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A is thrice as fast as B and is therefore able to finish a work in 40 days less than that of B. Find the time in which they can do it working together.
- a)20 days
- b)30 days
- c)25 days
- d)15 days
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A is thrice as fast as B and is therefore able to finish a work in 40 ...
Given,
Ratio of time taken by A and B = 1 : 3
∴ B takes 3 days to finish a unit work while A takes 1 day to finish the same work
The difference of time is 2 days
Given,
Difference of time is 40 days
∴ Time taken by B to complete the work = [(3/2) × 40] = 60 days
∴ A takes 20 days to finish a work
⇒ Work in 1 day by A = 1/20
⇒ Work in 1 day by B = 1/60
⇒ Work in 1 day by (A+B) = [(1/20) + (1/60)] = 4/60
∴ A and B will take days to complete the work = 15 days
Ratio of time taken by A and B = 1 : 3
∴ B takes 3 days to finish a unit work while A takes 1 day to finish the same work
The difference of time is 2 days
Given,
Difference of time is 40 days
∴ Time taken by B to complete the work = [(3/2) × 40] = 60 days
∴ A takes 20 days to finish a work
⇒ Work in 1 day by A = 1/20
⇒ Work in 1 day by B = 1/60
⇒ Work in 1 day by (A+B) = [(1/20) + (1/60)] = 4/60
∴ A and B will take days to complete the work = 15 days
Most Upvoted Answer
A is thrice as fast as B and is therefore able to finish a work in 40 ...
Given:
A is thrice as fast as B
A finishes the work in 40 days less than B
To find:
Time taken by A and B working together
Solution:
Let the time taken by B to finish the work be x days.
Then, the time taken by A to finish the same work would be x/3 days.
According to the question, A finishes the work in 40 days less than B.
So, we can write the following equation:
x/3 = x - 40
Solving for x, we get:
x = 60
Therefore, B takes 60 days to finish the work.
And A takes 20 days to finish the same work. (Since A is thrice as fast as B)
Now, let's find the time taken by A and B working together.
Let the total work be 1 unit.
Then, in 1 day, B can do 1/60th of the work.
And in 1 day, A can do 1/20th of the work.
So, in 1 day, working together, A and B can do:
1/60 + 1/20 = 1/30th of the work
Therefore, the time taken by A and B working together to finish the work would be:
1 / (1/30) = 30 days
Hence, the correct answer is option (D) 15 days.
A is thrice as fast as B
A finishes the work in 40 days less than B
To find:
Time taken by A and B working together
Solution:
Let the time taken by B to finish the work be x days.
Then, the time taken by A to finish the same work would be x/3 days.
According to the question, A finishes the work in 40 days less than B.
So, we can write the following equation:
x/3 = x - 40
Solving for x, we get:
x = 60
Therefore, B takes 60 days to finish the work.
And A takes 20 days to finish the same work. (Since A is thrice as fast as B)
Now, let's find the time taken by A and B working together.
Let the total work be 1 unit.
Then, in 1 day, B can do 1/60th of the work.
And in 1 day, A can do 1/20th of the work.
So, in 1 day, working together, A and B can do:
1/60 + 1/20 = 1/30th of the work
Therefore, the time taken by A and B working together to finish the work would be:
1 / (1/30) = 30 days
Hence, the correct answer is option (D) 15 days.
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A is thrice as fast as B and is therefore able to finish a work in 40 days less than that of B. Find the time in which they can do it working together.a)20 daysb)30 daysc)25 daysd)15 daysCorrect answer is option 'D'. Can you explain this answer?
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