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A pn junction solar cell of area 1.0 cm2, illuminated uniformly with 100 mW cm-2, has the following parameters:E fficiency = 15%, open circuit voltage = 0.7 V, fill factor = 0.8, and thickness = 200 pm, The charge of an electron is 1.6 x 10-19 C. The average optical generation rate (in cm-3 S-1) is
- a)1.04 x 1019
- b)83.60 x 1019
- c)0.84 x 1019
- d)5.57 x 1019
Correct answer is option 'C'. Can you explain this answer?
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Calculation of Average Optical Generation Rate in a PN Junction Solar Cell
Given Parameters:
Area of the solar cell (A) = 1.0 cm2
Illumination intensity (I) = 100 mW cm-2
Efficiency (η) = 15%
Open circuit voltage (Voc) = 0.7 V
Fill factor (FF) = 0.8
Thickness (d) = 200 pm
Charge of an electron (q) = 1.6 x 10-19 C
1. Calculation of Short Circuit Current (Isc):
Isc = I * A
Isc = 100 x 1.0 x 10-3 A
Isc = 0.1 A
2. Calculation of Maximum Power (Pmax):
Pmax = Isc * Voc * FF
Pmax = 0.1 * 0.7 * 0.8
Pmax = 0.056 W
3. Calculation of Photon Flux (Φ):
Φ = I / (q * η * A)
Φ = 100 x 1.0 x 10-3 / (1.6 x 10-19 x 0.15 x 1.0 x 10-4)
Φ = 4.17 x 1015 photons cm-2 s-1
4. Calculation of Average Optical Generation Rate (G):
G = Φ / d
G = 4.17 x 1015 / (200 x 10-7)
G = 0.84 x 1019 cm-3 s-1
Therefore, the correct answer is option 'C' which is 0.84 x 1019 cm-3 s-1.
Given Parameters:
Area of the solar cell (A) = 1.0 cm2
Illumination intensity (I) = 100 mW cm-2
Efficiency (η) = 15%
Open circuit voltage (Voc) = 0.7 V
Fill factor (FF) = 0.8
Thickness (d) = 200 pm
Charge of an electron (q) = 1.6 x 10-19 C
1. Calculation of Short Circuit Current (Isc):
Isc = I * A
Isc = 100 x 1.0 x 10-3 A
Isc = 0.1 A
2. Calculation of Maximum Power (Pmax):
Pmax = Isc * Voc * FF
Pmax = 0.1 * 0.7 * 0.8
Pmax = 0.056 W
3. Calculation of Photon Flux (Φ):
Φ = I / (q * η * A)
Φ = 100 x 1.0 x 10-3 / (1.6 x 10-19 x 0.15 x 1.0 x 10-4)
Φ = 4.17 x 1015 photons cm-2 s-1
4. Calculation of Average Optical Generation Rate (G):
G = Φ / d
G = 4.17 x 1015 / (200 x 10-7)
G = 0.84 x 1019 cm-3 s-1
Therefore, the correct answer is option 'C' which is 0.84 x 1019 cm-3 s-1.
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A pn junction solar cell of area 1.0 cm2, illuminated uniformly with 100 mW cm-2, has the following parameters:E fficiency = 15%, open circuit voltage = 0.7 V, fill factor = 0.8, and thickness = 200 pm, The charge of an electron is 1.6 x 10-19 C. The average optical generation rate (in cm-3 S-1) isa)1.04 x 1019b)83.60 x 1019c)0.84 x 1019d)5.57 x 1019Correct answer is option 'C'. Can you explain this answer?
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A pn junction solar cell of area 1.0 cm2, illuminated uniformly with 100 mW cm-2, has the following parameters:E fficiency = 15%, open circuit voltage = 0.7 V, fill factor = 0.8, and thickness = 200 pm, The charge of an electron is 1.6 x 10-19 C. The average optical generation rate (in cm-3 S-1) isa)1.04 x 1019b)83.60 x 1019c)0.84 x 1019d)5.57 x 1019Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A pn junction solar cell of area 1.0 cm2, illuminated uniformly with 100 mW cm-2, has the following parameters:E fficiency = 15%, open circuit voltage = 0.7 V, fill factor = 0.8, and thickness = 200 pm, The charge of an electron is 1.6 x 10-19 C. The average optical generation rate (in cm-3 S-1) isa)1.04 x 1019b)83.60 x 1019c)0.84 x 1019d)5.57 x 1019Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pn junction solar cell of area 1.0 cm2, illuminated uniformly with 100 mW cm-2, has the following parameters:E fficiency = 15%, open circuit voltage = 0.7 V, fill factor = 0.8, and thickness = 200 pm, The charge of an electron is 1.6 x 10-19 C. The average optical generation rate (in cm-3 S-1) isa)1.04 x 1019b)83.60 x 1019c)0.84 x 1019d)5.57 x 1019Correct answer is option 'C'. Can you explain this answer?.
A pn junction solar cell of area 1.0 cm2, illuminated uniformly with 100 mW cm-2, has the following parameters:E fficiency = 15%, open circuit voltage = 0.7 V, fill factor = 0.8, and thickness = 200 pm, The charge of an electron is 1.6 x 10-19 C. The average optical generation rate (in cm-3 S-1) isa)1.04 x 1019b)83.60 x 1019c)0.84 x 1019d)5.57 x 1019Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A pn junction solar cell of area 1.0 cm2, illuminated uniformly with 100 mW cm-2, has the following parameters:E fficiency = 15%, open circuit voltage = 0.7 V, fill factor = 0.8, and thickness = 200 pm, The charge of an electron is 1.6 x 10-19 C. The average optical generation rate (in cm-3 S-1) isa)1.04 x 1019b)83.60 x 1019c)0.84 x 1019d)5.57 x 1019Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pn junction solar cell of area 1.0 cm2, illuminated uniformly with 100 mW cm-2, has the following parameters:E fficiency = 15%, open circuit voltage = 0.7 V, fill factor = 0.8, and thickness = 200 pm, The charge of an electron is 1.6 x 10-19 C. The average optical generation rate (in cm-3 S-1) isa)1.04 x 1019b)83.60 x 1019c)0.84 x 1019d)5.57 x 1019Correct answer is option 'C'. Can you explain this answer?.
Solutions for A pn junction solar cell of area 1.0 cm2, illuminated uniformly with 100 mW cm-2, has the following parameters:E fficiency = 15%, open circuit voltage = 0.7 V, fill factor = 0.8, and thickness = 200 pm, The charge of an electron is 1.6 x 10-19 C. The average optical generation rate (in cm-3 S-1) isa)1.04 x 1019b)83.60 x 1019c)0.84 x 1019d)5.57 x 1019Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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