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Four channels are multiplexed using TDM. If each channel sends 100 bytes/second and we multiplex 1 byte per channel, then the bit rate for the link is ……………bps
  • a)
    400
  • b)
    800
  • c)
    1600
  • d)
    3200
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Four channels are multiplexed using TDM. If each channel sends 100 byt...
Firstly we understand the working of Multiplexer using TDM.
Each frame contain 1 byte from each channel; { 1 Byte = 8 Bit}
we have 4 channels
Then ,the size of each frame is
1x4= 4 bytes = =~ 32 bits.
Each channel is sending 100 bytes/second
A frame carries 1 byte from each channel,
The frame rate must be 100 frames per second. { its given}
Then the total rate is = 32×100 = 3200 bits/second
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Most Upvoted Answer
Four channels are multiplexed using TDM. If each channel sends 100 byt...
If each channel sends 100 bytes/second and we multiplex 1 byte per channel, then the total number of bytes transmitted per second is 4 bytes per second (1 byte per channel) multiplied by 100 bytes per channel, which equals 400 bytes per second.

Since 1 byte is equal to 8 bits, the total number of bits transmitted per second is 400 bytes per second multiplied by 8 bits per byte, which equals 3200 bits per second.

Therefore, the bit rate for the link is 3200 bits per second.
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Four channels are multiplexed using TDM. If each channel sends 100 bytes/second and we multiplex 1 byte per channel, then the bit rate for the link is ……………bpsa)400b)800c)1600d)3200Correct answer is option 'D'. Can you explain this answer?
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