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In an n-p-n transistor, 108 electrons are emitted from the emitter in 10-4 s. If 2% of electrons are lost in the base. Then the current gain in common-emitter configuration mode is
- a)0.98
- b)0.49
- c)98
- d)49
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
In an n-p-n transistor, 108electrons are emitted from the emitter in 1...
= (98/100) / (2/100)
= 98/2
= 49
Most Upvoted Answer
In an n-p-n transistor, 108electrons are emitted from the emitter in 1...
Given data:
Number of electrons emitted from the emitter = 108
Time taken for the emission of electrons = 10^-4 s
Percentage of electrons lost in the base = 2%
Formula used:
The current gain in common-emitter configuration mode is given by the formula:
β = (Ic / Ib)
where,
Ic = Collector current
Ib = Base current
Calculation:
1. Calculation of emitter current:
The number of electrons emitted from the emitter can be converted into the emitter current by dividing it by the time taken for the emission of electrons.
Emitter current (Ie) = Number of electrons emitted / Time taken
Ie = 108 / 10^-4 = 1.08 x 10^6 A
2. Calculation of base current:
As 2% of electrons are lost in the base, the number of electrons reaching the collector will be 98% of the total electrons emitted from the emitter.
Number of electrons reaching the collector = 98% of 108
= 0.98 x 108 = 105.84
The remaining electrons (2%) are lost in the base. Therefore, the base current (Ib) can be calculated as follows:
Ib = 2% of Ie
= 2/100 x 1.08 x 10^6
= 21,600 A
3. Calculation of current gain:
Using the formula of current gain in common-emitter configuration mode, we get:
β = Ic / Ib
In an n-p-n transistor, the collector current is the flow of electrons from the collector to the emitter. Therefore, the number of electrons reaching the collector is equal to the collector current.
Ic = Number of electrons reaching the collector / Time taken
Ic = 105.84 / 10^-4
Ic = 1.0584 x 10^6 A
Now, substituting the values of Ic and Ib in the formula of current gain, we get:
β = 1.0584 x 10^6 / 21,600
β = 49
Therefore, the current gain in the common-emitter configuration mode is 49.
Hence, option (d) is the correct answer.
Number of electrons emitted from the emitter = 108
Time taken for the emission of electrons = 10^-4 s
Percentage of electrons lost in the base = 2%
Formula used:
The current gain in common-emitter configuration mode is given by the formula:
β = (Ic / Ib)
where,
Ic = Collector current
Ib = Base current
Calculation:
1. Calculation of emitter current:
The number of electrons emitted from the emitter can be converted into the emitter current by dividing it by the time taken for the emission of electrons.
Emitter current (Ie) = Number of electrons emitted / Time taken
Ie = 108 / 10^-4 = 1.08 x 10^6 A
2. Calculation of base current:
As 2% of electrons are lost in the base, the number of electrons reaching the collector will be 98% of the total electrons emitted from the emitter.
Number of electrons reaching the collector = 98% of 108
= 0.98 x 108 = 105.84
The remaining electrons (2%) are lost in the base. Therefore, the base current (Ib) can be calculated as follows:
Ib = 2% of Ie
= 2/100 x 1.08 x 10^6
= 21,600 A
3. Calculation of current gain:
Using the formula of current gain in common-emitter configuration mode, we get:
β = Ic / Ib
In an n-p-n transistor, the collector current is the flow of electrons from the collector to the emitter. Therefore, the number of electrons reaching the collector is equal to the collector current.
Ic = Number of electrons reaching the collector / Time taken
Ic = 105.84 / 10^-4
Ic = 1.0584 x 10^6 A
Now, substituting the values of Ic and Ib in the formula of current gain, we get:
β = 1.0584 x 10^6 / 21,600
β = 49
Therefore, the current gain in the common-emitter configuration mode is 49.
Hence, option (d) is the correct answer.
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In an n-p-n transistor, 108electrons are emitted from the emitter in 10-4s. If 2% of electrons are lost in the base. Then the current gain in common-emitter configuration mode isa)0.98b)0.49c)98d)49Correct answer is option 'D'. Can you explain this answer?
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