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A horizontal force, just sufficient to move a body of mass 4kg lying on a rough horizontal surface is applied on it. The coefficients of static and kinetic friction between the body and the surface are 0.8 and 0.6 respectively. If the force continues to act even after the block has started moving, the acceleration of the block in m s−2 is [g = 10 m s − 2 ]
- a)1/4
- b)1/2
- c)2
- d)4
Correct answer is option 'C'. Can you explain this answer?
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First, we need to determine the maximum static frictional force that can act on the block before it starts moving. This is given by:
f_static = μ_static * N
where μ_static is the coefficient of static friction and N is the normal force acting on the block. Since the block is lying on a horizontal surface, the normal force is equal to its weight:
N = m * g = 4 kg * 9.81 m/s^2 = 39.24 N
Therefore, the maximum static frictional force is:
f_static = 0.8 * 39.24 N = 31.39 N
Since the applied force is just sufficient to move the block, it must be equal to the maximum static frictional force:
F_applied = f_static = 31.39 N
Once the block starts moving, the frictional force changes from static to kinetic. The kinetic frictional force is given by:
f_kinetic = μ_kinetic * N
where μ_kinetic is the coefficient of kinetic friction. In this case, μ_kinetic = 0.6. Therefore, the kinetic frictional force is:
f_kinetic = 0.6 * 39.24 N = 23.54 N
The net force acting on the block is the difference between the applied force and the kinetic frictional force:
F_net = F_applied - f_kinetic = 31.39 N - 23.54 N = 7.85 N
Finally, we can use Newton's second law (F = m*a) to determine the acceleration of the block:
a = F_net / m = 7.85 N / 4 kg = 1.96 m/s^2
Therefore, the acceleration of the block is 1.96 m/s^2.
f_static = μ_static * N
where μ_static is the coefficient of static friction and N is the normal force acting on the block. Since the block is lying on a horizontal surface, the normal force is equal to its weight:
N = m * g = 4 kg * 9.81 m/s^2 = 39.24 N
Therefore, the maximum static frictional force is:
f_static = 0.8 * 39.24 N = 31.39 N
Since the applied force is just sufficient to move the block, it must be equal to the maximum static frictional force:
F_applied = f_static = 31.39 N
Once the block starts moving, the frictional force changes from static to kinetic. The kinetic frictional force is given by:
f_kinetic = μ_kinetic * N
where μ_kinetic is the coefficient of kinetic friction. In this case, μ_kinetic = 0.6. Therefore, the kinetic frictional force is:
f_kinetic = 0.6 * 39.24 N = 23.54 N
The net force acting on the block is the difference between the applied force and the kinetic frictional force:
F_net = F_applied - f_kinetic = 31.39 N - 23.54 N = 7.85 N
Finally, we can use Newton's second law (F = m*a) to determine the acceleration of the block:
a = F_net / m = 7.85 N / 4 kg = 1.96 m/s^2
Therefore, the acceleration of the block is 1.96 m/s^2.
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A horizontal force, just sufficient to move a body of mass 4kg lying on a rough horizontal surface is applied on it. The coefficients of static and kinetic friction between the body and the surface are 0.8 and 0.6 respectively. If the force continues to act even after the block has started moving, the acceleration of the block in m s−2 is [g = 10 m s − 2 ]a)1/4b)1/2c)2d)4Correct answer is option 'C'. Can you explain this answer?
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A horizontal force, just sufficient to move a body of mass 4kg lying on a rough horizontal surface is applied on it. The coefficients of static and kinetic friction between the body and the surface are 0.8 and 0.6 respectively. If the force continues to act even after the block has started moving, the acceleration of the block in m s−2 is [g = 10 m s − 2 ]a)1/4b)1/2c)2d)4Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A horizontal force, just sufficient to move a body of mass 4kg lying on a rough horizontal surface is applied on it. The coefficients of static and kinetic friction between the body and the surface are 0.8 and 0.6 respectively. If the force continues to act even after the block has started moving, the acceleration of the block in m s−2 is [g = 10 m s − 2 ]a)1/4b)1/2c)2d)4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A horizontal force, just sufficient to move a body of mass 4kg lying on a rough horizontal surface is applied on it. The coefficients of static and kinetic friction between the body and the surface are 0.8 and 0.6 respectively. If the force continues to act even after the block has started moving, the acceleration of the block in m s−2 is [g = 10 m s − 2 ]a)1/4b)1/2c)2d)4Correct answer is option 'C'. Can you explain this answer?.
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