height of object=5cmu=-25v=?f=-10(concave lens)1/f=1/v+1/uput this formulathen you get "v"=-16.66v=16.67(approx)image formed = real and inverted

Ray Diagram Analysis:
1. Ray Diagram Construction:
- Draw a ray parallel to the principal axis that passes through the focal point after refraction.
- Draw a ray passing through the optical center of the lens without deviation.
- Draw a ray passing through the focal point before refraction.
2. Image Position Determination:
- Using the ray diagram, locate the point where the rays intersect after refraction.
- Measure the distance from the lens to this point to determine the image position.
- In this case, the image is formed beyond 2F, as the rays converge after refraction.
3. Image Size Analysis:
- Measure the size of the image formed by the converging lens.
- Calculate the magnification using the formula: Magnification = Image Height / Object Height.
- The magnification will indicate whether the image is larger or smaller than the object.
4. Nature of the Image:
- Determine the nature of the image based on its position and size.
- Since the image is real and inverted, it is formed on the opposite side of the lens from the object.
- The image size may be larger or smaller depending on the magnification value.

Explanation:
When an object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm, the image formed is real, inverted, and located beyond 2F. The size of the image can be determined using the magnification formula, which compares the height of the image to the height of the object. In this case, the image may appear larger or smaller than the object, depending on the magnification value. By analyzing the ray diagram, one can understand how light rays interact with the lens to form an image at a specific position. This process helps in visualizing and predicting the characteristics of the image formed by the lens.