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A block of mass 2kg rest on a plane inclined at an angle of 30∘ with the horizontal. The coefficient of friction between the block and the surface is 0.7. What will be the frictional force acting on the block?
- a)10.3 N
- b)23.8 N
- c)11.9 N
- d)6.3 N
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A block of mass 2kg rest on a plane inclined at an angle of 30 with th...
Here, frictional force, f = μR
= μmgcosθ = 0.7 × 2 × 9.8cos30∘
= 0.7 × 2 × 9.8 × 0.866 = 11.9 N
= μmgcosθ = 0.7 × 2 × 9.8cos30∘
= 0.7 × 2 × 9.8 × 0.866 = 11.9 N
Most Upvoted Answer
A block of mass 2kg rest on a plane inclined at an angle of 30 with th...
Frictional force is the force that opposes the motion or tendency of motion between two surfaces in contact. It can be calculated using the equation:
Frictional force (F) = coefficient of friction (μ) * normal force (N)
where,
μ = coefficient of friction
N = normal force
Given:
Mass of the block (m) = 2 kg
Angle of inclination (θ) = 30 degrees
Coefficient of friction (μ) = 0.7
To find the frictional force, we need to first calculate the normal force acting on the block.
Normal force (N) = weight of the block (mg) * cos(θ)
where,
g = acceleration due to gravity
Weight of the block (mg) = mass (m) * acceleration due to gravity (g)
Acceleration due to gravity (g) = 9.8 m/s^2
Calculating the weight of the block:
Weight of the block (mg) = 2 kg * 9.8 m/s^2 = 19.6 N
Calculating the normal force:
Normal force (N) = 19.6 N * cos(30 degrees) = 19.6 N * 0.866 = 16.96 N
Now, we can calculate the frictional force:
Frictional force (F) = 0.7 * 16.96 N = 11.872 N
Rounding off to the nearest tenth, the frictional force acting on the block is approximately 11.9 N.
Therefore, the correct answer is option C) 11.9 N.
Frictional force (F) = coefficient of friction (μ) * normal force (N)
where,
μ = coefficient of friction
N = normal force
Given:
Mass of the block (m) = 2 kg
Angle of inclination (θ) = 30 degrees
Coefficient of friction (μ) = 0.7
To find the frictional force, we need to first calculate the normal force acting on the block.
Normal force (N) = weight of the block (mg) * cos(θ)
where,
g = acceleration due to gravity
Weight of the block (mg) = mass (m) * acceleration due to gravity (g)
Acceleration due to gravity (g) = 9.8 m/s^2
Calculating the weight of the block:
Weight of the block (mg) = 2 kg * 9.8 m/s^2 = 19.6 N
Calculating the normal force:
Normal force (N) = 19.6 N * cos(30 degrees) = 19.6 N * 0.866 = 16.96 N
Now, we can calculate the frictional force:
Frictional force (F) = 0.7 * 16.96 N = 11.872 N
Rounding off to the nearest tenth, the frictional force acting on the block is approximately 11.9 N.
Therefore, the correct answer is option C) 11.9 N.
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A block of mass 2kg rest on a plane inclined at an angle of 30 with the horizontal. The coefficient of friction between the block and the surface is 0.7. What will be the frictional force acting on the block?a)10.3 Nb)23.8 Nc)11.9 Nd)6.3 NCorrect answer is option 'C'. Can you explain this answer?
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A block of mass 2kg rest on a plane inclined at an angle of 30 with the horizontal. The coefficient of friction between the block and the surface is 0.7. What will be the frictional force acting on the block?a)10.3 Nb)23.8 Nc)11.9 Nd)6.3 NCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A block of mass 2kg rest on a plane inclined at an angle of 30 with the horizontal. The coefficient of friction between the block and the surface is 0.7. What will be the frictional force acting on the block?a)10.3 Nb)23.8 Nc)11.9 Nd)6.3 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 2kg rest on a plane inclined at an angle of 30 with the horizontal. The coefficient of friction between the block and the surface is 0.7. What will be the frictional force acting on the block?a)10.3 Nb)23.8 Nc)11.9 Nd)6.3 NCorrect answer is option 'C'. Can you explain this answer?.
A block of mass 2kg rest on a plane inclined at an angle of 30 with the horizontal. The coefficient of friction between the block and the surface is 0.7. What will be the frictional force acting on the block?a)10.3 Nb)23.8 Nc)11.9 Nd)6.3 NCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A block of mass 2kg rest on a plane inclined at an angle of 30 with the horizontal. The coefficient of friction between the block and the surface is 0.7. What will be the frictional force acting on the block?a)10.3 Nb)23.8 Nc)11.9 Nd)6.3 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 2kg rest on a plane inclined at an angle of 30 with the horizontal. The coefficient of friction between the block and the surface is 0.7. What will be the frictional force acting on the block?a)10.3 Nb)23.8 Nc)11.9 Nd)6.3 NCorrect answer is option 'C'. Can you explain this answer?.
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