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A ball is thrown vertically with a velocity U from balloon descending with a constant velocity v .the ball will pass by the balloon after time (a). (u v)/2g (b) (2u v)/g. (c)(2u 2v)/g. (d) (u v)/g?
Verified Answer
A ball is thrown vertically with a velocity U from balloon descending ...
Relative speed of ball with respect to the balloon = u + v.
Time taken by ball to reach the highest point is t.
0 = - (u + v) +gt
Therefore, t = (u + v)/g
Total time = 2t = (2u + 2v)/g
This question is part of UPSC exam. View all NEET courses
Most Upvoted Answer
A ball is thrown vertically with a velocity U from balloon descending ...
Explanation:
When a ball is thrown vertically with a velocity "U" from a balloon descending with a constant velocity "v", the ball will pass by the balloon after a certain time. Let's calculate this time.
Step 1: Analyzing the Vertical Motion of the Ball
Since the ball is thrown vertically, we only need to consider the vertical motion of the ball. The only force acting on the ball is gravity, which causes it to accelerate downwards with a constant acceleration of "g" (acceleration due to gravity).
Step 2: Finding the Time Taken by the Ball to Reach its Maximum Height
When a ball is thrown vertically upwards, it reaches its maximum height when its vertical velocity becomes zero. At this point, the ball starts to fall downwards. The time taken by the ball to reach its maximum height can be calculated using the equation:
Time taken = Vertical velocity / Acceleration due to gravity
= U / g
Step 3: Finding the Time Taken by the Ball to Pass the Balloon
Since the balloon is descending with a constant velocity "v", the ball needs to cover the distance between the balloon and its maximum height. The time taken by the ball to cover this distance can be calculated using the equation:
Time taken = Distance / Vertical velocity
= v / g
Step 4: Total Time Taken by the Ball to Pass the Balloon
The total time taken by the ball to pass the balloon is the sum of the time taken to reach its maximum height and the time taken to cover the distance between the balloon and its maximum height. Therefore, the total time taken is:
Total time taken = Time taken to reach maximum height + Time taken to cover distance to balloon
= U / g + v / g
= (U + v) / g
Final Answer:
Therefore, the correct option is (d) (U + v) / g.
When a ball is thrown vertically with a velocity "U" from a balloon descending with a constant velocity "v", the ball will pass by the balloon after a certain time. Let's calculate this time.
Step 1: Analyzing the Vertical Motion of the Ball
Since the ball is thrown vertically, we only need to consider the vertical motion of the ball. The only force acting on the ball is gravity, which causes it to accelerate downwards with a constant acceleration of "g" (acceleration due to gravity).
Step 2: Finding the Time Taken by the Ball to Reach its Maximum Height
When a ball is thrown vertically upwards, it reaches its maximum height when its vertical velocity becomes zero. At this point, the ball starts to fall downwards. The time taken by the ball to reach its maximum height can be calculated using the equation:
Time taken = Vertical velocity / Acceleration due to gravity
= U / g
Step 3: Finding the Time Taken by the Ball to Pass the Balloon
Since the balloon is descending with a constant velocity "v", the ball needs to cover the distance between the balloon and its maximum height. The time taken by the ball to cover this distance can be calculated using the equation:
Time taken = Distance / Vertical velocity
= v / g
Step 4: Total Time Taken by the Ball to Pass the Balloon
The total time taken by the ball to pass the balloon is the sum of the time taken to reach its maximum height and the time taken to cover the distance between the balloon and its maximum height. Therefore, the total time taken is:
Total time taken = Time taken to reach maximum height + Time taken to cover distance to balloon
= U / g + v / g
= (U + v) / g
Final Answer:
Therefore, the correct option is (d) (U + v) / g.
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A ball is thrown vertically with a velocity U from balloon descending with a constant velocity v .the ball will pass by the balloon after time (a). (u v)/2g (b) (2u v)/g. (c)(2u 2v)/g. (d) (u v)/g?
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A ball is thrown vertically with a velocity U from balloon descending with a constant velocity v .the ball will pass by the balloon after time (a). (u v)/2g (b) (2u v)/g. (c)(2u 2v)/g. (d) (u v)/g? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball is thrown vertically with a velocity U from balloon descending with a constant velocity v .the ball will pass by the balloon after time (a). (u v)/2g (b) (2u v)/g. (c)(2u 2v)/g. (d) (u v)/g? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is thrown vertically with a velocity U from balloon descending with a constant velocity v .the ball will pass by the balloon after time (a). (u v)/2g (b) (2u v)/g. (c)(2u 2v)/g. (d) (u v)/g?.
A ball is thrown vertically with a velocity U from balloon descending with a constant velocity v .the ball will pass by the balloon after time (a). (u v)/2g (b) (2u v)/g. (c)(2u 2v)/g. (d) (u v)/g? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball is thrown vertically with a velocity U from balloon descending with a constant velocity v .the ball will pass by the balloon after time (a). (u v)/2g (b) (2u v)/g. (c)(2u 2v)/g. (d) (u v)/g? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is thrown vertically with a velocity U from balloon descending with a constant velocity v .the ball will pass by the balloon after time (a). (u v)/2g (b) (2u v)/g. (c)(2u 2v)/g. (d) (u v)/g?.
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