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The difference in the work done when one mole of Al4C3 (s) reacts with water in a closed vessel at 27°C against; atmospheric pressure and that in an open vessel under the same conditions is
- a)greater in the open vessel by 600 cal
- b)greater in the closed vessel by 600 cal
- c)greater in the open vessel by 1800 cal
- d)greater in the closed vessel by 1800 cal
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The difference in the work done when one mole of Al4C3 (s) reacts with...
Reaction occuring is
When the vessel is closed, volume = constant i.e.,
ΔV = 0
Hence, W = -PΔV = 0
When vessel is open, initial volume,
V1 = 0 (as no gas is present)
Final volume, V2 = volume of 3 mole of CH4
PV2 = nRT
∴
∴ W = -P (V2 - V1)
= -PV2
i.e., work is done by the system.
When the vessel is closed, volume = constant i.e.,
ΔV = 0
Hence, W = -PΔV = 0
When vessel is open, initial volume,
V1 = 0 (as no gas is present)
Final volume, V2 = volume of 3 mole of CH4
PV2 = nRT
∴
∴ W = -P (V2 - V1)
= -PV2
i.e., work is done by the system.
Most Upvoted Answer
The difference in the work done when one mole of Al4C3 (s) reacts with...
The work done when one mole of Al4C3 (s) reacts with water in a closed vessel at 27°C can be calculated using the equation:
ΔG = ΔH - TΔS
where ΔG is the change in Gibbs free energy, ΔH is the enthalpy change, ΔS is the entropy change, and T is the temperature in Kelvin.
To find the work done, we need to calculate ΔG. The enthalpy change can be found using the balanced chemical equation for the reaction:
Al4C3 (s) + 12H2O (l) -> 4Al(OH)3 (s) + 3CH4 (g)
The enthalpy change for this reaction can be looked up in a reference table or calculated using Hess's law.
The entropy change can also be looked up in a reference table or calculated using standard entropy values for the reactants and products.
Once we have the values for ΔH and ΔS, we can substitute them into the equation and calculate ΔG. From there, we can determine the work done.
ΔG = ΔH - TΔS
where ΔG is the change in Gibbs free energy, ΔH is the enthalpy change, ΔS is the entropy change, and T is the temperature in Kelvin.
To find the work done, we need to calculate ΔG. The enthalpy change can be found using the balanced chemical equation for the reaction:
Al4C3 (s) + 12H2O (l) -> 4Al(OH)3 (s) + 3CH4 (g)
The enthalpy change for this reaction can be looked up in a reference table or calculated using Hess's law.
The entropy change can also be looked up in a reference table or calculated using standard entropy values for the reactants and products.
Once we have the values for ΔH and ΔS, we can substitute them into the equation and calculate ΔG. From there, we can determine the work done.
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The difference in the work done when one mole of Al4C3 (s) reacts with water in a closed vessel at 27°C against; atmospheric pressure and that in an open vessel under the same conditions isa)greater in the open vessel by 600 calb)greater in the closed vessel by 600 calc)greater in the open vessel by 1800 cald)greater in the closed vessel by 1800 calCorrect answer is option 'C'. Can you explain this answer?
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The difference in the work done when one mole of Al4C3 (s) reacts with water in a closed vessel at 27°C against; atmospheric pressure and that in an open vessel under the same conditions isa)greater in the open vessel by 600 calb)greater in the closed vessel by 600 calc)greater in the open vessel by 1800 cald)greater in the closed vessel by 1800 calCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The difference in the work done when one mole of Al4C3 (s) reacts with water in a closed vessel at 27°C against; atmospheric pressure and that in an open vessel under the same conditions isa)greater in the open vessel by 600 calb)greater in the closed vessel by 600 calc)greater in the open vessel by 1800 cald)greater in the closed vessel by 1800 calCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The difference in the work done when one mole of Al4C3 (s) reacts with water in a closed vessel at 27°C against; atmospheric pressure and that in an open vessel under the same conditions isa)greater in the open vessel by 600 calb)greater in the closed vessel by 600 calc)greater in the open vessel by 1800 cald)greater in the closed vessel by 1800 calCorrect answer is option 'C'. Can you explain this answer?.
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