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Calculate the heat required (in kJ, up to 1 digit after the decimal point) to raise the temperature of 1 mole of a solid material from 100°C to 1000°C. The specific heat ( CP ) of the material (in J/mol-K) is expressed as CP = 20 + 0.005T, where T is in K. Assume no phase change.______
 
Important : you should answer only the numeric value
 
    Correct answer is '21.703'. Can you explain this answer?
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    °C to 200°C, given that its specific heat capacity is 0.5 J/g°C and its molar mass is 50 g/mol.

    First, we need to convert the temperature difference from Celsius to Kelvin:
    ΔT = (200 + 273.15) - (100 + 273.15) = 100 K

    Next, we need to calculate the mass of 1 mole of the solid material:
    mass = molar mass = 50 g/mol

    Then, we can calculate the heat required using the formula:
    q = m × c × ΔT
    where q is the heat required, m is the mass, c is the specific heat capacity, and ΔT is the temperature difference.

    Substituting the values we have:
    q = 50 g × 0.5 J/g°C × 100 K = 2500 J = 2.5 kJ (rounded to 1 digit after the decimal point)

    Therefore, the heat required to raise the temperature of 1 mole of the solid material from 100°C to 200°C is 2.5 kJ.
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    In linear gas tungsten arc welding of two plates of the same material, the peak temperature T (inK) is given as T = c1q / α,where q is the heat input per unit length (in J/m) of weld, α is the thermaldiffusivity (in m2/s) of the plate materials and C1 is a constant independent of process parametersand material types. Two welding cases are given below.Case I: V = 15 V, I = 200 A, v = 5 mm/s, k = 150 W/mK, ρ = 3000 kg/m3, C = 900 J/kg-KCase II: V = 15 V, I = 300 A, v = 10 mm/s, k = 50 W/mK, ρ = 8000 kg/m3, C = 450 J/kg-Kwhere, V is welding voltage, I is welding current, v is welding speed, and k, ρand C refer to the thermal conductivity, the density and the specific heat of the plate materials,respectively. Consider that electrical energy is completely converted to thermal energy. All otherconditions remain same.The ratio of the peak temperature in Case I to that in Case II is

    Calculate the heat required (in kJ, up to 1 digit after the decimal point) to raise the temperature of 1 mole of a solid material from 100°C to 1000°C. The specific heat ( CP ) of the material (in J/mol-K) is expressed as CP = 20 + 0.005T, where T is in K. Assume no phase change.______Important : you should answer only the numeric valueCorrect answer is '21.703'. Can you explain this answer?
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    Calculate the heat required (in kJ, up to 1 digit after the decimal point) to raise the temperature of 1 mole of a solid material from 100°C to 1000°C. The specific heat ( CP ) of the material (in J/mol-K) is expressed as CP = 20 + 0.005T, where T is in K. Assume no phase change.______Important : you should answer only the numeric valueCorrect answer is '21.703'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Calculate the heat required (in kJ, up to 1 digit after the decimal point) to raise the temperature of 1 mole of a solid material from 100°C to 1000°C. The specific heat ( CP ) of the material (in J/mol-K) is expressed as CP = 20 + 0.005T, where T is in K. Assume no phase change.______Important : you should answer only the numeric valueCorrect answer is '21.703'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the heat required (in kJ, up to 1 digit after the decimal point) to raise the temperature of 1 mole of a solid material from 100°C to 1000°C. The specific heat ( CP ) of the material (in J/mol-K) is expressed as CP = 20 + 0.005T, where T is in K. Assume no phase change.______Important : you should answer only the numeric valueCorrect answer is '21.703'. Can you explain this answer?.
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