NEET Exam > NEET Questions > A ball A is dropped from a building of height...
Start Learning for Free
A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).
- a)0
- b)10 m s-1
- c)25 ms-1
- d)50 ms-1
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A ball A is dropped from a building of height 45 m. Simultaneously ano...
Here, uA = −0 , uB = +50ms−1
aA = −g , aB = −g
uBA = uB − uA = 50ms−1 − (0)ms−1 = 50ms−1
aBA = aB − aA = −g − (−g) = 0
∵ vBA = uBA + aBAt(As aBA = 0)
∴ vBA = uBA
As there is no acceleration of ball B w.r.t to ball A, therefore the relative speed of ball B w.r.t ball A at any instant of time remains constant (= 50ms−1).
Most Upvoted Answer
A ball A is dropped from a building of height 45 m. Simultaneously ano...
To solve this problem, we need to consider the motion of both balls A and B separately.
For ball A:
Since ball A is dropped, it only experiences free fall due to gravity. The height of the building is 45 m, so the initial velocity of ball A is 0 m/s (since it is dropped) and the final velocity is unknown. The acceleration due to gravity, g, is approximately 9.8 m/s^2. Using the equation of motion:
h = ut + (1/2)gt^2
where h is the height, u is the initial velocity, g is the acceleration due to gravity, and t is the time taken.
Substituting the given values, we have:
45 = 0 + (1/2)(9.8)t^2
Simplifying the equation:
45 = 4.9t^2
Dividing both sides by 4.9:
t^2 = 9.18
Taking the square root of both sides:
t ≈ 3.03 seconds
Therefore, ball A will take approximately 3.03 seconds to reach the ground.
For ball B:
Ball B is thrown up with a speed of 50 m/s. The initial velocity, u, is 50 m/s, and the acceleration due to gravity, g, is still approximately 9.8 m/s^2. Using the equation of motion:
v = u - gt
where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity, and t is the time taken.
Substituting the given values, we have:
0 = 50 - 9.8t
Simplifying the equation:
9.8t = 50
Dividing both sides by 9.8:
t ≈ 5.1 seconds
Therefore, ball B will take approximately 5.1 seconds to reach its maximum height.
In summary, ball A will take approximately 3.03 seconds to reach the ground, while ball B will take approximately 5.1 seconds to reach its maximum height.
For ball A:
Since ball A is dropped, it only experiences free fall due to gravity. The height of the building is 45 m, so the initial velocity of ball A is 0 m/s (since it is dropped) and the final velocity is unknown. The acceleration due to gravity, g, is approximately 9.8 m/s^2. Using the equation of motion:
h = ut + (1/2)gt^2
where h is the height, u is the initial velocity, g is the acceleration due to gravity, and t is the time taken.
Substituting the given values, we have:
45 = 0 + (1/2)(9.8)t^2
Simplifying the equation:
45 = 4.9t^2
Dividing both sides by 4.9:
t^2 = 9.18
Taking the square root of both sides:
t ≈ 3.03 seconds
Therefore, ball A will take approximately 3.03 seconds to reach the ground.
For ball B:
Ball B is thrown up with a speed of 50 m/s. The initial velocity, u, is 50 m/s, and the acceleration due to gravity, g, is still approximately 9.8 m/s^2. Using the equation of motion:
v = u - gt
where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity, and t is the time taken.
Substituting the given values, we have:
0 = 50 - 9.8t
Simplifying the equation:
9.8t = 50
Dividing both sides by 9.8:
t ≈ 5.1 seconds
Therefore, ball B will take approximately 5.1 seconds to reach its maximum height.
In summary, ball A will take approximately 3.03 seconds to reach the ground, while ball B will take approximately 5.1 seconds to reach its maximum height.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer?
Question Description
A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer?.
A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer?.
Solutions for A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer?, a detailed solution for A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A ball A is dropped from a building of height 45 m. Simultaneously another identical ball B is thrown up with a speed 50 m s−1. The relative speed of ball B w.r.t. ball A at any instant of time is (Take g = 10 m s−2).a)0b)10 m s-1c)25 ms-1d)50 ms-1Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup