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A 1 mA meter movement with an internal resistance of 100Ω is to be converted into (0 – 100) mA. To achieve this, value of shunt resistance Rsh is given by
- a)1 KΩ
- b)200 KΩ
- c)1.01 Ω
- d)1.01 Ω
Correct answer is option 'C'. Can you explain this answer?
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Ohms is to be used in a circuit to measure a current of 10 mA. What external resistance should be used in series with the meter movement to obtain a full-scale deflection?
We can use Ohm's Law to calculate the external resistance needed:
V = IR
where V is the voltage across the meter movement and external resistance, I is the current through the circuit, and R is the total resistance of the circuit.
At full-scale deflection, the current through the meter movement is 1 mA. Therefore, the voltage across the meter movement is:
V = IR = (1 mA)(100 ohms) = 0.1 V
To obtain a full-scale deflection with a current of 10 mA, the total current through the circuit must be 11 mA (10 mA for the external resistance and 1 mA for the meter movement). Therefore, the total resistance of the circuit must be:
R = V/I = 0.1 V / (11 mA) = 9.09 ohms
Since the external resistance is in series with the meter movement, the external resistance needed is:
Rext = R - Rm = 9.09 ohms - 100 ohms = -90.91 ohms
This result is negative, which means that it is not possible to obtain a full-scale deflection with a 1 mA meter movement and an external resistance in series. The external resistance cannot be negative. Therefore, a different meter movement or a current amplifier circuit would need to be used to measure a current of 10 mA with a full-scale deflection.
We can use Ohm's Law to calculate the external resistance needed:
V = IR
where V is the voltage across the meter movement and external resistance, I is the current through the circuit, and R is the total resistance of the circuit.
At full-scale deflection, the current through the meter movement is 1 mA. Therefore, the voltage across the meter movement is:
V = IR = (1 mA)(100 ohms) = 0.1 V
To obtain a full-scale deflection with a current of 10 mA, the total current through the circuit must be 11 mA (10 mA for the external resistance and 1 mA for the meter movement). Therefore, the total resistance of the circuit must be:
R = V/I = 0.1 V / (11 mA) = 9.09 ohms
Since the external resistance is in series with the meter movement, the external resistance needed is:
Rext = R - Rm = 9.09 ohms - 100 ohms = -90.91 ohms
This result is negative, which means that it is not possible to obtain a full-scale deflection with a 1 mA meter movement and an external resistance in series. The external resistance cannot be negative. Therefore, a different meter movement or a current amplifier circuit would need to be used to measure a current of 10 mA with a full-scale deflection.
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A 1 mA meter movement with an internal resistance of 100Ω is to be converted into (0 – 100) mA. To achieve this, value of shunt resistance Rsh is given bya)1 KΩb)200 KΩc)1.01 Ωd)1.01 ΩCorrect answer is option 'C'. Can you explain this answer?
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A 1 mA meter movement with an internal resistance of 100Ω is to be converted into (0 – 100) mA. To achieve this, value of shunt resistance Rsh is given bya)1 KΩb)200 KΩc)1.01 Ωd)1.01 ΩCorrect answer is option 'C'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A 1 mA meter movement with an internal resistance of 100Ω is to be converted into (0 – 100) mA. To achieve this, value of shunt resistance Rsh is given bya)1 KΩb)200 KΩc)1.01 Ωd)1.01 ΩCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 1 mA meter movement with an internal resistance of 100Ω is to be converted into (0 – 100) mA. To achieve this, value of shunt resistance Rsh is given bya)1 KΩb)200 KΩc)1.01 Ωd)1.01 ΩCorrect answer is option 'C'. Can you explain this answer?.
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