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Ionic product of Ni(OH)2 is 2.0 x 10-15 Molar solubility of Ni(OH)2 in 0.10 M NaOH will be
  • a)
    1.0 x 10-13M
  • b)
    2.0 x 10-13M
  • c)
    4.0 x 10-13M
  • d)
    8.0 x 10-13M
Correct answer is option 'B'. Can you explain this answer?
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Ionic product of Ni(OH)2is 2.0 x 10-15Molar solubility of Ni(OH)2in 0.10 M NaOH will bea)1.0 x 10-13Mb)2.0 x 10-13Mc)4.0 x 10-13Md)8.0 x 10-13MCorrect answer is option 'B'. Can you explain this answer?
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Ionic product of Ni(OH)2is 2.0 x 10-15Molar solubility of Ni(OH)2in 0.10 M NaOH will bea)1.0 x 10-13Mb)2.0 x 10-13Mc)4.0 x 10-13Md)8.0 x 10-13MCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Ionic product of Ni(OH)2is 2.0 x 10-15Molar solubility of Ni(OH)2in 0.10 M NaOH will bea)1.0 x 10-13Mb)2.0 x 10-13Mc)4.0 x 10-13Md)8.0 x 10-13MCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ionic product of Ni(OH)2is 2.0 x 10-15Molar solubility of Ni(OH)2in 0.10 M NaOH will bea)1.0 x 10-13Mb)2.0 x 10-13Mc)4.0 x 10-13Md)8.0 x 10-13MCorrect answer is option 'B'. Can you explain this answer?.
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