, the denominator is Ks^2 + s^6. Since the denominator is a quadratic polynomial, we can compare it with the general form of a second-order system's characteristic equation:
      s^2 + 2ζω_ns + ω_n^2

      Comparing the coefficients, we can see that the actual damping coefficient c is equal to 2ζω_n, where ω_n is the natural frequency.

      2. Critical Damping Coefficient (c_critical):
      The critical damping coefficient corresponds to the case where the system is critically damped. In this case, the damping ratio is equal to 1. For a critically damped system, the damping coefficient c_critical is given by:
      c_critical = 2√(K)

      Equating Damping Coefficients

      Now, we can equate the actual damping coefficient c to the critical damping coefficient c_critical and solve for the damping ratio ζ.

      2ζω_n = 2√(K)

      Dividing both sides by 2ω_n, we get:
      ζ = √(K) / ω_n

      In the given transfer function, the numerator is s^6 and the denominator is Ks^2 + s^6. The natural frequency ω_n can be determined by finding the square root of the coefficient of s^2 in the denominator.

      Since the damping ratio is given as 0.5, we can substitute this value into the equation for ζ and solve for K.

      0.5 = √(K) / ω_n

      Squaring both sides, we get:
      0.25 = K / (K + 1)

      Simplifying the equation, we have:
      0.25(K + 1) = K

      Expanding the equation, we get:
      0.25K + 0.25 = K

      Rearranging the terms, we get:
      0.75K = 0.25

      Dividing both sides by 0.75, we get:
      K = 1/3

      Therefore, the value of K for which the damping ratio is 0.5 is 1/3, which corresponds to option C.

      Calculate the peak value of the source voltage (in V) if the root-mean square voltage across the resistor and inductor in a series RL circuit is 13 V and 12 V, respectively. 
      • a)
        1
      • b)
        17.68
      • c)
        25
      • d)
        3
      Correct answer is option 'C'. Can you explain this answer?

      Pooja Patel answered
      Concept:
      Source voltage RMS value of a series RL circuit will be;
      Vrms = √(VR2 + VL2)
      Where;
      Vrms → Source voltage in RMS.
      VR  → Voltage across resistance in RMS.
      VL  → Voltage across inductor in RMS.
      RMS voltage = Peak voltage/√(2) 
      Calculation:
      Given;
      VR = 13 V
      VL  = 12 V
      Vrms = √(VR2 + VL2) = √(132 + 122) = 17.69
      Peak value of the source voltage = Vrms × √2 = 25.01 V ≈ 25 V

      In the circuit shown below, switch S1 and S2 are in open and close position respectively for long time. At t = t0, switch S1 is closed and switch S2 is opened. What would be the current through R1 immediately after the transition of switches?
      • a)
        0 mA
      • b)
        1 mA
      • c)
        0.5 mA
      • d)
        2 mA
      Correct answer is option 'B'. Can you explain this answer?

      Concept:
      A capacitor doesn’t allow a sudden change in voltage, i.e. Vc(0+) = Vc(0-).
      Similarly, an inductor doesn’t allow a sudden change in current, i.e. iL(0+) = iL(0-)
      Calculation:
      The circuit for t = t0- is as shown,
      Vc(t0-) = 5V as shown above,
      At t = t0+, the circuit will be as shown, in which the capacitor will be at 5V (∵ Vc(0+) = Vc(0-))
      To find the voltage at node ‘x’, we apply KCL to get,
      Now the required current through R1 = 5KΩ, immediately after the transition of switches is
       

      A switch is connected in between a 12 V battery and an uncharged capacitor and a 1 KΩ resistor. At the time instant when the switch is closed, the voltage across the capacitor is:
      • a)
        6 V
      • b)
        12 V
      • c)
        0 V
      • d)
        24 V
      Correct answer is option 'C'. Can you explain this answer?

      Ameya Nambiar answered
      Ω resistor, as shown in the circuit below:

      Battery (+12V) ---[Switch]--- [Capacitor] ---[Resistor]--- Ground

      When the switch is closed, the capacitor begins to charge. The time constant of this RC circuit is given by the product of the resistance and the capacitance (RC). In this case, the time constant is 1KΩ * C, where C is the capacitance in farads.

      The time constant determines how quickly the capacitor charges. Specifically, it is the time it takes for the capacitor to charge to approximately 63.2% of its final voltage.

      If we want to calculate the time it takes for the capacitor to charge to 99% of its final voltage, we can use the formula:

      t = -RC * ln(1 - 0.99)

      In this case, the final voltage is 12V, so we can plug in the values:

      t = -1KΩ * C * ln(1 - 0.99)

      To calculate the time it takes for the capacitor to charge to 99% of its final voltage, we need to know the capacitance value. Can you provide the capacitance value?

      A series RL circuit having a resistance of 20 Ω and inductance of 8 H is connected to a DC voltage source of 120 V at t = 0. The current in the circuit at t = 0.6 sec is
      • a)
        0 A
      • b)
        2.33 A
      • c)
        4.66 A
      • d)
        1 A
      Correct answer is option 'C'. Can you explain this answer?

      Swati Tiwari answered

      Calculation of Current in the Circuit at t = 0.6 sec

      Given Data:
      Resistance (R) = 20 Ω
      Inductance (L) = 8 H
      DC voltage source = 120 V
      Time (t) = 0.6 sec

      Formula Used:
      The current in a series RL circuit can be calculated using the formula:
      i(t) = (V/R) * (1 - e^(-Rt/L))

      Calculation:
      Substitute the given values into the formula:
      i(0.6) = (120/20) * (1 - e^(-20*0.6/8))
      i(0.6) = 6 * (1 - e^(-1.5))

      Now, calculate the value of e^(-1.5):
      e^(-1.5) ≈ 0.2231

      Substitute the value back into the formula:
      i(0.6) = 6 * (1 - 0.2231)
      i(0.6) = 6 * 0.7769
      i(0.6) ≈ 4.66 A

      Therefore, the current in the circuit at t = 0.6 sec is approximately 4.66 A, which corresponds to option 'C'.

      The peak percentage overshoot of the closed loop system is :
      • a)
        5.0%
      • b)
        10.0%
      • c)
        16.3%
      • d)
        1.63%
      Correct answer is option 'C'. Can you explain this answer?

      Pooja Patel answered
      C(s)/R(s) = 1/s2+s+1
      C(s)/R(s) = w/ws+ 2Gws + w2
      Compare both the equations,
      w = 1 rad/sec
      2Gw = 1
      Mp = 16.3 %

      In the figure shown, the ideal switch has been open for a long time.
      If it is closed at t = 0, then the magnitude of the current (in mA) through the 4kΩ resistor at t = 0+ is _______.
        Correct answer is between '1.2,1.3'. Can you explain this answer?

        Pooja Patel answered
        Concept:
        Under steady-state:
        • When a capacitor, is present with a D.C supply, it behaves as an open circuit.
        • When an inductor is present with D.C supply, it behaves as a short circuit
        At t = 0+ :
        Inductor replace with current source IL (0+) = IL (0-)
        The inductor does NOT allow the sudden change in current”
        The capacitor is replaced with the voltage source
        Vc (0+) = Vc (0-)
        The capacitor does NOT allow the sudden change in voltage.
        Calculation:
        The circuit at t = 0-
        Vc (0-) = 5 V
        Circuit at t = 0+
        I = 5/4 = 1.25mA

        The network function (s2 + 4s)/(s + 1)(s + 2)(s + 3) represents
        • a)
          RC impedance
        • b)
          RL impedance
        • c)
          LC impedance
        • d)
          None of the mentioned
        Correct answer is option 'D'. Can you explain this answer?

        Uday Saini answered
        Explanation:

        Network Function Analysis:
        The given network function is in the form of a transfer function representing a system in the Laplace domain. It is a ratio of polynomials in the Laplace variable 's'.

        RC, RL, and LC Impedance:
        The network function (s^2 + 4s) / ((s + 1)(s + 2)(s + 3)) does not directly represent an RC, RL, or LC impedance. It is a transfer function that describes the input-output relationship of a system, rather than an impedance characteristic.

        Impedance Representation:
        Impedance characteristics are typically represented by expressions involving complex variables such as s or jω, where ω is the frequency. The given network function does not have the form of an impedance expression involving resistors, capacitors, or inductors.

        Conclusion:
        Therefore, the correct answer is option 'D' - None of the mentioned. The given network function is a transfer function and does not directly correspond to an RC, RL, or LC impedance. It describes the system's dynamics in the Laplace domain rather than an impedance characteristic.

        For the system 2/s+1, the approximate time taken for a step response to reach 98% of its final value is:
        • a)
          1s
        • b)
          2s
        • c)
          4s
        • d)
          8s
        Correct answer is option 'C'. Can you explain this answer?

        Kalyan Patel answered
        To determine the approximate time taken for a step response to reach 98% of its final value for the given system, we need to analyze the system's transfer function.

        Transfer function:
        The transfer function of the given system is 2/s, where s represents the Laplace variable.

        Step response:
        A step response is the output of a system when a unit step input is applied.

        Time taken for a step response to reach 98% of its final value:
        To determine the time taken for a step response to reach 98% of its final value, we need to find the time at which the output reaches 0.98 times the final value.

        Approximation using time constant:
        In a first-order system, the time constant is defined as the time taken for the output to reach 63.2% of its final value. For a step response, the time constant (τ) is given by τ = 1/(ζωn), where ζ is the damping ratio and ωn is the natural frequency.

        In this case, the transfer function is 2/s, which represents a first-order system. Since the damping ratio and natural frequency are not given, we'll assume a critically damped system (ζ = 1) for simplicity.

        Time constant (τ) = 1/(1 × ωn) = 1/ωn

        Approximation using time constant:
        To approximate the time taken for the step response to reach 98% of its final value, we can use the 2% settling time formula for a second-order system.

        Approximate settling time = 4/ζωn

        For a critically damped system (ζ = 1), the approximate settling time is 4/ωn.

        Since the system in question is a first-order system, we can approximate the settling time by doubling the time constant (τ).

        Approximate settling time ≈ 2τ

        In this case, the time constant (τ) is 1/ωn.

        Approximate settling time ≈ 2 × (1/ωn) = 2/ωn

        Therefore, the approximate time taken for the step response to reach 98% of its final value is 2/ωn.

        Comparing options:
        From the given options, option 'C' states that the approximate time taken is 4s.

        Since we do not have any information about the natural frequency (ωn) of the system, we cannot determine the exact time taken. However, option 'C' can be considered a reasonable approximation based on the assumption of a critically damped system.

        Therefore, option 'C' is the correct answer.

        The unit step response of a second order system is = 1-e-5t-5te-5t . Consider the following statements:
        1. The under damped natural frequency is 5 rad/s.
        2. The damping ratio is 1.
        3. The impulse response is 25te-5t.
        Which of the statements given above are correct?
        • a)
          Only 1 and 2
        • b)
          Only 2 and 3
        • c)
          Only 1 and 3
        • d)
          1,2 and 3
        Correct answer is option 'D'. Can you explain this answer?

        Srestha Gupta answered
        Explanation:

        The given unit step response of a second-order system is:

        y(t) = 1 - e^(-5t) - 5t * e^(-5t)

        To analyze the system, we need to find the natural frequency and the damping ratio.

        1. The underdamped natural frequency is 5 rad/s:

        To find the natural frequency, we need to find the coefficient of the exponential term in the unit step response. In this case, the coefficient is -5.

        Natural frequency (ωn) = sqrt(coefficient) = sqrt(-5) = √5

        So, the given statement is correct.

        2. The damping ratio is 1:

        To find the damping ratio, we need to find the coefficient of the linear term in the unit step response. In this case, the coefficient is -5t.

        The damping ratio (ζ) is given by the formula:

        ζ = coefficient / (2 * natural frequency) = (-5) / (2 * √5) = -√5 / 2

        The given statement is incorrect. The damping ratio is not 1.

        3. The impulse response is 25te^(-5t):

        To find the impulse response, we need to differentiate the unit step response with respect to time.

        Differentiating the unit step response, we get:

        y'(t) = 5e^(-5t) - 5e^(-5t) - 5te^(-5t) + 25te^(-5t)

        Simplifying, we get:

        y'(t) = 5te^(-5t)

        Comparing this with the given impulse response, we can see that they are the same.

        So, the given statement is correct.

        Therefore, the correct statements are:

        1. The underdamped natural frequency is 5 rad/s.
        3. The impulse response is 25te^(-5t).

        Hence, the correct answer is option D) 1, 2, and 3.

        Calculate the power factor of a series RL circuit having the conductance of 30 Siemens and the susceptance of 40 Siemens. 
        • a)
          0.2 
        • b)
          0.4
        • c)
          0.6
        • d)
          0.8
        Correct answer is option 'C'. Can you explain this answer?

        Pooja Patel answered
        Concept:
        The admittance triangle is also represented similarly to the impedance triangle. As the impedance (Z) of the circuit has two rectangular components, resistance (R) and reactance (X).
        Similarly, admittance (Y) also has two components, conductance (G) and susceptance (B).
        Then Power factor will be:
        PF = cosθ  = G/Y
        Calculation:
        Given;
        G = 30 siemens
        B = 40 Siemens
        Y = √(302 + 402) = 50 Siemens
        PF = cosθ = 30/50 = 0.6

        What is the phase angle between the capacitor current and the applied voltage in a parallel RC circuit?
        • a)
          90° 
        • b)
          0° 
        • c)
          45° 
        • d)
          180° 
        Correct answer is option 'A'. Can you explain this answer?

        Naroj Boda answered
        The phasor diagram is drawn as:
         
        1) There is no phase difference between the applied voltage and the voltage across R and C in parallel.
        2) The current through the resistive branch is in phase with the applied signal.
        3) But the current through the capacitive branch leads its voltage Vc by 90 degrees.
        .

        The network function (s + 1)(s + 4)/s(s + 2)(s + 5) represents
        • a)
          RC impedance
        • b)
          RL impedance
        • c)
          LC impedance
        • d)
          All of the mentioned
        Correct answer is option 'B'. Can you explain this answer?

        Mainak Pillai answered
        RL Impedance Representation:
        RL impedance refers to the impedance in a circuit that consists of a resistor and an inductor. The given network function can be represented as (s + 1)(s + 4)/s(s + 2)(s + 5).

        Analysis:
        1. The network function contains terms in the form of (s + a) where 'a' is a constant. These terms indicate poles in the system.
        2. The terms in the denominator indicate the roots of the characteristic equation that represent the natural response of the system.
        3. The presence of (s + 1)(s + 4) in the numerator suggests the presence of poles at s = -1 and s = -4.
        4. Poles at negative real values imply the existence of energy storage elements like inductors in the system.
        5. The absence of any term in the form of (s + b) where 'b' is a constant in the numerator indicates the absence of zeros in the system.

        Conclusion:
        Based on the analysis, the network function (s + 1)(s + 4)/s(s + 2)(s + 5) can be associated with an RL impedance. The presence of poles at negative real values (-1 and -4) suggests the involvement of energy storage elements like inductors, which aligns with the characteristics of RL impedance.

        The initial charge in the 1 F capacitor present in the circuit shown is zero. The energy in joules transferred from the DC source until steady state condition is reached equals _________. (Give the answer up to one decimal place.)
          Correct answer is between '99,101'. Can you explain this answer?

          Given circuit diagram:
          The above circuit can be redrawn as, (the above circuit forms a balanced bridge condition)
          The equivalent resistance of all the 5 Ω resistors is 5 Ω 
          Current in the circuit will be 
          i(t) = I e-4τ
          Time constant τ = RC = 5 secs
          Energy transferred from the DC source,
           

          In the circuit shown below, steady state was reached when the switch ‘s’ was open. The switch was closed at t = 0. Then initial value of the current through the capacitor 2C is?
          • a)
            0 A
          • b)
            1 A
          • c)
            2 A
          • d)
            3 A
          Correct answer is option 'C'. Can you explain this answer?

          At steady-state conditions, the capacitor acts as an open circuit, and the inductor acts as a short circuit.
          Now considering t = 0-,
          Now voltage across 4 Ω resistor is 12 V.
          Considering t = 0+
          By KCL, 
          i2c (0+) = 2 A
          The initial value of the current through the capacitor 2 C is 2 A.

          For the circuit shown in the figure, the value of  is _____ (in A/s)
            Correct answer is '-4'. Can you explain this answer?

            Pooja Patel answered
            At t = 0-, the circuit is as shown below.
            i(0) = 12 / 6 = 2A
            V(0-) = 12 V
            The inductor doesn’t allow the sudden change in current.
            I(0+) = i(0-) = 2 A
            Capacitor doesn’t allow the sudden change in voltage.
            V(0-) = V(0+) = 12 V
            At t = 0+, the circuit becomes,
            By applying KVL,
            -12 + 4(2) + 6(2) + VL(0+) = 0
            VL(0+) = -8 V
            Since  
             

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