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In amines ,the hybridisation state of N is:- a)sp
- b)sp2d
- c)sp2
- d)sp3
Correct answer is option 'D'. Can you explain this answer?
In amines ,the hybridisation state of N is:
a)
sp
b)
sp2d
c)
sp2
d)
sp3
|
Riya Banerjee answered |
Hybridisation of N in amine is sp3 with nitrogen having a one pair and 3 bond pair. Remember that amine is RR’R”N where R, R’ and R” may be alkyl or hydrogen.
- a)Sandmeyers reaction
- b)Gattermanns reaction
- c)Dehydrogenation reaction
- d)Esterification reaction
Correct answer is option 'B'. Can you explain this answer?
a)
Sandmeyers reaction
b)
Gattermanns reaction
c)
Dehydrogenation reaction
d)
Esterification reaction
|
Geetika Shah answered |
This reaction is called Gattermann reaction. In this reaction, Cl, Br and CN can be introduced into the benzene ring by simply treating diazonium salts with HCl, HBr, KCN. Respectively in presnce of copper powder instead of using Cu(I) salts.
Reduction of alkanenitriles with sodium and alcohol or LiAlH4 is called:- a)Wolf-Kishner reduction
- b)Rosenmund reduction
- c)Mendius reaction
- d)Catalytic reduction
Correct answer is option 'C'. Can you explain this answer?
Reduction of alkanenitriles with sodium and alcohol or LiAlH4 is called:
a)
Wolf-Kishner reduction
b)
Rosenmund reduction
c)
Mendius reaction
d)
Catalytic reduction
|
Nikita Singh answered |
The reaction is a Mendius reaction as because in this reaction the organic nitrile is reduced by nascent hydrogen(from sodium in ethanol) to a primary amine. (RCN+2H2=RCH2NH2).
where as LiAlH4 is a strong reducing agent and can be used as an abstract source of H neucophile.
where as LiAlH4 is a strong reducing agent and can be used as an abstract source of H neucophile.
Pyridine is less basic than triethylamine because:- a)Pyridine has aromatic character
- b)Nitrogen in pyridine is sp2 hybridized.
- c)Pyridine has a cyclic system.
- d)Lone pair of nitrogen in pyridine is delocalized.
Correct answer is option 'D'. Can you explain this answer?
Pyridine is less basic than triethylamine because:
a)
Pyridine has aromatic character
b)
Nitrogen in pyridine is sp2 hybridized.
c)
Pyridine has a cyclic system.
d)
Lone pair of nitrogen in pyridine is delocalized.
|
Om Desai answered |
Basicity of amines is due to availability of an unshared pair (lone pair) of electrons on nitrogen. This lone pair of electrons is available for the formation of a new bond with a proton or Lewis acid. Pyridine is less basic than triethylamine because lone pair of nitrogen in pyridine is delocalised.
Write the IUPAC name of the given compound.
- a)N-Methylethanamine
- b)Methylethanamine
- c)Ethylmethanamine
- d)N-Ethylmethanamine
Correct answer is option 'A'. Can you explain this answer?
Write the IUPAC name of the given compound.
a)
N-Methylethanamine
b)
Methylethanamine
c)
Ethylmethanamine
d)
N-Ethylmethanamine
|
|
Om Desai answered |
The correct answer is option A
The IUPAC name for the given compound is
N-Methylethanamine
N-Methylethanamine
Which of the following amine gives diazonium salt on reaction with HNO2?- a)(CH3)2NH
- b)CH3NH2
- c)C6H5NH2
- d)(CH3)3N
Correct answer is option 'C'. Can you explain this answer?
Which of the following amine gives diazonium salt on reaction with HNO2?
a)
(CH3)2NH
b)
CH3NH2
c)
C6H5NH2
d)
(CH3)3N
|
Mohit Rajpoot answered |
C6H5NH2 reacts with HNO2 to forms diazonium salts, the reaction are as follows,
C6H5NH2 + HNO2 ------> C6H5OH + H2O + N2
C6H5NH2 + HNO2 ------> C6H5OH + H2O + N2
The following reaction takes place in the presence of 
- a)NaOH/Pd
- b)H2/Pd
- c)HCl/Pd
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
The following reaction takes place in the presence of
a)
NaOH/Pd
b)
H2/Pd
c)
HCl/Pd
d)
None of these
|
Anaya Patel answered |
−NO2 group is reduced to –NH2 using H2/Pd.
When hypophosphorous acid is treated with diazonium salts, it is reduced to:- a)Arenes
- b)Methane
- c)Ethyl alcohol
- d)Amines
Correct answer is option 'A'. Can you explain this answer?
When hypophosphorous acid is treated with diazonium salts, it is reduced to:
a)
Arenes
b)
Methane
c)
Ethyl alcohol
d)
Amines
|
Lavisha Yadav answered |
Answer is arenes because they are more stable product than the other products obtained.
Which of the following amine will form stable diazonium salt at 273-283 K ?- a)C6H5NH2
- b)C6H5N(CH3)2
- c)C2H5NH2
- d)C6H5CH2NH2
Correct answer is option 'A'. Can you explain this answer?
Which of the following amine will form stable diazonium salt at 273-283 K ?
a)
C6H5NH2
b)
C6H5N(CH3)2
c)
C2H5NH2
d)
C6H5CH2NH2
|
|
Riya Banerjee answered |
The correct answer is Option A.
Aromatic Primary amine will form the most stable diazonium salt because it releases water when it reacts with nitronium ions. If aliphatic primary amine reacts with nitrosonium ion it Also releases water but in this case water reacts with alkyl diazonium salt and it forms alcohol while benzene diazonium salt does not react with water at this temperature.
Aromatic Primary amine will form the most stable diazonium salt because it releases water when it reacts with nitronium ions. If aliphatic primary amine reacts with nitrosonium ion it Also releases water but in this case water reacts with alkyl diazonium salt and it forms alcohol while benzene diazonium salt does not react with water at this temperature.
The stability of benzene diazonium salts is because of- a)Inductive effect
- b)Mesomeric effect
- c)Hyperconjugation
- d)Resonance
Correct answer is option 'D'. Can you explain this answer?
The stability of benzene diazonium salts is because of
a)
Inductive effect
b)
Mesomeric effect
c)
Hyperconjugation
d)
Resonance
|
|
Geetika Shah answered |
None of the errors that are pointed are correct.
Their stability is because of resonance. D is the correct answer.
Benzene diazonium chloride on reaction with phenol in weakly basic medium gives:- a)p-Hydroxyazobenzene
- b)Benzene
- c)Diphenyl ether
- d)Chlorobenzene
Correct answer is option 'A'. Can you explain this answer?
Benzene diazonium chloride on reaction with phenol in weakly basic medium gives:
a)
p-Hydroxyazobenzene
b)
Benzene
c)
Diphenyl ether
d)
Chlorobenzene
|
Arka Das answered |
**Benzene diazonium chloride**
Benzene diazonium chloride (C6H5N2Cl) is an organic compound that is commonly used in diazotization reactions. It is formed by the reaction of aniline (C6H5NH2) with nitrous acid (HNO2) in the presence of hydrochloric acid (HCl).
**Reaction with Phenol**
When benzene diazonium chloride reacts with phenol (C6H5OH) in a weakly basic medium, it undergoes a substitution reaction known as the Sandmeyer reaction. This reaction involves the replacement of the diazonium group (-N2Cl) with the phenolic group (-OH) to form a new compound.
**Formation of p-Hydroxyazobenzene**
The reaction between benzene diazonium chloride and phenol results in the formation of p-hydroxyazobenzene (C12H10N2O), which is the correct answer (option A).
The reaction proceeds as follows:
1. The weakly basic medium provides the necessary conditions for the reaction to occur. It helps in the deprotonation of phenol to form the phenoxide ion (C6H5O-).
2. The diazonium group of benzene diazonium chloride is highly reactive and undergoes nucleophilic substitution. The nitrogen atom of the diazonium group attacks the phenoxide ion, leading to the formation of a new carbon-nitrogen bond.
3. The chlorine atom attached to the nitrogen atom is replaced by the phenoxide group, resulting in the formation of p-hydroxyazobenzene.
The reaction can be represented by the following equation:
C6H5N2Cl + C6H5O- → C12H10N2O + Cl-
**Explanation of Other Options**
Option B: Benzenedoes not participate in the reaction. It remains unchanged.
Option C: Diphenyl ether is not formed in this reaction. It involves the formation of a carbon-oxygen bond between two phenyl groups, which is not observed in the given reaction.
Option D: Chlorobenzene is not formed in this reaction. The chlorine atom from the diazonium chloride is replaced by the phenoxide group, not by another chlorine atom.
Thus, the correct answer is option A: p-Hydroxyazobenzene.
Benzene diazonium chloride (C6H5N2Cl) is an organic compound that is commonly used in diazotization reactions. It is formed by the reaction of aniline (C6H5NH2) with nitrous acid (HNO2) in the presence of hydrochloric acid (HCl).
**Reaction with Phenol**
When benzene diazonium chloride reacts with phenol (C6H5OH) in a weakly basic medium, it undergoes a substitution reaction known as the Sandmeyer reaction. This reaction involves the replacement of the diazonium group (-N2Cl) with the phenolic group (-OH) to form a new compound.
**Formation of p-Hydroxyazobenzene**
The reaction between benzene diazonium chloride and phenol results in the formation of p-hydroxyazobenzene (C12H10N2O), which is the correct answer (option A).
The reaction proceeds as follows:
1. The weakly basic medium provides the necessary conditions for the reaction to occur. It helps in the deprotonation of phenol to form the phenoxide ion (C6H5O-).
2. The diazonium group of benzene diazonium chloride is highly reactive and undergoes nucleophilic substitution. The nitrogen atom of the diazonium group attacks the phenoxide ion, leading to the formation of a new carbon-nitrogen bond.
3. The chlorine atom attached to the nitrogen atom is replaced by the phenoxide group, resulting in the formation of p-hydroxyazobenzene.
The reaction can be represented by the following equation:
C6H5N2Cl + C6H5O- → C12H10N2O + Cl-
**Explanation of Other Options**
Option B: Benzenedoes not participate in the reaction. It remains unchanged.
Option C: Diphenyl ether is not formed in this reaction. It involves the formation of a carbon-oxygen bond between two phenyl groups, which is not observed in the given reaction.
Option D: Chlorobenzene is not formed in this reaction. The chlorine atom from the diazonium chloride is replaced by the phenoxide group, not by another chlorine atom.
Thus, the correct answer is option A: p-Hydroxyazobenzene.
Replacement of diazo group by other groups is helpful in preparing those substituted aromatic compounds which cannot be prepared by
- a)Direct elimination
- b)Addition reaction
- c)Direct substitution
- d)Replacement reaction
Correct answer is option 'C'. Can you explain this answer?
Replacement of diazo group by other groups is helpful in preparing those substituted aromatic compounds which cannot be prepared by
a)
Direct elimination
b)
Addition reaction
c)
Direct substitution
d)
Replacement reaction
|
Vikas Kumar answered |
Replacement of diazo group by other groups is helpful in preparing those substituted aromatic compounds which cannot be prepared by direct substitution. ... The cyano group usually cannot be introduced by nucleophilic substitution of haloarenes, but such compounds can be easily prepared from diazonium salts.
. IUPAC name of NH2CH2CH2CH2COOH is :- a)1-Aminobutanoic acid
- b)4-Aminobutanoic acid
- c)4-Nitrobutanoic acid
- d)4-Aminopropanoic acid
Correct answer is option 'B'. Can you explain this answer?
. IUPAC name of NH2CH2CH2CH2COOH is :
a)
1-Aminobutanoic acid
b)
4-Aminobutanoic acid
c)
4-Nitrobutanoic acid
d)
4-Aminopropanoic acid
|
Vikas Choudhury answered |
4 3 2 1
NH2CH2CH2 CH2 COOH is 4-Aminobutanoic acid , here carboxy group gets preferred over amino group as a main chain.
The main product formed by treating an alkyl or benzyl halide with excess ammonia- a)Mixed
- b)Tertiary
- c)Secondary
- d)Primary
Correct answer is option 'D'. Can you explain this answer?
The main product formed by treating an alkyl or benzyl halide with excess ammonia
a)
Mixed
b)
Tertiary
c)
Secondary
d)
Primary
|
Amita Das answered |
The N in ammonia functions as the nucleophile and attacks the electrophilic C of the alkyl halide displacing the bromide and creating the new C-N bond.
Step 2: An acid/base reaction. The base (excess ammonia) deprotonates the positive N (ammonium) center creating the alkylation product, the primary amine.
The molecular formula of ethyl acetate is- a)C4H8O
- b)C4H8O2
- c)C5H10O2
- d)C5H8O2
Correct answer is option 'B'. Can you explain this answer?
The molecular formula of ethyl acetate is
a)
C4H8O
b)
C4H8O2
c)
C5H10O2
d)
C5H8O2
|
Tejas Singh answered |
Its molecular formula is C4H8O2
When ethanol is treated with benzene diazoniumchloride it forms:- a)Arenes
- b)Ethyl alcohol
- c)Amines
- d)Methane
Correct answer is option 'A'. Can you explain this answer?
When ethanol is treated with benzene diazoniumchloride it forms:
a)
Arenes
b)
Ethyl alcohol
c)
Amines
d)
Methane
|
|
Om Desai answered |
The correct answer is option A
When C2H5OH (ethanol) is treated with C6H5N2Cl it forms benzene.
Some mild reducing agents like C2H5OH themselves get oxidized to ethanol after reducing C6H5N2Cl to benzene.
When C2H5OH (ethanol) is treated with C6H5N2Cl it forms benzene.
Some mild reducing agents like C2H5OH themselves get oxidized to ethanol after reducing C6H5N2Cl to benzene.
. Identify the most basic compound from the following.- a)C6H5NH2
- b)(C6H5)2NH
- c)CH3NH2
- d)(CH3)2NH
Correct answer is option 'D'. Can you explain this answer?
. Identify the most basic compound from the following.
a)
C6H5NH2
b)
(C6H5)2NH
c)
CH3NH2
d)
(CH3)2NH
|
|
Jyoti Aiims Aspirant answered |
In a and b lone pair are in resonance
+I group of d is more than c which increase electron density on nitrogen
+I group of d is more than c which increase electron density on nitrogen
. Acrylonitrile is the common name of:- a)CH3CH2CH2CN
- b)CH3CH2CN
- c)CH2=CHCN
- d)CH3CN
Correct answer is option 'C'. Can you explain this answer?
. Acrylonitrile is the common name of:
a)
CH3CH2CH2CN
b)
CH3CH2CN
c)
CH2=CHCN
d)
CH3CN
|
Shreya Gupta answered |
Acrylonitrile is an organic compound with the formula CH2CHCN. It is a colorless volatile liquid, although commercial samples can be yellow due to impurities. In terms of its molecular structure, it consists of a vinyl group linked to a nitrile. It is an important monomer for the manufacture of useful plastics such as polyacrylonitrile. It is reactive and toxic at low doses. Acrylonitrile was first synthesized by the French chemist Charles Moureu (1863–1929) in 1893.
What is the common name of the given compound?
- a)Methyl benzamine
- b)o-Toluidine
- c)Methyl aniline
- d)Aniline
Correct answer is option 'B'. Can you explain this answer?
What is the common name of the given compound?
a)
Methyl benzamine
b)
o-Toluidine
c)
Methyl aniline
d)
Aniline
|
Sneha Kalra answered |
In this you see that methyl is at o position and there is toulene ( benzene+ ch3) and nh3 + benzeze called aniline so aniline with ch3 is toluidine
Ambident group among the following are:- a)Cyanides and Isocyanides
- b)Acetone and aldehydes
- c)Ethers and esters
- d)Acetal and ketal
Correct answer is option 'A'. Can you explain this answer?
Ambident group among the following are:
a)
Cyanides and Isocyanides
b)
Acetone and aldehydes
c)
Ethers and esters
d)
Acetal and ketal
|
|
Nikita Singh answered |
Ambident groups are those which can attack from both sides. So option a is correct because cyanides is C-N and carbon forms bonds here. Isocyanides are N-C in which nitrogen contains lone pairs which initiates reaction and attaches from nitrogen side.
C6H5-NH-C6H5 is :- a)Dibenzenamine
- b)Diphenyl amine
- c)1,2 Diphenyl amine
- d)Toluidine
Correct answer is option 'B'. Can you explain this answer?
C6H5-NH-C6H5 is :
a)
Dibenzenamine
b)
Diphenyl amine
c)
1,2 Diphenyl amine
d)
Toluidine
|
|
Vikas Choudhury answered |
In the structure two phenyl groups are attached to the amino group, hence the name Diphenyl amine.
When diazonium salt solution is treated with water at a temperature of 283 K it forms?- a)Ester
- b)Phenol
- c)Amines
- d)Alcohol
Correct answer is option 'B'. Can you explain this answer?
When diazonium salt solution is treated with water at a temperature of 283 K it forms?
a)
Ester
b)
Phenol
c)
Amines
d)
Alcohol
|
Vatturi Anjani answered |
Yes as when the temperature of the diazonium salt is allowed to rise upto 283K then the salt is reduced to phenol releasing N2 and hydrochloric acid as the by-products.
. When diazonium salt solution is treated with KI, it forms:- a)Bromobenzene
- b)Iodobenzene
- c)Phenol
- d)Acid
Correct answer is option 'B'. Can you explain this answer?
. When diazonium salt solution is treated with KI, it forms:
a)
Bromobenzene
b)
Iodobenzene
c)
Phenol
d)
Acid
|
Kshitij Pandey answered |
This reaction is unique this is only reaction in which idobenzene formed by diaazonium salt , to make idobenzene first we make diaazonium salt by aniline then we treated diaazonium salt with ki
C6H5N2Cl(diaazonium salt)+KI=C6H5I
C6H5N2Cl(diaazonium salt)+KI=C6H5I
p-amino azo benzene is obtained by treating diazoniumchloride with:- a)Phenol
- b)Aniline
- c)Alcohol
- d)Benzoic acid
Correct answer is option 'B'. Can you explain this answer?
p-amino azo benzene is obtained by treating diazoniumchloride with:
a)
Phenol
b)
Aniline
c)
Alcohol
d)
Benzoic acid
|
|
Lavanya Menon answered |
p-amino azo benzene is obtained by treating diazonium chloride with aniline. The reactions are specifically acid catalyzed and involve pre‐equilibrium formation of amine and diazonium salt followed by rate‐limiting attack of the diazonium ion at a C‐atom (C‐coupling) to give the corresponding amino azo compounds.
Benzonitrile is the IUPAC name of the compound:- a)C6H5NH2
- b)C6H5-CH2NH2
- c)C6H5CN
- d)C6H5-CH2CN
Correct answer is option 'C'. Can you explain this answer?
Benzonitrile is the IUPAC name of the compound:
a)
C6H5NH2
b)
C6H5-CH2NH2
c)
C6H5CN
d)
C6H5-CH2CN
|
Aayush Agarwal answered |
The correct answer is C you can refer ncert of class 11 part 2
Alkyl cyanides are isomeric with:- a)Diazonium salts
- b)Nitroalkanes
- c)Ethers
- d)Isocyanides
Correct answer is option 'D'. Can you explain this answer?
Alkyl cyanides are isomeric with:
a)
Diazonium salts
b)
Nitroalkanes
c)
Ethers
d)
Isocyanides
|
|
Vikas Choudhury answered |
Cyanides and isocyanides are isomeric compounds.
Which one of the following is used to increase blood pressure- a)Ephedrine
- b)Novocain
- c)Benadryl
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
Which one of the following is used to increase blood pressure
a)
Ephedrine
b)
Novocain
c)
Benadryl
d)
None of these
|
|
Anjali Iyer answered |
Correct answer is d) none of these:
1. Fludrocortisone is a medication that seems to help most types of low blood pressure. It works by promoting sodium retention by the kidney, thereby causing fluid retention and some swelling, which is necessary to improve blood pressure.
2. Midodrine activates receptors on the smallest arteries and veins to produce an increase in blood pressure. It is used to help increase standing blood pressure in people with postural hypotension related to nervous system dysfunction.
By treating diazonium salts with cuprous cyanide or KCN and copper powder it forms:- a)Citric acid
- b)Benzoic acid
- c)Aryl nitrile
- d)Oxalic acid
Correct answer is option 'C'. Can you explain this answer?
By treating diazonium salts with cuprous cyanide or KCN and copper powder it forms:
a)
Citric acid
b)
Benzoic acid
c)
Aryl nitrile
d)
Oxalic acid
|
|
Rishika Patel answered |
Formation of Aryl Nitrile from Diazonium Salts
Diazonium salts are compounds containing a positively charged nitrogen atom that is linked to an aromatic ring. These salts are often used in organic synthesis as a source of the aryl group. When treated with cuprous cyanide or KCN and copper powder, diazonium salts undergo a reaction known as Sandmeyer reaction, which forms aryl nitriles.
Reaction Mechanism
The reaction mechanism involves several steps:
1. Formation of Copper(I) Salt
First, cuprous cyanide or KCN is added to the diazonium salt solution to form a copper(I) salt. The copper(I) salt plays a crucial role in the reaction by catalyzing the formation of the aryl nitrile.
2. Formation of Aryl Copper(I) Intermediate
Next, copper powder is added to the reaction mixture, which reduces the copper(I) salt to copper metal. The copper metal then reacts with the diazonium salt to form an aryl copper(I) intermediate.
3. Formation of Aryl Cyanide
The aryl copper(I) intermediate then reacts with the cyanide ion from the cuprous cyanide or KCN to form the aryl cyanide. The reaction releases copper metal, which can then react with more diazonium salt to form more aryl copper(I) intermediate.
Overall Reaction
The overall reaction can be represented as follows:
ArN2+X- + CuCN/KCN → [CuX] + N2 + ArCu + HX
ArCu + CN- → ArCN + Cu
Where Ar represents the aryl group, X represents the anion of the diazonium salt, and HX represents the acid formed in the reaction.
Conclusion
In conclusion, the treatment of diazonium salts with cuprous cyanide or KCN and copper powder forms aryl nitriles through the Sandmeyer reaction. This reaction is an important method for the synthesis of aryl nitriles, which have a variety of applications in organic synthesis and industry.
Diazonium salts are compounds containing a positively charged nitrogen atom that is linked to an aromatic ring. These salts are often used in organic synthesis as a source of the aryl group. When treated with cuprous cyanide or KCN and copper powder, diazonium salts undergo a reaction known as Sandmeyer reaction, which forms aryl nitriles.
Reaction Mechanism
The reaction mechanism involves several steps:
1. Formation of Copper(I) Salt
First, cuprous cyanide or KCN is added to the diazonium salt solution to form a copper(I) salt. The copper(I) salt plays a crucial role in the reaction by catalyzing the formation of the aryl nitrile.
2. Formation of Aryl Copper(I) Intermediate
Next, copper powder is added to the reaction mixture, which reduces the copper(I) salt to copper metal. The copper metal then reacts with the diazonium salt to form an aryl copper(I) intermediate.
3. Formation of Aryl Cyanide
The aryl copper(I) intermediate then reacts with the cyanide ion from the cuprous cyanide or KCN to form the aryl cyanide. The reaction releases copper metal, which can then react with more diazonium salt to form more aryl copper(I) intermediate.
Overall Reaction
The overall reaction can be represented as follows:
ArN2+X- + CuCN/KCN → [CuX] + N2 + ArCu + HX
ArCu + CN- → ArCN + Cu
Where Ar represents the aryl group, X represents the anion of the diazonium salt, and HX represents the acid formed in the reaction.
Conclusion
In conclusion, the treatment of diazonium salts with cuprous cyanide or KCN and copper powder forms aryl nitriles through the Sandmeyer reaction. This reaction is an important method for the synthesis of aryl nitriles, which have a variety of applications in organic synthesis and industry.
is a tertiary amine with IUPAC name:- a)N,N-Dimethyl-methanamine
- b)N-methyl-ethanamine
- c)N-Phenyl-methanamine
- d)N-Methylmethanamine
Correct answer is option 'A'. Can you explain this answer?
is a tertiary amine with IUPAC name:a)
N,N-Dimethyl-methanamine
b)
N-methyl-ethanamine
c)
N-Phenyl-methanamine
d)
N-Methylmethanamine
|
|
Varsha Mangla answered |
C'oz 2 methyl group (CH3) are attached to the N group and as per the rule for the amine, the naming can only be done as N,N-Dimethyl methanamine.
The carbylamine reaction is given by compounds having:- a)-CN group
- b)-NH2 group
- c)-NO2 group
- d)-NH2OH group
Correct answer is option 'B'. Can you explain this answer?
The carbylamine reaction is given by compounds having:
a)
-CN group
b)
-NH2 group
c)
-NO2 group
d)
-NH2OH group
|
|
Vikas Choudhury answered |
-NH2 group.
Carbyl amine reaction is given by aliphatic and aromatic primary amines.
Diazonium salts are used in the preparation of- a)Hormones
- b)Vitamins
- c)Dyes
- d)Proteins
Correct answer is option 'C'. Can you explain this answer?
Diazonium salts are used in the preparation of
a)
Hormones
b)
Vitamins
c)
Dyes
d)
Proteins
|
|
Vijay Bansal answered |
A diazonium salt is an organic compound that contains a nitrogen-nitrogen triple bond and some other generic side group that could be either alkyl (an alkane derivative) or aryl (benzene ring). The 'salt' portion of the name comes from the fact that the diazo (meaning 'di-nitrogen') portion of the compound is present as its ionic salt, with a chloride ion being a typical counter-ion for the positively charged nitrogen atom.
The Hofmann elimination proceeds via a(n) __________ pathway.- a)SN2
- b)E2
- c)E1
- d)SN1
Correct answer is option 'B'. Can you explain this answer?
The Hofmann elimination proceeds via a(n) __________ pathway.
a)
SN2
b)
E2
c)
E1
d)
SN1
|
|
Rajat Kapoor answered |
The Hofmann Elimination is an elimination reaction that forms C-C double (pi) bonds that specifically occurs when the leaving group is NR3 [note] It proceeds through an E2 mechanism. Although the key concepts are no different than one learns in the chapter on elimination from way back in Org 1, it is often included in Org 2 as part of the grab-bag chapter on amines. Because, well… nitrogen.
Which of the following amines is most soluble in water?- a)(CH3CH2CH2)2NH
- b)ethylamine
- c)pyrrolidine
- d)(CH3CH3)3N
Correct answer is option 'B'. Can you explain this answer?
Which of the following amines is most soluble in water?
a)
(CH3CH2CH2)2NH
b)
ethylamine
c)
pyrrolidine
d)
(CH3CH3)3N
|
Sankar Gupta answered |
Because to maximum hydrogen bonding.
Amines that have one of their three hydrogen atoms replaced by an alkyl or aromatic substituent are referred to as- a)primary amines
- b)secondary amines
- c)tertiary amines
- d)quaternary amines
Correct answer is option 'A'. Can you explain this answer?
Amines that have one of their three hydrogen atoms replaced by an alkyl or aromatic substituent are referred to as
a)
primary amines
b)
secondary amines
c)
tertiary amines
d)
quaternary amines
|
Srishti Kaur answered |
Amines that have one of their three hydrogen atoms replaced by an alkyl or aromatic substituent are referred to as primary amines. Secondary amines are those that have two substituents and one hydrogen bonded to a nitrogen.
The IUPAC name of
- a)4- bromoaniline
- b)3-bromoaniline
- c)Aniline
- d)o-bromoaniline
Correct answer is option 'A'. Can you explain this answer?
The IUPAC name of
a)
4- bromoaniline
b)
3-bromoaniline
c)
Aniline
d)
o-bromoaniline
|
|
Nikita Singh answered |
THe IUPAC name of p-bromoaniline is 4-bromoaniline. Carbon attached with NH2 acts as first position and then numbering is done.
An azo compound is formed when benzene diazonium chloride reacts with:- a)2,4,6-Trimethylphenol
- b)Both (A) and (B)
- c)Phenol
- d)Aniline
Correct answer is option 'B'. Can you explain this answer?
An azo compound is formed when benzene diazonium chloride reacts with:
a)
2,4,6-Trimethylphenol
b)
Both (A) and (B)
c)
Phenol
d)
Aniline
|
Manoj Chauhan answered |
Formation of Azo Compound
An azo compound is formed when benzene diazonium chloride reacts with 2,4,6-trimethylphenol and phenol. The reaction involves the substitution of diazonium group (-N2+) with the hydroxyl group (-OH) of the phenol. The reaction is called diazotization.
Diazotization Reaction
Diazotization is a chemical reaction that involves the conversion of an aromatic primary amine to a diazonium salt by the action of nitrous acid. It is a two-step process that involves the formation of a diazonium intermediate, which then reacts with a nucleophile to form the final product.
Step 1: Diazotization of Aromatic Primary Amine
In the first step of diazotization, an aromatic primary amine is treated with nitrous acid (HNO2) to form a diazonium salt. The reaction can be represented as:
R-NH2 + HNO2 → R-N2+Cl- + H2O
where R represents the aromatic group.
Step 2: Reaction with Nucleophile
In the second step, the diazonium salt reacts with a nucleophile (such as phenol or 2,4,6-trimethylphenol) to form the final product, which is an azo compound. The reaction can be represented as:
R-N2+Cl- + Ar-OH → R-N=N-Ar + HCl + H2O
where Ar represents the aromatic ring.
Formation of Azo Compound from Benzene Diazonium Chloride
When benzene diazonium chloride reacts with 2,4,6-trimethylphenol or phenol, an azo compound is formed. The reaction can be represented as:
C6H5-N2+Cl- + Ar-OH → C6H5-N=N-Ar + HCl + H2O
where Ar represents the aromatic ring of 2,4,6-trimethylphenol or phenol.
Therefore, option B (Both A and B) is the correct answer as both 2,4,6-trimethylphenol and phenol can react with benzene diazonium chloride to form azo compounds.
An azo compound is formed when benzene diazonium chloride reacts with 2,4,6-trimethylphenol and phenol. The reaction involves the substitution of diazonium group (-N2+) with the hydroxyl group (-OH) of the phenol. The reaction is called diazotization.
Diazotization Reaction
Diazotization is a chemical reaction that involves the conversion of an aromatic primary amine to a diazonium salt by the action of nitrous acid. It is a two-step process that involves the formation of a diazonium intermediate, which then reacts with a nucleophile to form the final product.
Step 1: Diazotization of Aromatic Primary Amine
In the first step of diazotization, an aromatic primary amine is treated with nitrous acid (HNO2) to form a diazonium salt. The reaction can be represented as:
R-NH2 + HNO2 → R-N2+Cl- + H2O
where R represents the aromatic group.
Step 2: Reaction with Nucleophile
In the second step, the diazonium salt reacts with a nucleophile (such as phenol or 2,4,6-trimethylphenol) to form the final product, which is an azo compound. The reaction can be represented as:
R-N2+Cl- + Ar-OH → R-N=N-Ar + HCl + H2O
where Ar represents the aromatic ring.
Formation of Azo Compound from Benzene Diazonium Chloride
When benzene diazonium chloride reacts with 2,4,6-trimethylphenol or phenol, an azo compound is formed. The reaction can be represented as:
C6H5-N2+Cl- + Ar-OH → C6H5-N=N-Ar + HCl + H2O
where Ar represents the aromatic ring of 2,4,6-trimethylphenol or phenol.
Therefore, option B (Both A and B) is the correct answer as both 2,4,6-trimethylphenol and phenol can react with benzene diazonium chloride to form azo compounds.
Aniline does not undergo Friedel – Crafts reaction- a)Anilium ion deactivates any further reaction.
- b)aluminium chloride, the catalyst reacts with NH2 group
- c)nitrogen of aniline acquires positive charge
- d)all of these
Correct answer is option 'D'. Can you explain this answer?
Aniline does not undergo Friedel – Crafts reaction
a)
Anilium ion deactivates any further reaction.
b)
aluminium chloride, the catalyst reacts with NH2 group
c)
nitrogen of aniline acquires positive charge
d)
all of these
|
Gauri Sharma answered |
NH2 has lp of electron which reacts with AlCl3 or other catalyst that we add to form anilium ion.
The conversion of primary aromatic amines into diazonium salts is known as:- a)Diazotisation
- b)Alkylation
- c)Acylation
- d)Displacement
Correct answer is option 'A'. Can you explain this answer?
The conversion of primary aromatic amines into diazonium salts is known as:
a)
Diazotisation
b)
Alkylation
c)
Acylation
d)
Displacement
|
Preeti Iyer answered |
The process of conversion of primary aromatic amines into its diazonium salt is called diazotization. Diazonium salts are important synthetic intermediates that can undergo coupling reactions to form azo dyes and electrophilic substitution reactions to introduce functional groups.
The general formula of Diazonium salt is:- a)RN2+X–
- b)RN+
- c)RXI
- d)RN2+HSO–4
Correct answer is option 'A'. Can you explain this answer?
The general formula of Diazonium salt is:
a)
RN2+X–
b)
RN+
c)
RXI
d)
RN2+HSO–4
|
Aarya Dasgupta answered |
Any of a group of salts of the general formula ArN
2
X, in which Ar represents an aryl group and X an anion, as benzenediazonium chloride, C
6
H
5
N(N)Cl, many of which are important intermediates in the manufacture of azo dyes.
Hinsberg’s reagent reacts with primary and secondary amines to form sulphonamides. This reagent is also known as- a)N Methylbenzamide
- b)p – toluenesulphonyl chloride
- c)None of these
- d)Benzenesulphonyl chloride
Correct answer is option 'D'. Can you explain this answer?
Hinsberg’s reagent reacts with primary and secondary amines to form sulphonamides. This reagent is also known as
a)
N Methylbenzamide
b)
p – toluenesulphonyl chloride
c)
None of these
d)
Benzenesulphonyl chloride
|
Mohit Patel answered |
C6H5SO2Cl this is benzenesulphonyl chloride or hinsberg reagent.
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