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The Bragg angle corresponding to the first order reflection from (1,1,1) planes in a crystal is 30° when X - rays of wavelength 1.75Å are used. Calculate the interatomic spacing.
Correct answer is '3.031'. Can you explain this answer?
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The Bragg angle corresponding to the first order reflection from (1,1,...

where a = interatomic distance
d = interplanar distance 
h,k,l = Miller indices.
According to the problem h = k = I = 1 (being d111 plane) 
q = 30°, I = 1.75 x 10-10m, n = 1 
from bragg’s equation 2d sin q = nl, we have

Solving we have a = 3.031Å
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The Bragg angle corresponding to the first order reflection from (1,1,...
Degrees.

The Bragg angle is given by the equation:

2dsinθ = nλ

where d is the spacing between the crystal planes, θ is the Bragg angle, n is the order of the reflection, and λ is the wavelength of the incident radiation.

For the first order reflection from (1,1,1) planes, n = 1 and d is the spacing between adjacent (1,1,1) planes, which is given by:

d = a/√(h^2+k^2+l^2)

where a is the lattice parameter and h, k, and l are the Miller indices of the crystal planes.

For (1,1,1) planes, h = k = l = 1, so:

d = a/√(1^2+1^2+1^2) = a/√3

Substituting n = 1, d = a/√3, and θ = 30 degrees into the Bragg equation, we get:

2(a/√3)sin30 = λ

Simplifying and solving for λ, we get:

λ = 2a/(√3)

Therefore, the wavelength of the incident radiation is determined by the lattice parameter of the crystal.
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The Bragg angle corresponding to the first order reflection from (1,1,1) planes in a crystal is 30° when X - rays of wavelength 1.75Å are used. Calculate the interatomic spacing.Correct answer is '3.031'. Can you explain this answer?
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