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A glass convex lens, [ug (myu g) = 1.5] has a focal length of 40 cm. when placed in air. what would be the focal length of the glass if it is placed in water [uw (myu w) = 1.33] (a)2 (b)4 (c)16 (d)32 how to solve ?
Most Upvoted Answer
A glass convex lens, [ug (myu g) = 1.5] has a focal length of 40 cm. w...
Solution:
Given that,
Focal length of glass convex lens in air, f = 40 cm
Refractive index of glass, ug = 1.5
Refractive index of water, uw = 1.33
To find: Focal length of the glass lens when placed in water.
Using the formula,
1/f = (ug - 1) * (1/R1 - 1/R2)
where R1 and R2 are the radii of curvature of the lens surfaces.
We know that, the lens is convex, so the radius of curvature of both the surfaces will be positive.
Also, when the lens is placed in air, R1 = R2 = R (say)
Substituting the given values in the above formula, we get,
1/40 = (1.5 - 1) * (1/R - 1/R)
=> R = 40 cm
Now, when the lens is placed in water, using the formula,
1/f' = (ug/uw) * (1/f - (ug - uw)/R)
Substituting the values, we get,
1/f' = (1.5/1.33) * (1/40 - (1.5 - 1.33)/(40))
=> f' = 32 cm
Therefore, the focal length of the glass lens when placed in water is 32 cm.
Answer: (d) 32
Given that,
Focal length of glass convex lens in air, f = 40 cm
Refractive index of glass, ug = 1.5
Refractive index of water, uw = 1.33
To find: Focal length of the glass lens when placed in water.
Using the formula,
1/f = (ug - 1) * (1/R1 - 1/R2)
where R1 and R2 are the radii of curvature of the lens surfaces.
We know that, the lens is convex, so the radius of curvature of both the surfaces will be positive.
Also, when the lens is placed in air, R1 = R2 = R (say)
Substituting the given values in the above formula, we get,
1/40 = (1.5 - 1) * (1/R - 1/R)
=> R = 40 cm
Now, when the lens is placed in water, using the formula,
1/f' = (ug/uw) * (1/f - (ug - uw)/R)
Substituting the values, we get,
1/f' = (1.5/1.33) * (1/40 - (1.5 - 1.33)/(40))
=> f' = 32 cm
Therefore, the focal length of the glass lens when placed in water is 32 cm.
Answer: (d) 32
Community Answer
A glass convex lens, [ug (myu g) = 1.5] has a focal length of 40 cm. w...
Use the len's maker formulae...f=(Mu-1)[1/r1-1/r2]
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A glass convex lens, [ug (myu g) = 1.5] has a focal length of 40 cm. when placed in air. what would be the focal length of the glass if it is placed in water [uw (myu w) = 1.33] (a)2 (b)4 (c)16 (d)32 how to solve ?
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A glass convex lens, [ug (myu g) = 1.5] has a focal length of 40 cm. when placed in air. what would be the focal length of the glass if it is placed in water [uw (myu w) = 1.33] (a)2 (b)4 (c)16 (d)32 how to solve ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A glass convex lens, [ug (myu g) = 1.5] has a focal length of 40 cm. when placed in air. what would be the focal length of the glass if it is placed in water [uw (myu w) = 1.33] (a)2 (b)4 (c)16 (d)32 how to solve ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A glass convex lens, [ug (myu g) = 1.5] has a focal length of 40 cm. when placed in air. what would be the focal length of the glass if it is placed in water [uw (myu w) = 1.33] (a)2 (b)4 (c)16 (d)32 how to solve ?.
A glass convex lens, [ug (myu g) = 1.5] has a focal length of 40 cm. when placed in air. what would be the focal length of the glass if it is placed in water [uw (myu w) = 1.33] (a)2 (b)4 (c)16 (d)32 how to solve ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A glass convex lens, [ug (myu g) = 1.5] has a focal length of 40 cm. when placed in air. what would be the focal length of the glass if it is placed in water [uw (myu w) = 1.33] (a)2 (b)4 (c)16 (d)32 how to solve ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A glass convex lens, [ug (myu g) = 1.5] has a focal length of 40 cm. when placed in air. what would be the focal length of the glass if it is placed in water [uw (myu w) = 1.33] (a)2 (b)4 (c)16 (d)32 how to solve ?.
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