How to identify hybridization ?

Question

Answer

U can find out no. of orbitals involved in hybridization by the formula 1/2*[V+X-C+A] where V is no of valence e-¹ in the valence shell of central atom,X is no. of monovalent atom surrounding the central atom, C is charge of cation nd A is charge on anion.Hence,u can find out the type of hybridization followed by the value of 'H'.

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See in your book

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According to the structure of the compound

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The number of sigma bond in the structure tell the hybridisation

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Sigma bonds + lone pairs(localised)

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Number of no bond formation electron it means lone pair and number of single bond

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According to sturcture of compounds and so many short tricks is there... you can find this in many books...

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Number of Sigma bonds + number of lone pairs gives the hybridization

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Simple way to find hybridisationConsider the compound IF7i) Count the valence shell electron in central metal (Here Iodine ).ii) Now count the number of atoms it is attached to (here 3 fluorine).Now formula is  Add those two numbers /2 = 7+3/2=5 iii ) We should use 5 orbital so hybridisation is sp3d.@spider

Answer

Hybridization: valency-no. Of halides/hydrogen -cation +anion charge

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