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Calculate the heat required (in kJ, up to 1 digit after the decimal point) to raise the temperature of 1 mole of a solid material from 100°C to 1000°C. The specific heat ( CP ) of the material (in J/mol-K) is expressed as CP = 20 + 0.005T, where T is in K. Assume no phase change.______
Important : you should answer only the numeric value
Correct answer is '21.703'. Can you explain this answer?
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Calculate the heat required (in kJ, up to 1 digit after the decimal po...
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Calculate the heat required (in kJ, up to 1 digit after the decimal po...
°C to 200°C, given that its specific heat capacity is 0.5 J/g°C and its molar mass is 50 g/mol.
First, we need to convert the temperature difference from Celsius to Kelvin:
ΔT = (200 + 273.15) - (100 + 273.15) = 100 K
Next, we need to calculate the mass of 1 mole of the solid material:
mass = molar mass = 50 g/mol
Then, we can calculate the heat required using the formula:
q = m × c × ΔT
where q is the heat required, m is the mass, c is the specific heat capacity, and ΔT is the temperature difference.
Substituting the values we have:
q = 50 g × 0.5 J/g°C × 100 K = 2500 J = 2.5 kJ (rounded to 1 digit after the decimal point)
Therefore, the heat required to raise the temperature of 1 mole of the solid material from 100°C to 200°C is 2.5 kJ.
First, we need to convert the temperature difference from Celsius to Kelvin:
ΔT = (200 + 273.15) - (100 + 273.15) = 100 K
Next, we need to calculate the mass of 1 mole of the solid material:
mass = molar mass = 50 g/mol
Then, we can calculate the heat required using the formula:
q = m × c × ΔT
where q is the heat required, m is the mass, c is the specific heat capacity, and ΔT is the temperature difference.
Substituting the values we have:
q = 50 g × 0.5 J/g°C × 100 K = 2500 J = 2.5 kJ (rounded to 1 digit after the decimal point)
Therefore, the heat required to raise the temperature of 1 mole of the solid material from 100°C to 200°C is 2.5 kJ.
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Calculate the heat required (in kJ, up to 1 digit after the decimal point) to raise the temperature of 1 mole of a solid material from 100°C to 1000°C. The specific heat ( CP ) of the material (in J/mol-K) is expressed as CP = 20 + 0.005T, where T is in K. Assume no phase change.______Important : you should answer only the numeric valueCorrect answer is '21.703'. Can you explain this answer?
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