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At a certain temperature and total pressure of 1 ATM, A2 vapours contain 20% by volume of A atoms (A2 = 2A) The kp of the reaction is
a) 5 x 10^-2
b) 2 x 10^-3
c) 5 x 10^-3
d) 4 x 10^-4?
a) 5 x 10^-2
b) 2 x 10^-3
c) 5 x 10^-3
d) 4 x 10^-4?
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At a certain temperature and total pressure of 1 ATM, A2 vapours conta...
Calculation of Kp
Step 1: Write the balanced chemical equation for the reaction.
A2 ⇌ 2A
Step 2: Write the expression for Kp.
Kp = (P^2_A)/P_A2
Step 3: Calculate the partial pressure of A2.
Since the total pressure is 1 ATM and A2 vapours contain 20% by volume of A atoms,
PA2 = 0.8 ATM
Step 4: Calculate the partial pressure of A.
Since A2 ⇌ 2A, the initial number of moles of A is half that of A2.
n_A = 0.5n_A2
The initial volume of A is 0.2 times the total volume of the mixture.
V_A = 0.2(V_A2 + V_A)
Using the ideal gas law, we can write:
PV = nRT
Step 4.1: Calculate the initial number of moles of A2.
n_A2 = (PV_A2)/(RT) = (0.8)(V_total)/(RT)
Step 4.2: Calculate the initial number of moles of A.
n_A = 0.5n_A2 = 0.5(0.8V_total)/(RT)
Step 4.3: Calculate the initial volume of A.
V_A = 0.2(V_A2 + V_A) = 0.2(V_total - V_A2)
Step 4.4: Calculate the initial pressure of A.
P_A = (n_ART)/(V_A) = (0.5(0.8V_total)/(RT))/(0.2(V_total - V_A2)) = 2(0.8)/(5 - 2V_A2/V_total)
Step 5: Calculate Kp.
Kp = (P^2_A)/(P_A2) = [2(0.8)/(5 - 2V_A2/V_total)]^2/(0.8) = 4(0.64)/(5 - 2V_A2/V_total)^2
Step 6: Substitute the given values.
Kp = 4(0.64)/(5 - 2(0.2))^2 = 5 x 10^-3
Therefore, the correct option is (c) 5 x 10^-3.
Step 1: Write the balanced chemical equation for the reaction.
A2 ⇌ 2A
Step 2: Write the expression for Kp.
Kp = (P^2_A)/P_A2
Step 3: Calculate the partial pressure of A2.
Since the total pressure is 1 ATM and A2 vapours contain 20% by volume of A atoms,
PA2 = 0.8 ATM
Step 4: Calculate the partial pressure of A.
Since A2 ⇌ 2A, the initial number of moles of A is half that of A2.
n_A = 0.5n_A2
The initial volume of A is 0.2 times the total volume of the mixture.
V_A = 0.2(V_A2 + V_A)
Using the ideal gas law, we can write:
PV = nRT
Step 4.1: Calculate the initial number of moles of A2.
n_A2 = (PV_A2)/(RT) = (0.8)(V_total)/(RT)
Step 4.2: Calculate the initial number of moles of A.
n_A = 0.5n_A2 = 0.5(0.8V_total)/(RT)
Step 4.3: Calculate the initial volume of A.
V_A = 0.2(V_A2 + V_A) = 0.2(V_total - V_A2)
Step 4.4: Calculate the initial pressure of A.
P_A = (n_ART)/(V_A) = (0.5(0.8V_total)/(RT))/(0.2(V_total - V_A2)) = 2(0.8)/(5 - 2V_A2/V_total)
Step 5: Calculate Kp.
Kp = (P^2_A)/(P_A2) = [2(0.8)/(5 - 2V_A2/V_total)]^2/(0.8) = 4(0.64)/(5 - 2V_A2/V_total)^2
Step 6: Substitute the given values.
Kp = 4(0.64)/(5 - 2(0.2))^2 = 5 x 10^-3
Therefore, the correct option is (c) 5 x 10^-3.
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At a certain temperature and total pressure of 1 ATM, A2 vapours contain 20% by volume of A atoms (A2 = 2A) The kp of the reaction isa) 5 x 10^-2 b) 2 x 10^-3 c) 5 x 10^-3d) 4 x 10^-4?
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At a certain temperature and total pressure of 1 ATM, A2 vapours contain 20% by volume of A atoms (A2 = 2A) The kp of the reaction isa) 5 x 10^-2 b) 2 x 10^-3 c) 5 x 10^-3d) 4 x 10^-4? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about At a certain temperature and total pressure of 1 ATM, A2 vapours contain 20% by volume of A atoms (A2 = 2A) The kp of the reaction isa) 5 x 10^-2 b) 2 x 10^-3 c) 5 x 10^-3d) 4 x 10^-4? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At a certain temperature and total pressure of 1 ATM, A2 vapours contain 20% by volume of A atoms (A2 = 2A) The kp of the reaction isa) 5 x 10^-2 b) 2 x 10^-3 c) 5 x 10^-3d) 4 x 10^-4?.
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