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An object 2 cm tall is placed at 10 cm from a converging lens of focal length of 6 cm find the size, nature, magnification and position of image?
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An object 2 cm tall is placed at 10 cm from a converging lens of focal...
Solution:
Given data:
- Object height (h_o) = 2 cm
- Object distance (u) = -10 cm (since object is placed on the left side of the lens)
- Focal length (f) = 6 cm
Calculations:
1. Determining the image distance (v):
Using the lens formula:
1/f = 1/v - 1/u
1/6 = 1/v + 1/10
1/v = 1/6 - 1/10
v = 15 cm
2. Determining the magnification (m):
Using the magnification formula:
m = -v/u
m = -15/-10
m = 1.5
3. Determining the image height (h_i):
Using the magnification formula:
m = h_i/h_o
1.5 = h_i/2
h_i = 3 cm
4. Determining the nature of the image:
Since the magnification is positive, the image is erect. Since the object is placed beyond the focal length, it is a real image.
5. Determining the position of the image:
The image is formed at a distance of 15 cm on the right side of the lens.
Therefore, the size of the image is 3 cm, the nature of the image is real and erect, the magnification is 1.5, and the position of the image is 15 cm on the right side of the lens.
Given data:
- Object height (h_o) = 2 cm
- Object distance (u) = -10 cm (since object is placed on the left side of the lens)
- Focal length (f) = 6 cm
Calculations:
1. Determining the image distance (v):
Using the lens formula:
1/f = 1/v - 1/u
1/6 = 1/v + 1/10
1/v = 1/6 - 1/10
v = 15 cm
2. Determining the magnification (m):
Using the magnification formula:
m = -v/u
m = -15/-10
m = 1.5
3. Determining the image height (h_i):
Using the magnification formula:
m = h_i/h_o
1.5 = h_i/2
h_i = 3 cm
4. Determining the nature of the image:
Since the magnification is positive, the image is erect. Since the object is placed beyond the focal length, it is a real image.
5. Determining the position of the image:
The image is formed at a distance of 15 cm on the right side of the lens.
Therefore, the size of the image is 3 cm, the nature of the image is real and erect, the magnification is 1.5, and the position of the image is 15 cm on the right side of the lens.
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An object 2 cm tall is placed at 10 cm from a converging lens of focal length of 6 cm find the size, nature, magnification and position of image?
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An object 2 cm tall is placed at 10 cm from a converging lens of focal length of 6 cm find the size, nature, magnification and position of image? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An object 2 cm tall is placed at 10 cm from a converging lens of focal length of 6 cm find the size, nature, magnification and position of image? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object 2 cm tall is placed at 10 cm from a converging lens of focal length of 6 cm find the size, nature, magnification and position of image?.
An object 2 cm tall is placed at 10 cm from a converging lens of focal length of 6 cm find the size, nature, magnification and position of image? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An object 2 cm tall is placed at 10 cm from a converging lens of focal length of 6 cm find the size, nature, magnification and position of image? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object 2 cm tall is placed at 10 cm from a converging lens of focal length of 6 cm find the size, nature, magnification and position of image?.
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