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A can work twice as B and they together can finish a work in 16 days. In how many days will A alone finish the work?
  • a)
    24 days
  • b)
    10 days
  • c)
    15 days
  • d)
    5 days
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A can work twice as B and they together can finish a work in 16 days. ...
From the given data,
⇒ Ratio of A’s work and B’s work = 2 : 1
⇒ Work done by A and B in one day = 1/16
Divide 1/16 in the ratio of 2 : 1
⇒ Work done by A in one day = (1/16 × 2/3) = 2/48 = 1/24
∴ A alone can finish the work in 24 days
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Most Upvoted Answer
A can work twice as B and they together can finish a work in 16 days. ...
Let's assume that B can finish the work in 'x' days. Since A can work twice as fast as B, it means that A can finish the work in 'x/2' days.

To find out how long it will take for A to finish the work alone, we need to calculate the work done by A and B together in one day.

Since A can finish the work in 'x/2' days and B can finish the work in 'x' days, their combined work in one day would be:

1/(x/2) + 1/x

To find out how long it will take for A and B together to finish the work, we can set up the following equation:

1/(x/2) + 1/x = 1/16

Now, let's solve this equation to find the value of 'x':

Multiply both sides of the equation by 16x:

16 + 16x/(x/2) = x

Simplify the equation:

16 + 32 = x

x = 48

Therefore, B can finish the work in 48 days and A can finish the work in half the time, which is 24 days.

Hence, the correct answer is option A) 24 days.
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A can work twice as B and they together can finish a work in 16 days. In how many days will A alone finish the work?a)24 daysb)10 daysc)15 daysd)5 daysCorrect answer is option 'A'. Can you explain this answer?
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