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The load resistance and the input resistance of a CE amplifier are respectively 10 kΩ and 2 kΩ. If β of the transistor is 49, the voltage gain of the amplifier is
- a)125
- b)150
- c)175
- d)245
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The load resistance and the input resistance of a CE amplifier are re...
Output resistance, R0 = 10 kΩ
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Input resistance, Ri = 2 kΩ and β = 49
Voltage gain,
Most Upvoted Answer
The load resistance and the input resistance of a CE amplifier are re...
To find the voltage gain of a CE (Common Emitter) amplifier, we can use the formula:
Voltage Gain = β * (Load Resistance / Input Resistance)
Given:
Load Resistance (RL) = 10 kΩ
Input Resistance (Rin) = 2 kΩ
β (beta) = 49
Let's calculate the voltage gain using the given values:
Voltage Gain = β * (Load Resistance / Input Resistance)
= 49 * (10 kΩ / 2 kΩ)
= 49 * 5
= 245
Therefore, the voltage gain of the CE amplifier is 245.
Explanation:
- The CE amplifier is a common transistor amplifier configuration where the emitter terminal is common to both the input and output.
- The voltage gain of the CE amplifier is determined by the β (beta) value of the transistor, which is the current gain factor.
- The load resistance (RL) is the resistance connected to the output of the amplifier, and the input resistance (Rin) is the resistance connected to the input of the amplifier.
- The voltage gain formula for a CE amplifier is given by multiplying the β value with the ratio of the load resistance to the input resistance.
- In this case, the load resistance is 10 kΩ and the input resistance is 2 kΩ.
- The β value of the transistor is given as 49.
- Plugging these values into the voltage gain formula, we get a voltage gain of 245.
- Therefore, the correct answer is option 'D'.
Voltage Gain = β * (Load Resistance / Input Resistance)
Given:
Load Resistance (RL) = 10 kΩ
Input Resistance (Rin) = 2 kΩ
β (beta) = 49
Let's calculate the voltage gain using the given values:
Voltage Gain = β * (Load Resistance / Input Resistance)
= 49 * (10 kΩ / 2 kΩ)
= 49 * 5
= 245
Therefore, the voltage gain of the CE amplifier is 245.
Explanation:
- The CE amplifier is a common transistor amplifier configuration where the emitter terminal is common to both the input and output.
- The voltage gain of the CE amplifier is determined by the β (beta) value of the transistor, which is the current gain factor.
- The load resistance (RL) is the resistance connected to the output of the amplifier, and the input resistance (Rin) is the resistance connected to the input of the amplifier.
- The voltage gain formula for a CE amplifier is given by multiplying the β value with the ratio of the load resistance to the input resistance.
- In this case, the load resistance is 10 kΩ and the input resistance is 2 kΩ.
- The β value of the transistor is given as 49.
- Plugging these values into the voltage gain formula, we get a voltage gain of 245.
- Therefore, the correct answer is option 'D'.
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The load resistance and the input resistance of a CE amplifier are respectively 10 kΩ and 2 kΩ. If β of the transistor is 49, the voltage gain of the amplifier isa)125b)150c)175d)245Correct answer is option 'D'. Can you explain this answer?
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